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Aiyagari Models
Jes´us Fern´andez-Villaverde^1 April 12, 2022 (^1) University of Pennsylvania
A trio of models
- Different GE heterogenous household models with incomplete markets make different assumptions about how to interpret the assets in the household consumption-savings problem, and how they are supplied: 1. Huggett model: private IOUs in zero net supply (Huggett, 1993). 2. Bewley model: money or bonds in positive net supply (Imrohoro˘glu, 1989). 3. Aiyagari model: capital in positive net supply (Aiyagari, 1994).
- That is why the model is sometimes called the Bewley-Huggett-Aiyagari model.
- We will mainly focus on the (canonical) Aiyagari model.
- Later, we will say a few things about the other two models.
Building blocks
- Continuum of households (vs. models with finite number/types of agents).
- One firm renting aggregate capital.
- No aggregate uncertainty.
- Individuals are subject to idiosyncratic shocks to their labor income.
- Incomplete markets.
Households
- Continuum of measure 1 of households.
- Preferences for household i: E 0
X^ ∞
t=
βt^ u(ct )
- Budget constraint: ct + at+1 = wt yt + (1 + rt )at
- We could consider a hand-to-mouth (i.e., autarky) variation: ct = wt yt.
- Initial conditions y 0 , a 0 ≥ 0.
- Borrowing constraint at+1 ≥ 0.
Firm
- Perfectly competitive firm with neoclassical technology: Yt = F (Kt , Lt )
- Depreciation rate: 0 < δ < 1.
- Aggregate resource constraint: Ct + Kt+1 − (1 − δ)Kt = F (Kt , Lt )
- The only net asset in economy is physical capital.
- No state-contingent claims (i.e. incomplete markets).
- Remark: ownership of the firm.
Recursive formulation, I
- (a, y ): household state.
- Φ(a, y ): aggregate state variable.
- A = [0, ∞): set of possible asset holdings.
- B(A): Borel σ-algebra of A.
- Y : set of possible labor endowment realizations.
- P(Y ): power set of Y.
- Z = A × Y and B(Z ) = P(Y ) × B(A).
- M the set of all probability measures on the measurable space (Z , B(Z )).
Recursive competitive equilibrium
A RCE is value function v : Z × M → R, household policy functions a′, c : Z × M → R, firm policy functions K , L : M → R, pricing functions r , w : M → R and law of motion H : M → M s.t.
- v , a′, c are measurable with respect to B(Z ), v satisfies Bellman equation and a′, c are the policy functions, given r () and w ().
- K , L satisfy, given r () and w () r (Φ) = FK (K (Φ), L(Φ)) − δ w (Φ) = FL(K (Φ), L(Φ))
- For all Φ ∈ M, L(Φ) =
R
ydΦ and
K ′(Φ′) = K (H(Φ)) =
Z
a′(a, y ; Φ)dΦ Z c(a, y ; Φ)dΦ +
Z
a′(a, y ; Φ)dΦ = F (K (Φ), L(Φ)) + (1 − δ)K (Φ)
- Aggregate law of motion H is generated by π and a′. 8
Transition functions
- Define transition function QΦ : Z × B(Z ) → [0, 1] by
QΦ((a, y ), (A, Y)) =
X
y ′∈Y
π(y ′|y ) if a′(a, y ; Φ) ∈ A 0 else
for all (a, y ) ∈ Z and all (A, Y) ∈ B(Z ).
- QΦ((a, y ), (A, Y)) is the probability that an agent with current assets a and current income y ends up with assets a′^ in A tomorrow and income y ′^ in Y tomorrow.
- Hence
Φ′(A, Y) = (H(Φ)) (A, Y)
Z
QΦ((a, y ), (A, Y))Φ(da × dy )
Characterizing the stationary RCE
- Recall that L is exogenously given.
- Thus, from r = Fk (K , L) − δ w = FL(K , L) we can get w as a function of r (with w ′^ (r ) < 0).
- Example: Y = K αL^1 −α with: r = αK α−^1 L^1 −α^ − δ ⇒ K =
r + δ α
(^) α (^1) − 1 L and w = (1 − α) K αL^1 −α^ = (1 − α) α 1 −αα (r + δ) αα− 1 L
Existence and uniqueness
- By Walras’ law, we can forget about goods market and we only need to check input market clearing.
- Define asset market clearing condition: K = K (r ) =
Z
a′(a, y )dΦ ≡ Ea(r )
- Then: r = Fk (K (r ), L) − δ
- Existence and uniqueness of stationary RCE boils down to one equation in one unknown.
- From assumptions on production function, K (r ) is continuous, strictly decreasing function on r ∈ (−δ, ∞) with
r →−limδ K^ (r^ )^ =^ ∞ r lim→∞ K^ (r^ )^ =^0
A fixed point problem, I
- From now on assume ∃¯a s.t. a′(¯a, yN ) = ¯a and a′(a, y ) ≤ a¯ for all y ∈ Y and all a ∈ [0, a¯]. State space Z = [0, a¯] × Y and optimal policy a′ r (a, y ) defined on Z , indexed by r.
- Asset demand Ea(r ) =
Z
a′ r (a, y )dΦr
- Need Φr that satisfies Φr (A, Y) =
Z
Qr ((a, y ), (A, Y))dΦr
where Qr is the Markov transition function defined by ar as
Qr ((a, y ), (A, Y)) =
X
y ′∈Y
π(y ′|y ) if a′ r (a, y ) ∈ A 0 else
A fixed point problem, II
- Need to establish that operator T (^) r∗ : M → M defined by
(T (^) r∗ (Φ)) (A, Y) =
Z
Qr ((a, y ), (A, Y))dΦ
has a unique fixed point.
Existence of stationary distributions, I
- Assumption 1 requires that Qr is transition function, i.e., Qr (z, .) is probability measure on (Z , B(Z )) for all z ∈ Z and Qr (., Z ) is B(Z )-measurable ∀Z ∈ B(Z ). Use that a′(a, y ) is continuous.
- The assumption that Qr is increasing requires that for any nondecreasing function f : Z → R we have that (Tf ) (z) =
Z
f (z′)Qr (z, dz′)
is also nondecreasing. Note that a′(a, y ) is increasing in (a, y ).
- Monotone mixing condition 3. satisfied? Pick z∗^ = ( 12 (a′(0, yN ) + ¯a) , y 1 ). Start at d with a sequence of bad shocks y 1 and from c with a sequence of good shocks yN.
Existence of stationary distributions, II
- Conclusion of the theorem assures existence of a unique invariant measure Φr which can be found by iterating on the operator T ∗.
- Convergence is in the weak sense: for every continuous and bounded real-valued function f on Z , we have nlim→∞
Z
f (z)dΦn =
Z
f (z)dΦr