Zeta Potential - Novel Separation Processes - Lecture Notes, Study notes of Learning processes

some concept of Novel Separation Processes are Asymmetric Membrane, Centrifugal Separation Processes, Cloud Point Extraction, Colloidal Particles, Common Stationary Phase.Main points of this lecture are: Zeta Potential, Scaling Length, Surface Potential, Debye-Huckel Approximation, Permeate Flux, Electric Field, Debye Length, Stationary Outer, Solid Particles, Electrophoresis

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2012/2013

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Chapter 4
1. What is difference between electrophoresis and electroosmosis?
Ans: In electrophoresis, charged solid particles move under external electric field.
In electroosmosis, liquid with free charge move under external electric field
where charged solid is stationary.
2. What is Zeta potential?
Ans: The potential at the stationary outer surface of a charged surface is zeta potential.
3. What is the condition of Debye-Huckel approximation?
Ans: Surface potential is less than 25 mv.
4. What is the scaling length of electric double layer?
Ans: Debye length.
5. A protein solution in 0.05M NaCl is ultrafiltered with mass transfer cooefficient
8x10
-5
m/s. Filtration is gel layer controlled with gel concentration of 100 kg/m
3
and
feed concentration 1 kg/m
3
. Charge on protein is 5e and radius is 7 nm.
(a) What is permeate flux?
(b) If 500 V/m external electric field is applied, what is permeate flux?
Ans: K=8X10
-5
m/s; Cg=100 kg/m
3
; C0= 1 kg/m
3
(a) J=
ln
0
c
g
k
c
=
5
100
8.5 10 ln
1
×
= 3.7x10
-4
m/s
(b) κ
2
=(inverse of Debye length)
2
pf2

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Chapter 4

1. What is difference between electrophoresis and electroosmosis?

Ans: In electrophoresis, charged solid particles move under external electric field.

In electroosmosis, liquid with free charge move under external electric field

where charged solid is stationary.

2. What is Zeta potential?

Ans: The potential at the stationary outer surface of a charged surface is zeta potential.

3. What is the condition of Debye-Huckel approximation?

Ans: Surface potential is less than 25 mv.

4. What is the scaling length of electric double layer?

Ans: Debye length.

5. A protein solution in 0.05M NaCl is ultrafiltered with mass transfer cooefficient

8x

m/s. Filtration is gel layer controlled with gel concentration of 100 kg/m

3

and

feed concentration 1 kg/m

3

. Charge on protein is 5e and radius is 7 nm.

(a) What is permeate flux?

(b) If 500 V/m external electric field is applied, what is permeate flux?

Ans: K=8X

m/s; Cg=100 kg/m

3

; C0= 1 kg/m

3

(a) J= ln

cg

k (^) c

8.5 10 ln 1

× = 3.7x

m/s

(b) κ

2

=(inverse of Debye length)

2

2000 N (^) AMe

k T B

× × × × ×

× × × × ×

=1.38x

m

E

e

εξ ν = μ

Q

a a

ξ πε κ

× ×

− − ×

× × × × × × × +

×

×

×

=2.1 mv

e

× × × × ×

=7.43x10-7 m/s

J J 3.7 10 7.43 10

e e

ν

= + = × + ×

=3.7x

m

3

/m

2

.s