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A solution for determining the size of a rectangular garden that will maximize the contained space given a fixed length of 100 feet for the fence used to enclose three sides. The solution involves finding the length of the shorter sides and the longer side that will result in the maximum garden area.
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A backyard gardener wants to enclose a rectangular area for a new garden. He will use a portion of the backyard fence as the fourth side and has acquired 100 feet of wire fencing to enclose the other three sides. 1.If the sides of the fence perpendicular to the current fence have length L, provide a formula for the area enclosed by the fence. 2.What size should the garden be to make the most of the contained space? Solution: a) L + W + L, or simply 2L + W, equals 100 because we are aware that the fence available is only 100 feet long. As a result, we are able to express the width, W, in terms of L. W = 100 - 2L We now have to create an equation for the area that the fence encloses. The area of a rectangle is equal to its length multiplied by its width: A = L(W) A = L(100 - 2L) A(L) = 100L - 2L² The area of the fence is represented by this formula in terms of the length L. The function is to be written in general form in order to accurately solve for the other equations we may encounter: A(L) = -2L² + 100L b) -The leading coefficient of the quadratic equation is negative, which means the graph will open downward, with the vertex representing the area's maximum value. Because the equation is not represented in the standard polynomial form with decreasing powers, we must be careful when determining the vertex. For this reason, we modified the equation above in general form. -Determine the values for a, b, and c:
a = -2, b = 100, c = 0 -To find the vertex, solve for (h,k): h = -b/2a h = -100/2(-2) h = 25 L = 25 k = A(25) k = 100(25) - 2(25)² k = 1250 A = 1250 -When L = 25 feet, the function has its maximum value, which corresponds to an area of 1250 square feet. There are 50 feet of fencing remaining for the longer side when the shorter sides are 25 feet. -The farmer should enclose the garden so that the two shorter sides have a length of 25 feet and the longer side parallel to the current fence has a length of 50 feet in order to make the most of the space. This quadratic equation can also be solved by graphing: