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Chemical reactions notes 1, Apuntes de Química

In this document you will find everything you need to understand chemical reactions. It also provides simple mathematical formulas to complement all the material.

Tipo: Apuntes

2022/2023

Subido el 30/05/2023

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Chemical reactions
In this exploration, we will discover the link between chemical reactions and probability to
compare the kinetics of fundamental reactions.
If we assume that the sugar molecules (N) are randomly distributed throughout the flask,
what is the probability that a sugar molecule is at "Site A"?
For a reaction they need to collide with sufficient energy and make contact in just the right
orientation.
Step 1:
To determine the probability that a molecule occupies a single position, we can divide the
number of available molecules by the number of available positions:
p = N/V
Using this connection, we can draw some important conclusions about changes in
concentration that affect how reactions work.
Step 2:
For example, adding more water to the flask increases the number of available positions for
the sugar molecules already in the flask. Chemists would say that this reduces the
concentration of sugar molecules in the flask.
Since the number of sugar molecules has not changed, there is now a much lower
probability that any molecule will be at Site A and, as we will see, this has real
consequences for chemical reactions.
Concentration:
This probability also has a more common name: concentration. The higher the concentration
of a molecule in a flask, the more molecules there are per unit volume. If we want a more
concentrated sugar solution, we simply add more sugar molecules to the solution without
changing the amount of water.
In general, both the number of molecules and the number of locations in a flask are such
large numbers that it is not useful to think about them directly; the ratio is much more
practical.
The concentration of a molecule (B).
"B" is represented by:
[B] = N*B/V
What is the probability that a molecule (C) and a molecule (D) are both at location A?
p = [B]×[C]
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Chemical reactions In this exploration, we will discover the link between chemical reactions and probability to compare the kinetics of fundamental reactions. If we assume that the sugar molecules (N) are randomly distributed throughout the flask, what is the probability that a sugar molecule is at "Site A"? For a reaction they need to collide with sufficient energy and make contact in just the right orientation. Step 1: To determine the probability that a molecule occupies a single position, we can divide the number of available molecules by the number of available positions: p = N/V Using this connection, we can draw some important conclusions about changes in concentration that affect how reactions work. Step 2: For example, adding more water to the flask increases the number of available positions for the sugar molecules already in the flask. Chemists would say that this reduces the concentration of sugar molecules in the flask. Since the number of sugar molecules has not changed, there is now a much lower probability that any molecule will be at Site A and, as we will see, this has real consequences for chemical reactions. Concentration: This probability also has a more common name: concentration. The higher the concentration of a molecule in a flask, the more molecules there are per unit volume. If we want a more concentrated sugar solution, we simply add more sugar molecules to the solution without changing the amount of water. In general, both the number of molecules and the number of locations in a flask are such large numbers that it is not useful to think about them directly; the ratio is much more practical. The concentration of a molecule (B). "B" is represented by: [B] = N*B/V What is the probability that a molecule (C) and a molecule (D) are both at location A? p = [B]×[C]

Suppose there are 500 molecules of B and 500 molecules of C randomly distributed among 1000 locations in the flask. How many collisions would you expect to occur at the first time point if the molecules are truly randomly distributed? 250 Types of reactions: Not all reactions are equal: if we set up two different reactions and put their reactant molecules at the same concentrations, it is possible that one proceeds very quickly while the other proceeds very slowly. This is because collision is only one part of the success of a reaction. The other part is making sure that the molecules collide with sufficient speed and in the correct orientation to cause the transformation. Although we can think of the number of collisions purely probabilistically, the details of the success of the reactions depend on the speed of the collision and quantum mechanics. However, we can capture this information in a single number called the rate constant "k", an indicator of the probability that a collision between two molecules will result in a reaction. The number of reactions that occur between molecules (B) and (C) per second is: Rs. = k×[B]×[C] (Reaction per second) Suppose a reaction requires three molecules of [A] to join to produce a trimer: How would the rate of the reaction "r", depend on "k" and [A]? r = k[A]^