tEST ABOUT STREAMER BREAK DOWN, Exercises of High Speed Electronics and Optoelectronics

esting and Measurement: High-voltage testing is essential to evaluate the performance and safety of electrical equipment. Instruments like high-voltage testers and megohmmeters are used to assess insulation resistance and identify potential faults. Scientific and Industrial Applications: High voltage is used in various scientific experiment

Typology: Exercises

2022/2023

Uploaded on 09/06/2023

phelokazi-mwetu
phelokazi-mwetu 🇿🇦

3 documents

1 / 3

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
HIGH VOLTAGE TEST 1
Mnqobi Nzama ( 219062895)
Question 1
Where:
Vin is the AC source
C1 and C2 are capacitors
D1 and D2 are the diodes
Rload is the load resistor.
2. A Voltage Doubler is a voltage multiplier circuit which has a voltage multiplication factor of
two. The circuit consists of only two diodes D1 and D2, two capacitors C1 and C2, and an
oscillating AC input voltage. This diode-capacitor pump circuit gives a DC output voltage equal to
the peak-to-peak value of the sinusoidal input.
When operating, during the negative half cycle of the sinusoidal input waveform, D1 is
forward biased and conducts charging up the pump capacitor, C1 to the peak value of the
input voltage, (Vp). Since there is no return path for C1 to discharge into, thus, it remains
fully charged and acts as a storage device in series with the voltage supply. At the same
time, D2 conducts via D1 and charging up C2.
During the positive half cycle, D1 is reverse biased blocking the discharging of C1 while
D2 is forward biased charging up C2. But since there is a voltage across C1 already equal
pf3

Partial preview of the text

Download tEST ABOUT STREAMER BREAK DOWN and more Exercises High Speed Electronics and Optoelectronics in PDF only on Docsity!

HIGH VOLTAGE TEST 1 Mnqobi Nzama ( 219062895) Question 1 Where:

  • Vin is the AC source
  • C1 and C2 are capacitors
  • D1 and D2 are the diodes
  • Rload is the load resistor. 2. A Voltage Doubler is a voltage multiplier circuit which has a voltage multiplication factor of two. The circuit consists of only two diodes D1 and D2, two capacitors C1 and C2, and an oscillating AC input voltage. This diode-capacitor pump circuit gives a DC output voltage equal to the peak-to-peak value of the sinusoidal input.
  • When operating, during the negative half cycle of the sinusoidal input waveform, D1 is forward biased and conducts charging up the pump capacitor, C1 to the peak value of the input voltage, (Vp). Since there is no return path for C1 to discharge into, thus, it remains fully charged and acts as a storage device in series with the voltage supply. At the same time, D2 conducts via D1 and charging up C2.
  • During the positive half cycle, D1 is reverse biased blocking the discharging of C1 while D2 is forward biased charging up C2. But since there is a voltage across C1 already equal

to the peak input voltage, C2 then charges to twice the peak voltage value of the input signal.

  • V (positive peak) + V (negative peak), so on the negative half-cycle, D1 charges C1 to Vp and on the positive half-cycle D2 adds the AC peak voltage to Vp on C1 and transfers it all to C2. The voltage across C2 discharges through the load ready for the next half cycle.
  • Then the voltage across C2 can be calculated as: Vout = 2Vp, minus the voltage drops across the diodes used, where Vp is the peak value of the input voltage. Note that this double output voltage is not instantaneous but increases slowly on each input cycle, eventually settling to 2Vp.
  • As C2 only charges up during one half cycle of the input waveform, the resulting output voltage discharged into the load has a ripple frequency equal to the supply frequency. The disadvantage of this is that it can be difficult to smooth out this large ripple frequency in much the same way as for a half wave rectifier circuit. Also, C2 must have a DC voltage rating at least twice the value of the peak input voltage.