The Monatomic Chain - Solid State Physics - Lecture Slides, Slides of Solid State Physics

This course deals with crystalline solids and is intended to provide students with basic physical concepts and mathematical tools used to describe solids. Key words in this lecture are: The Monatomic Chain, Hooke's Law, Equation of Motion, Amplitude, Nth Atom, Phonon Dispersion Relaion, Normal Mode Frequencies, First Brillouin Zone, Standing Wave, Group Velocity, Kittel,s Notaions, Acoustic Branch, Wavelenght

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2012/2013

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Normal Modes of Vibration
One dimensional model # 1: The Monatomic Chain
Consider a
Monatomic Chain of
Identical Atoms
with nearest-neighbor,
“Hooke’s Law”
type forces (F = - kx) between the atoms.
This is equivalent to a force-spring
model, with masses m & spring
constants K.
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Normal Modes of Vibration

One dimensional model # 1:

The Monatomic Chain

-^ Consider a

Monatomic Chain of

Identical Atoms

with nearest-neighbor,

“Hooke’s Law”

type forces

( F = - kx

)^ between the atoms.

-^ This is equivalent to a force-springmodel, with masses

m^

& spring

constants

K.

-^ To illustrate the procedure for treating the interatomic potential in theharmonic approximation, consider just two neighboring atoms.

Assume

that they interact with a known potential

V(r)

. Expand

V(r)

in a

Taylor’s series in displacements about the equilibrium separation,keeping only up through quadratic terms in the displacements:

This potential energy is the same asthat associated with a spring with

spring constant:

ar Vd dr K

  ^     

2 2

) (^

a rK

Force

 

r^

R

V(R)^0

a

Repulsive

Attractive

  • Consider the simple case ofa monatomic linear chainwith only nearest-neighborinteractions.• Expand the energy near theequilibrium point for the

th n

atom. Then, the^ Newton’s 2

nd^

Law

equation of motion becomes:

a^

a

U^ n-^

U^ n^

U^ n+

l

l ..

Equation of Motion for the n

th^ Atom

..

1

1

(^

2

)

n^

n

n^

n

mu

K u

u^

u

^

^

^

^

^

^

^

^

^

^

^

0

0

0

0

1

1

2

e^

e^

2

e^

e

n^

n^

n^

n

i kx

t^

i kx

t^

i kx

t^

i kx

t

m^

K^

A^

A^

A

A

^

^

^

^

^

^

^

kna^

(^

k^ n^

a

(^

k^ n^

a

kna

^

^

^

^

^

^

^

2

e^

e^

e^

2 e

e^

e

ika^

ika

i kna

t

i kna

t

i kna

t

i kna

t

m^

K^

A^

A^

A

A

^

^

^

^

^

^

^

Cancel Common Terms & Get:

^

2

e^

2

e ika^

ika

m^

K

^

^

^

^

^

^

^

^

^

^

^

^

2

e^

e^

2

e^

e

i kna

t^

i kna

ka^

t^

i kna

t^

i kna

ka^

t

m^

K^

A^

A^

A

A

^

^

^

^

^

^

^

^

^

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-^ Mathematical Manipulation

finally gives:

Solution to the NormalMode Eigenvalue Problem for the monatomic chain.

-^ The

physical significance

of these results is that, for the monatomic

chain, the only allowed vibrational frequencies

ω^

must be related to

the wavenumber

k = (

π/λ

)^ or the wavelength

λ^ in this way.

-^ This result is often called the

“Phonon Dispersion Relation

^ for

the chain, even though

these are

classical

lattice vibrations

&

there are

no

(quantum mechanical

)^ phonons

in the classical theory.

-^ After more manipulation,

this simplifies to

-^ The maximum allowed frequency is:

Some Physics Discussion

-^ We started from the Newton’s 2

nd^ Law equations of motion for

N^

coupled

harmonic oscillators

.^ If one atom starts vibrating, it does not continue with

constant amplitude, but transfers energy to the others in a complicated way.That is, the vibrations of individual atoms are not simple harmonic because ofthis

exchange of energy among them.

-^ On the other hand, our solutions represent the oscillations of

N^ UNCOUPLED simple harmonic
oscillators.

-^ As we already said, these are called the

Normal Modes

of the system. They

are a

collective property of the system

as a whole & not a property of any of

the individual atoms. Each mode represented by

ω(k)

oscillates independently

of the other modes.

Also, it can be shown that the

number of modes is the

same as the original number of equations N.

Proof of this follows.

Monatomic ChainDispersion Relation

4

sin

2 K^

ka m

p a Nk k Nap

p Na

 ^

2

2

     

To establish

which wavenumbers are possible

for the one-dimensional

chain, reason as follows: Not all values are allowed because of periodicity.In particular, the

th n atom is equivalent to the (N+n)

th^ atom

. This means

that the assumed solution for the displacements:must satisfy the periodic boundary condition:This, in turn requires that

there are an integer number of wavelengths

in

the chain. So, in the first BZ,

there are only N allowed values of k.

^

 0

exp n^

n

u^

A^

i kx

t 

^

^

 ^

 p

Na^

n N n^

u u^

 

Points

A and C

have the same

frequency

& the

same atomic displacements.

It can

be shown that the

group velocity

v^ = (dg^

ω/dk)

there is negative, so that a

wave at that

ω^ & that

k^ moves to the left.

The

green curve

(below) corresponds to

point B

in the

ω(k)

diagram. It has the

same frequency & displacement as points A and C

, but

v^ = (dg^

ω/dk)

there is

positive, so that a wave at that

ω^ & that

k

moves to the right.

Points

A & C

are symmetrically

equivalent; adding a multiple of

^2 π/a

to^ k

does not change either

ω^ or

v^ ,g^

so point

A^ contains no physical information that is different frompoint

B. T^ The points

k = ±

π/a

have special

significance

x

2

2 n n^

n^

n k^

a ^

^

^

^

Bragg reflection occurs at k= ± n

π/a

2

2 4 sin

ka 2

m^

K ^

u n

x

a u n

  • π/a^

k

K V

K m (^2)  /^  s k

C

A B 0 ω(k)

π (dispersion relation) /a 2

π/a 0

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k = (

/a) = (

/

);^ 

= 2a

k^ 

0;^

^ 

The Monatomic Chain 

Group Velocity, v

in the 1g

st^ BZ

At the 1

st^ BZ Edge, v^ = 0g^

-^ This means that a wavewith

λ^ corresponding to a zone edgewavenumber

k =

^

(π/a)

Will Not Propagate

-^ That is, it must be a^ Standing Wave!

st^1

BZ

Edge

v^ g^

^ (d

ω/dk)

= a(K/m)

½ cos(½ka)

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One Dimensional Model # 2:

The Diatomic Chain