Two-Wattmeter Method: Unbalanced and Balanced Three-Phase Power Systems - Prof. Said Ahmed, Assignments of Electrical Circuit Analysis

Step-by-step solutions for calculating various quantities such as voltages, currents, and power factors using the two-wattmeter method in unbalanced and balanced three-phase power systems. Equations and diagrams to help visualize the concepts.

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Uploaded on 08/19/2009

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ECE225 TWO-WATTMETER METHOD UNBALANCED CASE SPRING 2008
a
b
c
A
B
C
b B
Cc
a A
I
CA
+
bn
10
j10
−j10
~
~
~
Z
~
o
V =127 0 V
o
V =127 120 V
~
IcC
bB
I
~
aA
I
~
an
AB
I
~
BC
I
~
CA
n N ca
o
V =127 −120 V
cn
ZBC
ZAB
+
+
+
V
Vbc
ab
V
+
+
(a) Find ˜
VAB,˜
VBC , and ˜
VCA geometrically.
˜
VAB =˜
Vab =
˜
VBC =˜
Vbc =
˜
VCA =˜
Vca =
(b) Find ¯
ZAB,¯
ZBC , and ¯
ZCA using the Y-to-∆ transformation:
¯
ZAB =¯
ZA¯
ZB+¯
ZB¯
ZC+¯
ZC¯
ZA
¯
ZC
=
¯
ZBC =¯
ZA¯
ZB+¯
ZB¯
ZC+¯
ZC¯
ZA
¯
ZA
=
¯
ZCA =¯
ZA¯
ZB+¯
ZB¯
ZC+¯
ZC¯
ZA
¯
ZB
=
(c) Find P3φ.
P3φ=
(d) Find Q3φ.
Q3φ=
1
pf3

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ECE225 TWO-WATTMETER METHOD – UNBALANCED CASE SPRING 2008

a

b

c

A

B

C

b B

c C

a A

I

CA

bn

10

j

Ω

Ω

−j10Ω

~

~

~

Z

~

o V =127 0 V

o V =127 120 V

~

I cC

bB

I

~

aA

I

~

an

AB

I

~

BC

I

~

CA

n N ca

o V =127 −120 V

cn

Z BC

Z AB

V

V

bc

ab

V

(a) Find

VAB ,

VBC , and

VCA geometrically.

VAB =

V

ab

V

BC

V

bc

V

CA

V

ca

(b) Find

Z

AB

Z

BC

, and

Z

CA

using the Y-to-∆ transformation:

ZAB =

Z

A

Z

B

Z

B

Z

C

Z

C

Z

A

Z

C

ZBC =

Z

A

Z

B

Z

B

Z

C

Z

C

Z

A

Z

A

Z

CA

Z

A

Z

B

Z

B

Z

C

Z

C

Z

A

Z

B

(c) Find P 3 φ.

P 3 φ =

(d) Find Q 3 φ.

Q 3 φ =

(e) Find

I

AB

I

BC

, and

I

CA

in polar and rectangular coordinates.

IAB =

V

AB

Z

AB

IBC =

V

BC

Z

BC

ICA =

V

CA

Z

CA

(f) Find

I

aA

I

bB

, and

I

cC

in rectangular and polar coordinates.

I

aA

I

AB

I

CA

I

bB

I

BC

I

AB

I

cC

I

CA

I

BC

(g) Find the value of a wattmeter W A

inserted between phases a and b (reference).

W

A

V

ab

I

aA

| cos(

6

V

ab

6

I

aA

(h) Find the value of a wattmeter WC inserted between phases c and b (reference).

W

C

V

cb

I

cC

| cos(^6

V

cb

I

cC

(i) Check that P 3 φ

= W

A

+ W

C

W

A

+ W

C

(j) Check whether Q 3 φ

3(W

C

− W

A

)? (Why or why not?)

3(WC − WA) =

(k) Finally, check that

S

3 φ

= P

3 φ

  • jQ 3 φ

V

an

I

aA

V

bn

I

bB

V

cn

I

cC