Three Decimal Place - Calculus - Solved Exam, Exams of Calculus

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Math 105C Test 2 (75 points) Name: 5o| ufirn oe e Check that you have 9 questions on four pages. e Show all your work to receive full credit for a problem. ‘You may use any of the following facts: uy? vul— uv! N=u'v é -j= (uv) = u'v + uv (=) 2 1 by! = (In b)bF logy 2)’ = —— (oY = (ind) (oes = aye (sin x)! = cos x (cos)’ = —sing (tan.v)’ = sec? x sah erect 1__ =} yt (aresin x)! = = {arecos x)! = Vice (arctan x)’ = eat 1. [9 points) Use Newton’s Method to find a solution of the equation «° — 4a = 3 in the interval [2,3] to three-decimal-place accuracy. xe hy= 3 So xe hx-3=0 | Let fexv)exP-4x- 3 then Pode Bx & . We See thet there Wy & met dpre fe 25° (o lek xX, = 2.57 Then ey An > Lo fog) 27/453 x. x X,— LO) 0 £0) Ceagh a fen 2.5 2.322 2322 2.303 2.303 23028 So an abhmeate dt The soln. 2.32% 1.3028 z [2-302]