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Solutions to two physics problems related to buoyancy and archimedes principle. The first problem calculates the size of a hot air balloon needed to lift a gondola and its passengers. The second problem determines how deep a glass will sink in water and how much water is required to drown it.
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1 One cubicmeter of air weighs 1.39 kg. If you heat it by 170 C the density reduces to. kg/m^3 (remember air expands when you heat it). How big do you have to make a hot air balloon to carry a gondola of 50 kg, attached to the skin of 880 lb and you with 3 friends, (pick your own weights ) Answer: One cubic meter hot air has a buoyancy of 1.39 ‐ .91 = .48 kg. To carry (50 + 880 ∙ 2 ∙ .44 + 60 + 80 + 75) kg, you need 1004 ∙ .48 = 500 m 3
. That corresponds to a circular balloon of 10 m diameter 2 A tall glass (20cm) is swimming in your bathtub. It weighs 60 grams and a bottom area of 10 cm2. How deep will it sink into the water, while it is still empty and how much water can you add to drown it? Answer : The glass will sink so far until the displaced water is 60gr. This correspond to 6 cm since 10cm2 ∙ 6 cm = 60cm3 = 60gr of water. Now 14 cm of glass floats above the surface of the water. Again 14 cm2 ∙ 10 cm = 140 cm3 suffice to sink the glass. This means you can add only 140 ml of water.