Catenary Length - Computational Methods - Lecture Slides, Slides of Calculus for Engineers

These are the Lecture Slides of Computational Methods which includes Thévenin’s Equivalent Circuit, Circuit Simplification, Analysis of Power Transfer, Voltage Division, Analytical Game Plan, Array Operation, Element Operations, Number of Allowable Values etc.Key important points are: Catenary Length, Curve-Length of Cable, Differential Analysis, Matlab Solution Plan, Numerical Value, Double Command, Matlab Code, Ummy Variables of Integration, Design of Program

Typology: Slides

2012/2013

Uploaded on 03/26/2013

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Catenary Length
Consider a cable
uniformly loaded by the
cable itself, e.g., a
cable hanging under its
own weight.
We would like to find the
Curve-Length of the cable,
s, as function of x alone
Use Differential Analysis
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Catenary Length

 Consider a cable

uniformly loaded by the

cable itself, e.g., a

cable hanging under its

own weight.

 We would like to find the

Curve-Length of the cable,

s, as function of x alone

  • Use Differential Analysis

 Next, relate

horizontal distance,

x, to cable-length s

dxds cos

 Then

 Recall Trig ID:

ds dxdx

sec

cos

 

1

 

sec  1  tan

• Now Eliminate θ

 From Differential

Diagram note:

dx

dy

tan  

 Sub Out tan θ in the definite Integral for L :

dx

dx

dy

L dx

x b
x a
x b

 x a 

1 tan  1

• Finally

yO

 Now in the Case of

Prob10-

for 0 50

x

x

y cosh

dx

dx

dy

L

x b

 x a

z z

dz

d

cosh  sinh

 An Analytical Soln

for L is possible as

 But it’s a bit Tedious

so Let’s have

MATLAB do it

MATLAB Code

% Bruce Mayer, PE % ENGR25 * 03Jan % file = Prob10_25_Symbolic_Soln_0801.m % % Solve P10. % % Declare x, a, b as symbolic syms x a b % % Define Catenary y(x) y = 10*cosh((x-20)/10) % % Take dy/dx symbolically dydx = diff(y) % % Find L Symbolically L = int(sqrt(1+dydx^2),a,b) pretty(L) % % display L disp(' ') disp('DISPLAYING L(a,b) - HIT ANY KEY TO CONTINUE') disp(' ') pause % % calc L(0,50) anum = 0; bnum = 50; Lnum = double(int(sqrt(1+dydx^2),anum,bnum)); disp('L from 0 to 50 = ') disp(Lnum)