Allowable Axial Compression - Elements of Architectural Structures - Assignment, Exercises of Structural Design and Architecture

Its assignment for Elements of Architectural Structures. Some points of assignment are: Allowable Axial Compression, Axial Compression Load, Wood Column Analysis, Seven Day Construction Load, Actual Size, Use US Units, Wood Column Design, Wall Length, Combined Stresses, Wood Connection Analysis

Typology: Exercises

2011/2012

Uploaded on 12/22/2012

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Assignment #7
Problems: all but 7A from Ambrose & Tripeny, Chapter 8, pgs 242, 254, 263, 264.
Note: Problems marked with a * have been altered with respect to the problem stated in the text.
Problem 6.2.A. Using the ASD method, find the allowable axial compression load for the
following wood column. Use Douglas fir-larch, No. 2 grade. Note: This is dimensioned
lumber < 4 inches thick. (wood column analysis)
Nominal Size
(in.)
Unbraced
Length ( ft)
Unbraced
Length (m)
4 x 4
8
2.44
Partial answers to check with: Pallowed = 6.8 kip.
Problem 6.2.D.* Using the ASD method, find the allowable axial compression load from a
seven day construction load for the following glu-lam wood column of Douglas fir-larch, No. 2
Southern Pine grade. Fc = 1500 psi, E = 1,400,000 psi (Actual size of 10 x 10 is 9.25”x9.25”)
(wood column analysis)
Nominal Size
(in.)
Unbraced
Length ( ft)
Unbraced
Length (m)
10 x 10
14
4.27
Partial answers to check with: Fc’ = 1387.5 psi.
Problem 6.2.F. USE US UNITS. Select square column section of Douglas fir-larch, No. 1 grade
from Table 6.1, for the following data. (wood column design)
Required Axial
Load (kips)
Required Axial
Load (kN)
Unbraced
Length ( ft)
Unbraced
Length (m)
50
222
12
3.66
Partial answers to check with: Padequate = 79.0 k.
Problem 6.5.B.* Ten-feet-high 2 x 4 studs of Douglas fir-larch, No. 1 grade, are used in an
exterior wall. Wind load is 25 psf on the wall surface; studs are 16 in. on center; the gravity
load on the wall is 500 lb/ft of wall length. Investigate the studs for combined action of
compression plus bending using the ASD method. Determine the working compression stress
and bending stress that would be used to investigate the studs for combined stresses. (beam-
column analysis)
Partial answers to check with: fc = 127 psi, fb = 1632 psi (>Fb*CD!)
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Assignment

Problems: all but 7A from Ambrose & Tripeny, Chapter 8, pgs 242, 254, 263, 264. Note: Problems marked with a * have been altered with respect to the problem stated in the text.

Problem 6.2.A. Using the ASD method, find the allowable axial compression load for the following wood column. Use Douglas fir-larch, No. 2 grade. Note: This is dimensioned lumber < 4 inches thick. (wood column analysis)

Nominal Size (in.)

Unbraced Length ( ft)

Unbraced Length (m)

4 x 4 8 2. Partial answers to check with: Pallowed = 6.8 kip.

Problem 6.2.D .* Using the ASD method, find the allowable axial compression load from a seven day construction load for the following glu-lam wood column of Douglas fir-larch, No. 2 Southern Pine grade. Fc = 1500 psi, E = 1,400,000 psi (Actual size of 10 x 10 is 9.25 ”x9.25” ) (wood column analysis)

Nominal Size (in.)

Unbraced Length ( ft)

Unbraced Length (m)

10 x 1 0 14 4. Partial answers to check with: Fc ’ = 1387.5 psi.

Problem 6.2.F. USE US UNITS. Select square column section of Douglas fir-larch, No. 1 grade from Table 6.1, for the following data. (wood column design)

Required Axial Load (kips)

Required Axial Load (kN)

Unbraced Length ( ft)

Unbraced Length (m)

50 222 12 3. Partial answers to check with: Padequate = 79.0 k.

_Problem 6.5.B._* Ten-feet-high 2 x 4 studs of Douglas fir-larch, No. 1 grade, are used in an exterior wall. Wind load is 25 psf on the wall surface; studs are 16 in. on center; the gravity load on the wall is 500 lb/ft of wall length. Investigate the studs for combined action of compression plus bending using the ASD method. Determine the working compression stress and bending stress that would be used to investigate the studs for combined stresses. (beam- column analysis) Partial answers to check with: fc = 127 psi, fb = 1632 psi (>Fb*CD!)

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Problem 7.2.A. A joint similar to that in Figure 7.4 is formed with outer members of 1- inch nominal thickness (3/4-in. actual thickness) and 10d common wire nails. Find the compression force that can be transferred to the two side members having 5 nails each board side. (wood connection analysis)

Problem 7.3.A. A truss heel joint similar to that in Figure 7.5 is made with gusset plates of ½- in. plywood and 8d nails. Find the tension force limit for the bottom chord having 12 nails each plywood side. (wood connection analysis)

7A) A nominal 3 x 8 in redwood beam is to be supported by two 2 x 8 in. members acting as a spaced column. The minimum spacing and edge distances for the 5/8 inch bolts are shown. How many 5/8 in. bolts will be required to safely carry a load of 3200 lb? Use the chart provided. (wood connection design) Partial answer to check with: min n = 3.95.

3200 lb

3” x 8”

2” x 8”

Example 1.^ Partial Figure 7.

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