IP Address Assignment for Departments using Class B Addressing, Exercises of Computer Network Management and Protocols

computer - computer

Typology: Exercises

2014/2015

Uploaded on 10/09/2015

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Assignment 4…. BY 069/BEX/307
Bigyan Guragain
Assign IP using class B address to 5 departments of IOE, TC with 50, 100, 200, 100 and 500
computers each. Start anywhere you like.
F 0
E 8
F 0
2 0
There are 5 departments, so masking should be done with 3 bits such that it can accommodate 23
= 8 departments in total.
Department Computer no. Subnet mask
1 500 001
2 100 010
3 200 011
4 100 100
5 50 101
Let us assume the departments are labelled A, B, C, D and E with the number of computers and
subnet mask as below:
Let the starting IP address for class B be 128.10.0.0
For Department 1:
Starting IP: 128.10.0010 0000.0000 0000 = 128.10.32.0
+0000 0001.1111 0100
Ending IP: 128.10.0010 0001.1111 0100 = 128.10.33.244
For Department 2:
Starting IP: 128.10.0100 0000.0000 0000 = 128.10.64.0
+0000 0000.1100 1000
Ending IP: 128.10.0100 0000.1100 1000 = 128.10.64.200
For Department 3:
Starting IP: 128.10.0110 0000.0000 0000 = 128.10.96.0
+0000 0000.0110 0100
Ending IP: 128.10.0110 0000.0110 0100 = 128.10.96.100
For Department 4:
Starting IP: 128.10.1000 0000.0000 0000 = 128.10.128.0
+0000 0000.0110 0100
Ending IP: 128.10.0110 0000.0110 0100 = 128.10.128.100
For Department 5:
Starting IP: 128.10.1010 0000.0000 0000 = 128.10.160.0
+0000 0000. 0011 0010
Ending IP: 128.10.1010 0000.0011 0010 = 128.10.160.50
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Assignment 4…. BY 069/BEX/

Bigyan Guragain

Assign IP using class B address to 5 departments of IOE, TC with 50, 100, 200, 100 and 500 computers each. Start anywhere you like. F 0 E 8

F 0 2 0There are 5 departments, so masking should be done with 3 bits such that it can accommodate 2^3 = 8 departments in total.

Department Computer no. Subnet mask 1 500 001 2 100 010 3 200 011 4 100 100 5 50 101 Let us assume the departments are labelled A, B, C, D and E with the number of computers and subnet mask as below:

Let the starting IP address for class B be 128.10.0. For Department 1: Starting IP : 128.10.0010 0000.0000 0000 = 128.10.32. +0000 0001.1111 0100 Ending IP : 128.10.0010 0001.1111 0100 = 128.10.33. For Department 2: Starting IP : 128.10.0100 0000.0000 0000 = 128.10.64. +0000 0000.1100 1000 Ending IP : 128.10.0100 0000.1100 1000 = 128.10.64. For Department 3: Starting IP : 128.10.0110 0000.0000 0000 = 128.10.96. +0000 0000.0110 0100 Ending IP : 128.10.0110 0000.0110 0100 = 128.10.96. For Department 4: Starting IP : 128.10.1000 0000.0000 0000 = 128.10.128. +0000 0000.0110 0100 Ending IP : 128.10.0110 0000.0110 0100 = 128.10.128. For Department 5: Starting IP : 128.10.1010 0000.0000 0000 = 128.10.160. +0000 0000. 0011 0010 Ending IP : 128.10.1010 0000.0011 0010 = 128.10.160.