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It states that the buoyant upward force acting on an object entirely or partially submerged in a fluid is equal to the weight of the fluid displaced by the ...
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The famous legend tells us that Archimedes was the person who discovered that the volume of displaced water equals the volume of a submerged object. He came up with that idea as he was trying to measure the volume of a crown of unusual shape. Puzzled he had filled his bathtub flush with water and water overflowed when he got inside of the tub. The idea that the amount of water splashed out of the tub is exactly the volume of his own body struck him and he ran outside of his house crying “Eureka!” This means, “I have found it”. Archimedes’ Principle itself isn’t directly about volume, it’s about buoyancy. It states that the buoyant upward force acting on an object entirely or partially submerged in a fluid is equal to the weight of the fluid displaced by the object. For a given object, the weight can be directly calculated from the mass or from the density and volume: 𝐹𝑔 = 𝑚𝑔 = 𝜌𝑉𝑔 The buoyant force is found by applying the same idea to the fluid instead of the object: 𝐹𝐵 = 𝑚fluid𝑔 = 𝜌fluid𝑉displaced𝑔 (1) Here, 𝑚fluid is the mass of the displaced fluid, which is broken down as the density of the fluid 𝜌fluid multiplied by the submerged volume of the object 𝑉displaced.
For a prism-shaped object like a cylinder, the submerged volume is equal to the cross-sectional area, 𝐴, multiplied by the submerged depth, 𝑑. So, the buoyant force can be written as: 𝐹𝐵 = 𝜌fluid𝐴𝑑𝑔 (2) If the object is lowered into the fluid while the buoyant force is measured, the slope of the graph of 𝐹𝐵 versus 𝑑 is proportional to the density of the fluid.
The purpose of this experiment is to verify Archimedes’ “finding” that the volume of the displaced liquid is the same as the volume of the object immersed. A metal ball will be used as the solid object.
The purpose of this experiment is to apply Archimedes’ principle to determine the density of a given liquid. For objects with constant cross-sectional areas (𝐴) such as cylinders or cubes one can use Equation 2 above. From this equation, you can see that the magnitude of the buoyant force is directly proportional to the portion of the object submerged in the liquid 𝑑. The graph 𝐹𝐵 vs. 𝑑 is a linear function with slope equal to 𝜌water𝐴𝑔. Figure 2. Taking data for Part 3. The object is lowered into a cup of water until it reached the desired line. The force recorded by the sensor is less than the weight of the block in the air because the buoyancy force supports the object.