Worksheet 1.5A, Function composition MATH 1410, Schemes and Mind Maps of Pre-Calculus

Given the functions f and g, below, find the composition function f ◦ g. ... (Please distinguish between your answer for f ◦ g and g ◦ f.).

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Worksheet 1.5A, Function composition
MATH 1410
(SOLUTIONS)
1. Given the functions fand g, below, find the composition function fg. (The function (fg)(x)
is the same as f(g(x)).
(a) f(x) = x2;g(x) = x.
(b) f(x) = x;g(x) = x2.
(c) f(x) = x21; g(x) = x+ 2.
(d) f(x) = x+ 2; g(x) = x21.
(e) f(x) = x+ 3 and g(x) = x210
(f) f(x) = ex;g(x) = x2.
(g) f(x) = x2;g(x) = ex.
Solution.
(a) f(x) = x2;g(x) = x.
(fg)(x) = x
(b) f(x) = x;g(x) = x2.
(fg)(x) = |x|
(c) f(x) = x21; g(x) = x+ 2.
(fg)(x) = (x+ 2)21 = x2+ 4x+ 3
(d) f(x) = x+ 2; g(x) = x21.
(fg)(x) = (x21) + 2 = x2+ 1
(e) f(x) = x+ 3 and g(x) = x210
(fg)(x) = (x210) + 3 = x27
(f) f(x) = ex;g(x) = x2.
(fg)(x) = ex2
(g) f(x) = x2;g(x) = ex.
(fg)(x) = (ex)2=e2x
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Worksheet 1.5A, Function composition MATH 1410 (SOLUTIONS)

  1. Given the functions f and g, below, find the composition function f ◦ g. (The function (f ◦ g)(x)

is the same as f (g(x)).

(a) f (x) = x^2 ; g(x) =

x.

(b) f (x) =

x; g(x) = x^2.

(c) f (x) = x^2 − 1; g(x) = x + 2.

(d) f (x) = x + 2; g(x) = x^2 − 1.

(e) f (x) = x + 3 and g(x) = x 2 − 10

(f) f (x) = e x ; g(x) = x 2 .

(g) f (x) = x 2 ; g(x) = e x .

Solution.

(a) f (x) = x 2 ; g(x) =

x.

(f ◦ g)(x) = x

(b) f (x) =

x; g(x) = x 2 .

(f ◦ g)(x) = |x|

(c) f (x) = x^2 − 1; g(x) = x + 2.

(f ◦ g)(x) = (x + 2)^2 − 1 = x^2 + 4x + 3

(d) f (x) = x + 2; g(x) = x^2 − 1.

(f ◦ g)(x) = (x^2 − 1) + 2 = x^2 + 1

(e) f (x) = x + 3 and g(x) = x 2 − 10

(f ◦ g)(x) = (x 2 − 10) + 3 = x 2 − 7

(f) f (x) = e x ; g(x) = x 2 .

(f ◦ g)(x) = e x^2

(g) f (x) = x 2 ; g(x) = e x .

(f ◦ g)(x) = (e x ) 2 = e 2 x

  1. Given the functions f and g, below, find the composition functions f ◦ g and g ◦ f. (The function

(f ◦ g)(x) is the same as f (g(x)); (g ◦ f )(x) is the same as g(f (x)).)

(Please distinguish between your answer for f ◦ g and g ◦ f .)

(a) f (x) = x 2

  • 1 and g(x) =

(b) f (x) = x 3

  • 2 and g(x) =

3

(c) f (x) = x^2 + 9 and g(x) =

x.

(d) f (x) = x^2 + 6x + 9 and g(x) =

x.

(e) f (x) = x^2 + 5 and g(x) =

x − 5.

Solution.

(a) f (x) = x 2

  • 1 and g(x) =

(f ◦ g)(x) = f (g(x)) = f (

2

  • 1 = 3 + 1 = 4.

(g ◦ f )(x) = g(f (x)). But g(anything) =

3, so the answer is

(f ◦ g)(x) = 4 and (g ◦ f )(x) =

(b) f (x) = x^3 + 2 and g(x) = 3

(f ◦ g)(x) = f (g(x)) = f ( 3

3

5)^3 + 2 = 5 + 2 = 7.

(g ◦ f )(x) = g(f (x). But g(anything) = 3

  1. So (g ◦ f )(x) = 3

(f ◦ g)(x) = 7 and (g ◦ f )(x) =

(c) f (x) = x 2

  • 9 and g(x) =

x.

(f ◦ g)(x) = (

x) 2

  • 9 = x + 9.

(g ◦ f )(x) =

x^2 + 9.

(f ◦ g)(x) = x + 9 and (g ◦ f )(x) =

x^2 + 9.

(d) f (x) = x 2

  • 6x + 9 and g(x) =

x.

(f ◦ g)(x) = (

x) 2

  • 6

x + 9 = x +

x + 9.

(g ◦ f )(x) =

x^2 + 6x + 9.

(f ◦ g)(x) = x + 6

x + 9 and (g ◦ f )(x) =

x^2 + 6x + 9.

(e) f (x) = x 2

  • 5 and g(x) =

x − 5.

(f ◦ g)(x) = (

x − 5) 2

(g ◦ f )(x) =

x^2 + 5 − 5 =

x^2 = |x|.

(f ◦ g)(x) = (

x − 5)^2 + 5 and (g ◦ f )(x) = |x|.