Physics Homework: Buoyancy and Archimedes Principle, Assignments of Physics

Solutions to two physics problems related to buoyancy and archimedes principle. The first problem calculates the size of a hot air balloon needed to lift a gondola and its passengers. The second problem determines how deep a glass will sink in water and how much water is required to drown it.

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Pre 2010

Uploaded on 08/26/2009

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Homework(12((((309K((Phys!
Due!April!27!in!Class!
!
1!!!!!!!One!cubicmeter!of!air!weighs!1.39!kg.!If!you!heat!it!by!170!C!the!density!reduces!to!.91!
kg/m3!(remember!air!expands!when!you!heat!it).!How!big!do!you!have!to!make!a!hot!air!balloon!
to!carry!a!gondola!of!50!kg,!attached!to!the!skin!of!880!lb!and!you!with!3!friends,!(pick!your!own!
weights!)!
Answer:(!One!cubic!meter!hot!air!has!a!buoyancy!of!1.39!‐!.91!=!.48!kg.!To!carry!(50!+!880!∙!2!∙!
.44!+!60!+!80!+!75)!kg,!you!need!1004!∙!.48!=!500!m3.!That!corresponds!to!a!circular!balloon!of!
10!m!diameter!!
2!!!!!!!!!A!tall!glass!(20cm)!is!swimming!in!your!bathtub.!It!weighs!60!grams!and!a!bottom!area!of!
10!cm2.!How!deep!will!it!sink!into!the!water,!while!it!is!still!empty!and!how!much!water!can!you!
add!to!drown!it?!
Answer:! ! The! glass! will! sink! so! far! until! the! displaced! water! is! 60gr.! This! correspond! to! 6! cm!
since!! !10cm2!∙! 6!cm!=! 60cm3! =!60gr!of! water.!Now!14! cm!of!glass! floats! above!the!surface! of!
the!water.! !Again! 14! cm2!∙!10!cm! =! 140! cm3!suffice!to!sink! the! glass.! This! means!you!can!add!
only!140!ml!of!water.!
!
((

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Homework 12 309 K Phys

Due April 27 in Class

1 One cubicmeter of air weighs 1.39 kg. If you heat it by 170 C the density reduces to. kg/m^3 (remember air expands when you heat it). How big do you have to make a hot air balloon to carry a gondola of 50 kg, attached to the skin of 880 lb and you with 3 friends, (pick your own weights ) Answer: One cubic meter hot air has a buoyancy of 1.39 ‐ .91 = .48 kg. To carry (50 + 880 ∙ 2 ∙ .44 + 60 + 80 + 75) kg, you need 1004 ∙ .48 = 500 m 3

. That corresponds to a circular balloon of 10 m diameter 2 A tall glass (20cm) is swimming in your bathtub. It weighs 60 grams and a bottom area of 10 cm2. How deep will it sink into the water, while it is still empty and how much water can you add to drown it? Answer : The glass will sink so far until the displaced water is 60gr. This correspond to 6 cm since 10cm2 ∙ 6 cm = 60cm3 = 60gr of water. Now 14 cm of glass floats above the surface of the water. Again 14 cm2 ∙ 10 cm = 140 cm3 suffice to sink the glass. This means you can add only 140 ml of water.