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Ejercicio sobre binarioas a decimal
Tipo: Ejercicios
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101010 0 10001111100 1011100101011100 101100011101001 1011110100011010 00001010010110010 1001010101100111 1111010101000101 1101001101010011 001010010101010 1010101000110010 010101001011000 110101100011010 11010100001011 001010100110 1001010010
and Subnetting
Version 1. 11111110 10010101 00011011 11010011 10000110
Class A 1 – 127 (Network 127 is reserved for loopback and internal testing) Leading bit pattern 0 00000000.00000000.00000000.00000000 Network. Host. Host. Host Class B 128 – 191 Leading bit pattern 10 10000000.00000000.00000000.00000000 Network. Network. Host. Host Class C 192 – 223 Leading bit pattern (^110 1) Network 1000000.00000000.00000000.00000000. Network. Network. Host Class D 224 – 239 (Reserved for multicast) Class E 240 – 255 (Reserved for experimental, used for research)
Class A 10.0.0.0 to 10.255.255. Class B 172.16.0.0 to 172.31.255. Class C 192.168.0.0 to 192.168.255.
Class A 255.0.0. Class B 255.255.0. Class C 255.255.255.
Decimal To Binary Conversion Use all 8 bits for each problem
Circle the network portion of these Circle the host portion
Default Subnet Masks Write the correct default subnet mask for each of the following addresses:
ANDING With
When you take a single network such as 192.100.10. 0 and divide it into five smaller networks (192.100.10.16, 192.100.10.32, 192.100.10.48, 192.100.10.64, 192.100.10.80) the outside world still sees the network as 192.100.10.0, but the internal computers and routers see five smaller subnetworks. Each independent of the other. This can only be accomplished by using a custom subnet mask. A custom subnet mask borrows bits from the host portion of the address to create a subnetwork address between the network and host portions of an IP address. In this example each range has 14 usable addresses in it. The computer must still AND the IP address against the custom subnet mask to see what the network portion is and which subnetwork it belongs to. IP Address: 192. 100. 10. 0 Custom Subnet Mask: 255.255.255. Address Ranges: 192.10.10.0 to 192.100.10.15 (Invalid Range) 192.100.10.16 to 192.100.10.31 (1st Usable Range) 192.100.10.32 to 192.100.10.47 (Range in the sample below) 192.100.10.48 to 192.100.10. 192.100.10.64 to 192.100.10. 192.100.10.80 to 192.100.10. 192.100.10.96 to 192.100.10. 111 192.100.10. 112 to 192.100.10. 192.100.10.128 to 192.100.10. 192.100.10.144 to 192.100.10. 192.100.10.160 to 192.100.10. 192.100.10.176 to 192.100.10. 192.100.10.192 to 192.100.10. 192.100.10.208 to 192.100.10. 192.100.10.224 to 192.100.10. 192.100.10.240 to 192.100.10.255 (Invalid Range) Network Sub Network Host IP Address: (^1 1 0 0 0 0 0 0). 1 1 0 0 1 0 0. 0 0 0 0 1 0 1 0. 0 0 1 0 0 0 0 1 (192. 100. 10. 33) Custom Subnet Mask: (^1 1 1 1 1 1 1 1). 1 1 1 1 1 1 1. 1 1 1 1 1 1 1 1. 1 1 1 1 0 0 0 0 (255. 255. 255. 240) AND: (^1 1 0 0 0 0 0 0). 1 1 0 0 1 0 0. 0 0 0 0 1 0 1 0. 0 0 1 0 0 0 0 0 (192. 100. 10. 32) Four bits borrowed from the host portion of the address for the custom subnet mask. The ANDING process of the four borrowed bits shows which range of IP addresses this particular address will fall into. In the next set of problems you will determine the necessary information to determine the correct subnet mask for a variety of IP addres
