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Construction materials and testing
1
Properties of Soil
Situation 1.
The sample of soil weighing 30.6 kg had a volume of
0.0183m
3
. The sample is allowed to dry in an oven and the
weight was reduced to 27.2 kg. The specific gravity of the
solids was found to be 2.65. Determine the following:
1.
Moist unit weight of soil in kN/m
3
2.
Dry unit weight of soil in kN/m
3
3.
Moisture content
4.
Void ratio
5.
Porosity
6.
Degree of saturation
Situation 2.
The soil sample in natural state having a volume of 0.0012 m3
weighs 1.73 kg. The degree of saturation being 61.6%. After
drying in an oven the final weight of sample was 1.44 kg.
Determine the follo wing:
7.
Specific gravity of solid
8.
Void ratio
9.
Critical hydraulic gradient
Situation 3.
The moist soil having a volume of 0.0154 m3 has a unit weight
of 16.5 kN/m3 and a moisture content of 15%. If the specific
gravity of solid is 2.7. Determine the following:
10.
Degree of Saturation
11.
Volume of air in the original sample
12.
Weight of water to be added to reach full saturation
Compaction
Situation 4.
The moist unit weight of sample of soil is 17.43 kN/m3. It has
a specific gravity of solid of 2 .65 and water content of 16%.
The sample has a void ratio of 0 .88 in the loosest condition
and 0.36 in the densest condition.
13.
Compute the density index
14.
If the dry unit weight at optimum water content was
19.12 kN/m
3
, what is the minimum dry unit
Situation 5.
A proposed embankment fill requires 5000 m3 of compaction
soil. The void ratio of the compacted fill is specified as 0.70.
Three borrow pits are available as described in the following
table.
Borrow Pit
Void Ratio
Cost/m
3
A
0.85
P830
B
0.95
P760
C
1.10
P720
What is the total cost for acquiring soil from:
15.
Borrow Pit A?
16.
Borrow Pit B?
17.
Borrow Pit C?
Situation 6.
A sand cone test has been performed in a compacted fill of
soil. The test results were as follows:
Initial mass of sand cone apparatus w/ sand = 5.912 kg
Final mass of sand cone apparatus w/ sand = 2.378 kg
Mass of soil recovered from hole = 2.833 kg
Moisture content of soil from hole = 7%
Density of sand =1300 kg/m3
Volume of cone below valve =1.114 x 103 m3
Max. dry unit weight =19 kN/m3
Determine the following:
18.
Moist unit weight
19.
Dry Unit Weight
20.
Relative compaction
Situation 7.
A sample of dry coarse-grained material was taken through
a layer of sieves and the following results were obtained:
Openings
(mm)
Mass of soil retained
(grams)
4.76
46.0
2.0
165.6
0.84
92.0
0.42
55.2
0.25
23.0
0.149
36.8
0.074
23.0
18.4
Determine the following:
21.
Effective particle size
22.
Uniformity coefficient
23.
Coefficient of curvature
Problems for Practice
Situation 8.
A saturated soil has a unit weight of 18.85 kN/m
3
and water
content of 32%. Determine the following:
1.
Specific gravity of solid (2.725)
2.
Porosity (0.466)
3.
Submerged unit weight
(9.04)
Situation 9.
The relative compaction of sand in the field is 94%. The
maximum and minimum dry unit weights of the sand are
16.2 kN/m
3
and 14.9 kN/m
3
respectively. For the field
condition determine the following :
4.
Dry unit weight (15.23)
5.
Relative density of compaction (27%)
6.
Moist unit weight at moisture content of 8% (16.45)
Situation 10.
A proposed earth fill needs 30,000 m3 of soil and be compacted
to 95% of Standard Proctor dry density. Tests indicate that the
max dry density is 19.4 kN/m3 at an optimum water content of
16%. The borrow material in its natural condition has a unit
weight of 17.6 kN/m3 and water content of 12%. Determine the
following:
7.
Total volume of borrow required (35,194)
8.
Volume of void of borrow material if Gs = 2.671 (14,077)
9.
Quantity of water to be added to bring the soil to the
optimum moisture content. (2254)
pf3
pf4
pf5

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Properties of Soil Situation 1. The sample of soil weighing 30.6 kg had a volume of 0.0183m^3. The sample is allowed to dry in an oven and the weight was reduced to 27.2 kg. The specific gravity of the solids was found to be 2.65. Determine the following:

1. (^) Moist unit weight of soil in kN/m 3 2. (^) Dry unit weight of soil in kN/m 3 3. Moisture content 4. Void ratio 5. Porosity 6. Degree of saturation Situation 2. The soil sample in natural state having a volume of 0.0012 m^3 weighs 1.73 kg. The degree of saturation being 61.6%. After drying in an oven the final weight of sample was 1.44 kg. Determine the following: 7. Specific gravity of solid 8. Void ratio 9. Critical hydraulic gradient Situation 3. The moist soil having a volume of 0.0154 m^3 has a unit weight of 16.5 kN/m^3 and a moisture content of 15%. If the specific gravity of solid is 2.7. Determine the following: 10. Degree of Saturation 11. Volume of air in the original sample 12. Weight of water to be added to reach full saturation Compaction Situation 4. The moist unit weight of sample of soil is 17.43 kN/m^3. It has a specific gravity of solid of 2.65 and water content of 16%. The sample has a void ratio of 0.88 in the loosest condition and 0.36 in the densest condition. 13. Compute the density index 14. If the dry unit weight at optimum water content was 19.12 kN/m^3 , what is the minimum dry unit Situation 5. A proposed embankment fill requires 5000 m^3 of compaction soil. The void ratio of the compacted fill is specified as 0.70. Three borrow pits are available as described in the following table. Borrow Pit Void Ratio Cost/m^3 A 0.85 P B 0.95 P C 1.10 P What is the total cost for acquiring soil from: 15. Borrow Pit A? 16. Borrow Pit B? 17. Borrow Pit C? Situation 6. A sand cone test has been performed in a compacted fill of soil. The test results were as follows: Initial mass of sand cone apparatus w/ sand = 5.912 kg Final mass of sand cone apparatus w/ sand = 2.378 kg Mass of soil recovered from hole = 2.833 kg Moisture content of soil from hole = 7% Density of sand =1300 kg/m^3 Volume of cone below valve =1.114 x 10^3 m^3 Max. dry unit weight =19 kN/m^3 Determine the following: 18. Moist unit weight 19. Dry Unit Weight 20. Relative compaction Situation 7. A sample of dry coarse-grained material was taken through a layer of sieves and the following results were obtained: Sieve no. Openings (mm) Mass of soil retained (grams) 4 4.76 46. 10 2.0 165. 20 0.84 92. 40 0.42 55. 60 0.25 23. 100 0.149 36. 200 0.074 23. Pan 18. Determine the following: 21. Effective particle size 22. Uniformity coefficient 23. Coefficient of curvature Problems for Practice Situation 8. A saturated soil has a unit weight of 18.85 kN/m^3 and water content of 32%. Determine the following: 1. Specific gravity of solid (2.725) 2. Porosity (0.466) 3. Submerged unit weight (9.04) Situation 9. The relative compaction of sand in the field is 94%. The maximum and minimum dry unit weights of the sand are 16.2 kN/m^3 and 14.9 kN/m^3 respectively. For the field condition determine the following: 4. Dry unit weight (15.23) 5. Relative density of compaction (27%) 6. Moist unit weight at moisture content of 8% ( 16.45) Situation 10. A proposed earth fill needs 30,000 m^3 of soil and be compacted to 95% of Standard Proctor dry density. Tests indicate that the max dry density is 19.4 kN/m^3 at an optimum water content of 16%. The borrow material in its natural condition has a unit weight of 17.6 kN/m^3 and water content of 12%. Determine the following: 7. Total volume of borrow required (35,194) 8. Volume of void of borrow material if Gs = 2.671 (14,077) 9. Quantity of water to be added to bring the soil to the optimum moisture content. (2254)

Situation 11. The following observations were recorded when sand replacement test was conducted using sand-cone equipment in order to find the density of natural soil. Density of sand used in the test = 1.4 g/cm^3 Weight of soil excavated from the pit = 950 grams Weight of sand filling the pit = 700 grams Water content of natural soil = 15% Specific gravity of solid = 2.

10. Compute the dry density of soil in g/cm^3 (1.65) Situation 12. The following are the details for the backfill material in a vibroflotation project. D 10 = 0.36 mm D 20 = 0.52 mm D 25 = 0.60 mm D 50 = 1.42 mm D 75 = 1.65 mm Determine the following: 11. Suitability number (6.11) 12. Rating based on the value of suitability number (Excellent) 13. Sorting coefficient (1.66)

13. Critical Hydraulic Gradient (icr)

i =

Gs − 1

cr

w^1 +^ e

Weight – Volume Relationships:

a. ^ d

Gs

1 + e w

b. ^ m

c.  m

d. 

=  d (1 + )

Gs + Gs 

1 + e w

Gs + Se

e. 

m sat

1 + e w

Gs + e

1 + e w

f.  ' =

Gs − 1

1 + e w

Sn Rating 0 - 10 Excellent 10 - 20 Good 20 - 30 Fair 30 - 50 Poor