Archimedes Principle: Buoyancy and Density in Physics 103, Study notes of Physics

The archimedes principle in physics 103, explaining how an object's density determines the buoyancy force on it when submerged in a fluid. If the object is less dense than the fluid, it will rise and float. Main points from the lecture and example problems.

Typology: Study notes

Pre 2010

Uploaded on 02/10/2009

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PHYSICS 103: Lecture 18
Archimedes Principle
Example Problems
Agenda for Today:
Archimedes Principle
An object imersed in a fluid experiences an upward
buyont force equal to the weight of fluid it displaces
Fg=mg
Fb=mfg
The density of anything is:
V
m
ρ=
This means that the mass can be written
as:
ρVm =
Since an object displaces the same volume of fluid, this means that if
an object is less dense than the fluid it is submerged in, the
buoyonacy force is greater than its weight
An Object in a Fluid:
The object will rise until it floats
pf2

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PHYSICS 103: Lecture 18

  • Archimedes Principle
  • Example Problems

Agenda for Today:

Archimedes Principle

An object imersed in a fluid experiences an upward

buyont force equal to the weight of fluid it displaces

F (^) g=mg

F (^) b =mfg

The density of anything is:

V

m ρ =

This means that the mass can be written as:

m = ρV

Since an object displaces the same volume of fluid, this means that if an object is less dense than the fluid it is submerged in, the buoyonacy force is greater than its weight

An Object in a Fluid:

The object will rise until it floats

Example Problems

Main Points from Today’s Lecture

  • Archimedes Principle You should understand that the density of an object determines the buoyancy force on it if it is submerged in a fluid. If it is less dense than the fluid, it will rise and float to a height where the water displaced is equal to the weight of the object.

You should understand the example problems we reviewed.