3-D Cartesian Coordinates: Finding Distances and Centers of Spheres, Study notes of Mathematics

Examples and equations for finding the distances between points and the centers and radii of spheres in three-dimensional cartesian coordinate systems. Students will learn how to calculate the distance between two points using the pythagorean theorem and find the equation of a sphere given its center and radius.

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Pre 2010

Uploaded on 03/28/2010

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Math 114 โ€“ Rimmer
13.1 3-D Cartesian Coord.
13.1 Three Dimensional Coordinate Systems (Cartesian)
Math 114 โ€“ Rimmer
13.1 3-D Cartesian Coord.
(
)
, ,
x y z
Points have coordinates:
( )
Example:
: 4,5, 6
A
(
)
: 3, 3, 1
B
โˆ’ โˆ’
(
)
Cโˆ’ โˆ’
A
B
C
pf2

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Math 114 โ€“ Rimmer 13.1 3-D Cartesian Coord. 13.1 Three Dimensional Coordinate Systems (Cartesian) Math 114 โ€“ Rimmer 13.1 3-D Cartesian Coord.

( x y z ,^ , )

Points have coordinates:

Example: A : 4,5, 6

B : 3, ( โˆ’3, โˆ’ 1 )

C : ( โˆ’2, โˆ’2,0)

A

B

C

Math 114 โ€“ Rimmer 13.1 3-D Cartesian Coord. d = PP 1 2

Distance between points: ( )

1 1 1 1 2 2 2 2 : , , : , , P x y z P x y z

2 2 2 = x 2 (^) โˆ’ x 1 (^) + y 2 (^) โˆ’ y 1 (^) + z 2 (^) โˆ’ z 1

AB = ( ) ( ( )) ( ( ))

2 2 2 4 โˆ’ 3 + 5 โˆ’ โˆ’ 3 + 6 โˆ’ โˆ’ 1 AB = 1 + 64 + 49 = 114 โ‰ˆ10.

AC = ( ( )) ( ( )) ( )

(^2 2 ) 4 โˆ’ โˆ’ 2 + 5 โˆ’ โˆ’ 2 + 6 โˆ’ 0 AC = 36 + 49 + (^36) = 121 = 11

A : 4,5,6 ( )

B : 3, ( โˆ’3,1)

C : ( โˆ’2, โˆ’2,0)

Find AB and AC. Which is larger? Math 114 โ€“ Rimmer 13.1 3-D Cartesian Coord.

(^2 2 2 ) x โˆ’ h + y โˆ’ k + z โˆ’ m = r Equation of a spheresphere :

Center: ( h k m , , ) Radius: r

Find the equation of the sphere with center at ( 0, โˆ’3, 6 )and radius 3.

2 2 2 x + y + 3 + z โˆ’ 6 = 3 2 2 2 Find the center and radius of the sphere that has the given equation: 4 x + 4 y + 4 z โˆ’ 4 x + 8 y โˆ’ 3 = 0

4 x^2 โˆ’ x + + 4 y^2^ + 2 y + + 4 z^2 = 3 + +

1 2 2 2 4 x โˆ’ 2 + 4 y + 1 + 4 z = 8 1 4 1 1 4

1 2 2 2

x โˆ’ 2 + y + 1 + z = 2 ( )

1 Center: 2 , โˆ’1,0 (^) Radius: 2