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lt is some problems' solutions for discrete math
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Discrete Mathematics 1.3. We know (1)a→b≡¬a∨b, (2)¬(a∧b)≡¬a∨¬b, (3)¬(a∨b)≡¬a∧¬b, (4)a∨(¬b∧¬a) ≡a∨¬b, (5)a∨¬a≡a, (6)a∨T≡T So (p∨q)∧(¬p∨r)→(q∨r) ≡¬((p∨q)∧(¬p∨r))∨(q∨r) (use(1)) ≡(¬(p∨q)∨¬(¬p∨r))∨(q∨r) (use(2)) ≡((¬p∧¬q)∨(p∧¬r))∨(q∨r) (use(3)) ≡(¬p∧¬q)∨(p∧¬r)∨q∨r ≡(q∨(¬p∧¬q))∨(r∨(p∧¬r)) ≡(q∨¬p)∨(r∨p) (use(4)) ≡q∨r∨(p∨¬p) 1.4. (c)(i)∃x¬S(x),S(x):x can swim (ii)∃x(C(x)∧¬S(x)),C(x):x is a person in your class (d)(i)∀xQ(x),Q(x):x can solve quadratic equations (ii)∀x(C(x)→Q(x)) (e)(i)∃x¬R(x),R(x):x wants to be rich (ii)∃x(C(x)∧¬R(x))