06 Task Performance Design an analog lowpass, Exercises of Mathematics

Design an analog lowpass filter that will satisfy the following specification

Typology: Exercises

2021/2022

Uploaded on 10/13/2023

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06 Task Performance
Determine the required order, N
N ≥
log
(
10
1
101
)
/
(
10
60
10 1
)
log (1000
10000 )
N ≥ -0.7066
N
-1
Determine the 3dB Stopband
Ωc
Ωc=ΩS
(10
RS
10 1)
1
2N
=
(
2π
)
(10000)
(10
60
101)
1
2(−1)
Ωc=62832rad /sec
Determine the -3dB Stopband
Ωc
=
(
2π
)
(1000)
(10
1
10 1)
1
2(−1)
Ωc=31972 rad /sec
Therefore,
31972 Ωc62832
pf2

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06 Task Performance Determine the required order, N

N ≥

log √( 10 1 (^10) − 1 )/( 10 60 (^10) − 1 ) log (

N ≥ -0.

N ≅^ -

Determine the 3dB Stopband Ωc Ωc =

ΩS

R (^) S (^10) − 1 ) 1 2 N

( 2 π ) ( 10000 ) ( 10 60 (^10) − 1 ) 1 2 (− 1 ) Ωc = 62832 rad / sec Determine the -3dB Stopband Ωc Ωc =

ΩS

R (^) S 10 − 1 ) 1 2 N

( 2 π ) ( 1000 ) ( 10 1 (^10) − 1 ) 1 2 (− 1 ) Ωc = 31972 rad / sec Therefore, 31972 ≤ Ωc ≤ 62832

F =

Rs 10 − 1 10 R (^) p (^10) − 1

55 (^10) − 1 10 2 (^10) − 1

F = 735.

Ωn =

Ωs Ωp

2 π ( 7000 ) 2 π ( 2500 )

Ωn = 2.8 or 3

N ≥

cosh − 1 ( F ) cosh−^1 ( Ωn ) ln ( F + (^) √ F 2 − 1 )

ln( Ωn +√ Ωn

2 − 1 ) ln ( F + (^) √ F 2 − 1 )

ln( Ωn +√ Ωn

2 − 1 ) ln (735.2940+√ 735. 2 − 1 ) ln( 3 +√( 3 ) 2 − 1 ) 4.

N ≅^^4

ε p =

√^10

R (^) p (^10) − 1

√^10

2 (^10) − 1

ε p = 0.

r =sinh(

N

sinh

ε (^) p

r = sinh(

sinh

r = 0.

ΩP = F p x 2 π

ΩP = 2500 x 2 π

ΩP = 5000 π rad/sec

ε = ( 10 0.1^ α^ p − 1 )

1 2

ε = ( 10 0.1^ (^3 )− 1 )

1 2

μ (^) = ε −^1 + (^) √ 1 + ε −^2

μ = ( 1 )−^1 + √ 1 +( 1 )−^2