Taylor Polynomial - Calculus - Solved Quiz, Exercises of Calculus

This is solved class quiz. Its from Calculus class. Some key points are: Taylor Polynomial, Degree, Approximating, Three Taylor Polynomial, Taylor Series, Summation, Series

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MATH 106D - CALCULUS II
WINTER 2005
QUIZ 6*
NAME:
Show ALL your work CAREFULLY.
Consider the function
f(x)= 1
1+x.
(a) Find the degree four Taylor polynomial P4(x) for approximating f(x)
near x=0.
Write f(x)=(1+x)โˆ’1. Then, f๎˜(x)=โˆ’(1 + x)โˆ’2,f๎˜๎˜(x)=2(1+
x)โˆ’3,f๎˜๎˜๎˜(x)=โˆ’3!(1 + x)โˆ’4and f(4)(x)=4!(1+x)โˆ’5. Evaluating these
derivatives at x=0,weobtainf๎˜(0) = โˆ’1,f๎˜๎˜(0) = 2,f๎˜๎˜๎˜(0) = โˆ’3! and
f(4)(0) = 4!.Notethatf(0) = 1. It follows that
P4(x)=f(0) + f๎˜(0)x+f๎˜๎˜(0)
2x2+f๎˜๎˜๎˜(0)
3! x3+f(4)(0)
4! x4
=1โˆ’x+x2โˆ’x3+x4.
(b) Find the degree three Taylor polynomial P3(x; 1) for approximating
f(x)nearx=1.
Using the derivatives from (a), f๎˜(1) = โˆ’1
4,f๎˜๎˜(1) = 1
4,f๎˜๎˜๎˜(1) = โˆ’3!
16
and f(1) = 1
2. It follows that
P3(x;1) = f(1) + f๎˜(1)(xโˆ’1) + f๎˜๎˜(1)
2(xโˆ’1)2+f๎˜๎˜๎˜(1)
3! (xโˆ’1)3
=1
2
โˆ’
(xโˆ’1)
4+(xโˆ’1)2
8
โˆ’
(xโˆ’1)3
16 .
(c) Write down the Taylor series (using summation sign, i.e., you need to
find the general n-th term of the series) for f(x)nearx=0.
From part (a), we see that the general n-th term is given by
(โˆ’1)nxnso that the desired Taylor series is given by
โˆž
๎˜
n=0
(โˆ’1)nxn.
Date: March 7, 2005.
1

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MATH 106D - CALCULUS II

WINTER 2005

QUIZ 6*

NAME:

Show ALL your work CAREFULLY.

Consider the function f (x) =

1 + x

(a) Find the degree four Taylor polynomial P 4 (x) for approximating f (x) near x = 0. Write f (x) = (1 + x)โˆ’^1. Then, f โ€ฒ(x) = โˆ’(1 + x)โˆ’^2 , f โ€ฒโ€ฒ(x) = 2(1 + x)โˆ’^3 , f โ€ฒโ€ฒโ€ฒ(x) = โˆ’3!(1 + x)โˆ’^4 and f (4)(x) = 4!(1 + x)โˆ’^5. Evaluating these derivatives at x = 0, we obtain f โ€ฒ(0) = โˆ’ 1 , f โ€ฒโ€ฒ(0) = 2, f โ€ฒโ€ฒโ€ฒ(0) = โˆ’3! and f (4)(0) = 4!. Note that f (0) = 1. It follows that

P 4 (x) = f (0) + f โ€ฒ(0)x +

f โ€ฒโ€ฒ(0) 2

x^2 +

f โ€ฒโ€ฒโ€ฒ(0) 3!

x^3 +

f (4)(0) 4!

x^4

= 1 โˆ’ x + x^2 โˆ’ x^3 + x^4.

(b) Find the degree three Taylor polynomial P 3 (x; 1) for approximating f (x) near x = 1. Using the derivatives from (a), f โ€ฒ(1) = โˆ’ 14 , f โ€ฒโ€ฒ(1) = 14 , f โ€ฒโ€ฒโ€ฒ(1) = โˆ’ 16 3! and f (1) = 12. It follows that

P 3 (x; 1) = f (1) + f โ€ฒ(1)(x โˆ’ 1) +

f โ€ฒโ€ฒ(1) 2

(x โˆ’ 1)^2 +

f โ€ฒโ€ฒโ€ฒ(1) 3!

(x โˆ’ 1)^3

(x โˆ’ 1) 4

(x โˆ’ 1)^2 8

(x โˆ’ 1)^3 16

(c) Write down the Taylor series (using summation sign, i.e., you need to find the general n-th term of the series) for f (x) near x = 0. From part (a), we see that the general n-th term is given by (โˆ’1)nxn^ so that the desired Taylor series is given by

โˆ‘^ โˆž

n=

(โˆ’1)nxn.

Date: March 7, 2005. 1