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Chapter 7 motion handwritten notes, Study notes of Physics

Physics

Ncert book science 2025-26 handwritten notes of physics chapter 1 by allakh pandey

Typology: Study notes

2025/2026

Available from 05/03/2026

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Download Chapter 7 motion handwritten notes and more Study notes Physics in PDF only on Docsity!

Rest - position of object does not Motion = poumn ey obyect changes eee ote ° Example: Sirds ply . » pishswim Example: Babita is sitting shantt isstand ing ~ : car is movin 1 i = {25 = = artexhalg revolution. cind distance . bad Siplacement- (Radius= !Um) Dist = AR Disp = aR! ‘ = 22x14 = Yum . e and 1 Penocantey Q- Full Revolution. pinddistance, Py S$ 319 os os Diep 0 5 ae wa Dist ; Q- An obyect has moved through qa re ca ce zero displacement? es, support a answer with an - as mple. ( NCERN) A >B Arter 1 Revolution <= @- can the magnitude (value) 0 disp lq cement be e ue) °F sistance trovelle by obyect 7 , when object travels in steaight line. a 8 Dist= Dis pi value) - for the path | n ——» B-——— C <4 initial Final 3 Find distance and displacement. 1 ‘ufone. Haat dgkcantant= Ue Seceag eRe = [om =-Imv Vs {. length of actual total path covered. ort path pom initval position to L.sh fl - Hs only iz magnitude, nodisection. | 9 i4¢ magnitude and direction: 4-Can never ie Un, 3.Vector wantity. 5.Depends on the ah followed 4-Can be positive . negative ,zeso- s.Depends only on in | by object. sation ' not on He ph olli . — jem __ | = fom ~ Distance = 6+@ — Displacement = shostest path A B = |4m 7 Df = On \ “i amis Distance covered pesunittime. Speed = Distance ¢Tunit = m/s time another unit = km/h - Displacement peé unit time. ly Displaceme $.I Unit =m WY ele. Panta anothex unit = km/h Examples :- () 54km/h = 54 Ke = 15m/s (3) 36 km/h = 36X32 ®) t2km/h = F2X a - 20m/s = 40mis Q- 1 speed = Dist - 10m - mts spend St ae 7 tes . Velocity = Dish . 10M = 5m/s — _ time ‘Qs a- -ve — a. speed with ivection- 8 6m 0 is velocity . speed = dist. _ 6M ~ amis velocity = “tsk -~om ime 2s =- 3m/s CAEERRERATIONE> «ce oy change got . change inv locity per unit time. acce leralion = ginalvelocity - initial velocity time taken — 10 m/s = 30omé -10mIls £2 ela 2s —_——— e's BS 20m/s _ 10m t=2s 2s se yo ginal velocity & crunit= mis* u> f nitial velodily t— time taken e Acceleration is also avectos Quantity .ithas magnitude and ditection —— ae —_—_—> 4 4 we Slope, y ‘ : KK Ke y oA Q- Calculate — i, i) acceleration in pisst 2Sec z. il) acceleration in last 2Sec E iii) Distance covered in 6 Seconds j IV) Time period of Uniform motton a= slope = Ya-yi _ 4-0 (i) a= slope= O2-g' ~~ 4-0 ~ Ma-Xy 4-0 %-%i 8-6 = 2 m/s* a= “4 = -2m/s* (iii) dist = Area undes V-T 92a Ph (iv) same speed | = 4 a a=0O (26-4 7 KQXKY +2KU t+ a K2KM elope = 0 ( s) = ytery = 16m hihen obyects travels In 4 STRAIGHT LINE with UNIFORM (SAME ) ACCELERATION ~ ) v=utat us inital veloci v= inal veloct i) v7-U* = 2a 2. $= Distance al) > = ied + gat t= i ok taken ® solution : - ilepaea moves with a uniform assaleration U=0 7 (Qy=utat for 2 minutes. 2° y a= o-Lm/s = O+ we — on Bathe ceenar iecened. ha | t= amin=2x60s ae () y2u*=2as 12*-0% = 2X0-IXS [2A UZ = FROCL KS 10 S=I2K6 Xo = 720m Q- solution ee ‘Wisepentediatiects he motion Wanecarenes ote t) V=Litat 12x tx 6HH stop after Soh cs loebeon calecdens Ger detaaee & O= Li- 6x2 = 24-12 travels during this time. . u=12m/s 10: tyts2aSK ext c —S =. ‘cout +Lok' Fo YV=0 =o —Fy20" (ii)v*- yrs 2as O*- |e = 2X(-6)xS qe eae FIZKID= 2X%6)KS t= O¢ V=0 $= 12m $= > Q- solution (I) v= pa A stone is thrown in a vertically upward direction with a = 20-! velocity of 20 m s-’. If the acceleration of the stone during its i= 20 motion is 10 m s- in the downward direction, what will be the height attained by the stone and how much += 26 time will it take to reach there? he ight =$ t =7 (ii) v’- u*= 24s 0*- 207 = 2x (-10)xs — 20X28 = -29's s= 20m 1. civculas motion with came pee? , d= constant -7 uniform spee , | change a Divectfon Velo wale ine pilates change 7 N 3. acceletahion js not zeso. vatoms " Y ® On constant ( same) speed. vT@ satellite yevoluing avouna , ihe earth in aPraliel arbitulth ‘ : JA cyclist ona civcula track Al constant speed: