59. Combining Eq. 32-7 with Eq. 32-2 and Eq. Eq. 32-3, we obtain
∆U=2µBB
where µBis the Bohr magneton (evaluated in Eq. 32-5). Thus, with ∆U=6.0×10−25 J, we find
B=|
B|=0.032 T.
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Bohr Magneton-Electricity Solved Problem, Exercises of Electrical Engineering
This is solution to problems related Electrical Engineering course. It was suggested by Prof. Bhooshan Sawhney at Shree Ram Swarup College of Engineering and Management. It includes: Combining, Bohr, Magneton, Magnet, Vicinity, Loop, Direction, Moment, Material, Regions
Typology: Exercises
2011/2012
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- Combining Eq. 32-7 with Eq. 32-2 and Eq. Eq. 32-3, we obtain
∆U = 2 μB B
where μB is the Bohr magneton (evaluated in Eq. 32-5). Thus, with ∆U = 6. 0 × 10
− 25 J, we find