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Fixed income introduction course ITAM
Tipo: Monografías, Ensayos
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Required reading:
IntroNotes.pdf
Suggested readings: Veronesi book pp.
3-7, 9-21, 32-38; Tuckman pp. 4-6, 23-25,
53-59, chapter 15
Valuing bonds and fixed income
derivatives
Managing the risk of bonds and fixed
income portfolios
Determining the optimal exercise policy
for the options that are embedded in
many fixed income securities
One makes one interest payment of 12%
of principal after one year (e.g. Eurobond)
One makes two coupon payments of 6%
in 6 and 12 months (e.g. corporate bond)
One makes an interest payment of 1%
every month (e.g. mortgage loan)
m Compounding
periodicity
Annually comp.
equivalent (r)
1 annual 12%
2 semi-annual 12.36%
4 quarterly 12.55%
12 monthly 12.68%
52 weekly 12.73%
8760 hourly 12.7496%
∞ continuous 12.7497%
In the limit, as m→∞, lim where
e≈2.
So if we define the continuously compounded
rate, r(∞), such that 1+r = e
r(∞)
, or r(∞) = ln (1+r),
where r is the annually compounded rate, we
have equivalent ways to discount a cash-flow of
K occurring at t:
(same result for all m)
r
m
r e
m
r
1 exp
mt
m
r m
r t
t r t
K
Ke
e
K
r
K
( )
( )
( )
1
( 1 )
11
1
2
1
2
1
2
1/
r
1
(∞)+r
2
(∞)
Coupon rate c, maturity M, par F (makes
payment of $cF/2 twice a yr., plus $F at
maturity)
Quantity of bonds bought or sold measured
by total par value (not price paid or number
of bonds).
Price quoted for $100 par.
If c=7.25% and M=May 15, 2016, bond
called “seven and a quarter’s of May 15,
Trade date: parties agree. Settlement date:
next business day
What is the value of the following bond:
coupon=10%, yield=5%, Time to maturity=
years, payments semi-annual, notional amount
Answer: Bond price = 152.
T T
(1 y/ 2 )
(1 y/ 2 )
y/
c/
Bond Value 100 *
Price at t=today, where today is between
t=0 and t=1:
t=0 ( L ast) t=1 ( N ext)
c/
……………………………
t=today ( S ettlement)
nLN
nLS nSN
SN LN
LN
n LS
n
n n
t
t today t
y
P
P P y
/
1
0
( 1 / 2 )
/
Compute the price of the following bond:
Assume semiannual payment and par=
Inputs of the function are
◦ Coupon, Yield, T
,
n
SN,
n
LN
20
LS
LN
LS
n
n
a 100 c / 2
LN
SN
n
n
y
c
P
1 / 2
1 / 2
100