Unit 28: Second Hourly (Practice A), Summaries of Linear Algebra

LINEAR ALGEBRA AND VECTOR ANALYSIS. MATH 22B. Unit 28: Second Hourly (Practice A). • You only need this booklet and something to write.

Typology: Summaries

2022/2023

Uploaded on 05/11/2023

heathl
heathl 🇺🇸

4.5

(11)

235 documents

1 / 6

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
LINEAR ALGEBRA AND VECTOR ANALYSIS
MATH 22B
Unit 28: Second Hourly (Practice A)
You only need this booklet and something to write. Please stow away any other
material and electronic devices. Remember the honor code.
Please write neatly and give details. Except for problems 28.2 and 28.3, we
want to see details, even if the answer should be obvious to you.
Try to answer the question on the same page. There is also space on the back
of each page.
If you finish a problem somewhere else, please indicate on the problem page so
that we find it.
You have 75 minutes for this hourly.
Archimedes sends his good luck wishes. He unfortunately can not join us as he is “busy
proving a new theorem”. He just sent us his selfie. Oh well, these celebrities!
10
9
8
7
6
5
4
3
2
1
Name:
Total :
pf3
pf4
pf5

Partial preview of the text

Download Unit 28: Second Hourly (Practice A) and more Summaries Linear Algebra in PDF only on Docsity!

LINEAR ALGEBRA AND VECTOR ANALYSIS

MATH 22B

Unit 28: Second Hourly (Practice A)

  • You only need this booklet and something to write. Please stow away any other material and electronic devices. Remember the honor code.
  • Please write neatly and give details. Except for problems 28.2 and 28.3, we want to see details, even if the answer should be obvious to you.
  • Try to answer the question on the same page. There is also space on the back of each page.
  • If you finish a problem somewhere else, please indicate on the problem page so that we find it.
  • You have 75 minutes for this hourly. Archimedes sends his good luck wishes. He unfortunately can not join us as he is “busy proving a new theorem”. He just sent us his selfie. Oh well, these celebrities!

10

9

8

7

6

5

4

3

2

1

Name:

Total :

Linear Algebra and Vector Analysis

Problems

Problem 28A.1 (10 points):

a) (4 points) Prove that if x^3 is irrational, then x is irrational.

b) (3 points) Prove or disprove: the product of two odd integers is odd.

c) (3 points) Prove or disprove: the sum of two odd integers is odd.

Linear Algebra and Vector Analysis

Problem 28A.3 (10 points) Each question is two points:

We see the level curves of a Morse function f. The circle through ABC will sometimes serve as a constraint g(x, y) = x^2 + y^2 = 1. In all questions, we only pick points from A,B,C,D,E,F,G,H,I,J,K,L,M.

a) Which points are local minima of f under the constraint g(x, y) = 1.

b) Which points are local maxima of f under the constraint g(x, y) = 1.

c) At which points do we have fx(x, y) · fy(x, y) 6 = 0?

d) At which points are |∇f (x, y)| maximal?

e) At which points are |∇f (x, y)| minimal?

  • 8 - 8
    • 7
  • 6
    • 5
  • 4
  • 3
  • 2 -^1

0

2 1

3

(^4 )

6

7

8

9 9 9

10

10 10

11 11

(^1312 )

14 14

(^15 )

16 16

(^17 )

18 18

19 19

20 20

A

B

C

D

E

F

G

H

I J

K

L

M

x

y

Problem 28A.4 (10 points):

a) (5 points) Find the tangent plane to the surface

f (x, y, z) = x^2 y − x^3 + y^2 + z^4 xy = − 13

at the point (2, − 1 , 1).

b) (5 points) Estimate f (2. 001 , − 0. 99 , 1 .1) by linear approximation.

Problem 28A.5 (10 points):

a) (5 points) Find the quadratic approximation Q(x, y) of

f (x, y) = 5 + x + y + x^2 + 3y^2 + sin(xy) + ex

at (x, y) = (0, 0).

b) (5 points) Estimate the value of f (0. 001 , 0 .02) using quadratic approximation.

Problem 28A.6 (10 points):

a) (8 points) Classify the critical points of the function

f (x, y) = x^2 − y^3 + 2x + 3y

using the second derivative test.

b) (2 points) Does the function f (x, y) have a global minimum or global maximum?

Problem 28A.7 (10 points):

Using the Lagrange optimization method, find the parameters (x, y) for which the area of an arch f (x, y) = 2x^2 + 4xy + 3y^2

is minimal, while the perimeter

g(x, y) = 8x + 9y = 33

is fixed.