Exam One in Computer Engineering, Fall 2010, Exams of Computer Science

A computer engineering exam from fall 2010. It consists of 4 problems to be solved within 5 pages. The exam is closed book and closed note, and calculators are not permitted. The problems cover various topics such as incomplete circuits, boolean algebra, karnaugh maps, and mixed logic design.

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2012/2013

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ECE 2030 C 2:00 pm Computer Engineering Fall 2010
4 problems, 5 pages Exam One 22 September 2010
Instructions: This is a closed book, closed note exam. Calculators are not permitted. If you have
a question, raise your hand and I will come to you. Please work the exam in pencil and do not
separate the pages of the exam. For maximum credit, show your work.
Good Luck!
Your Name (please print) ________________________________________________
1 2 3 4 total
30 20 24 26 100
1
pf3
pf4
pf5

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4 problems, 5 pages Exam One 22 September 2010

Instructions: This is a closed book, closed note exam. Calculators are not permitted. If you have

a question, raise your hand and I will come to you. Please work the exam in pencil and do not

separate the pages of the exam. For maximum credit, show your work.

Good Luck!

Your Name ( please print ) ________________________________________________

1 2 3 4 total

4 problems, 5 pages Exam One 22 September 2010

Problem 1 (3 parts, 30 points) Incomplete Circuits

The three parts below contain (A) a pull up network, (B) a pull down network, and (C) an

expression to be implemented. For (A) and (B), complete the missing complementary switching

networks so the circuit contains no floats or shorts and write the Boolean expression computed

by the completed circuit. For (C), design the entire switching network. Assume the inputs and

their complements are available.

OUTx =

OUTy =

OUTz = ๎‚ž^ A ๎‚ƒ^ B ๎‚Ÿโ‹… D ๎‚ƒ C โ‹…๎‚ž^ E^ ๎‚ƒ F^ ๎‚Ÿ

4 problems, 5 pages Exam One 22 September 2010

Problem 3 (2 parts, 24 points) Karnaugh Maps

Part A (12 points) For the follow expression, derive a simplified sum of products expression

using a Karnaugh Map. Circle and list all prime implicants, indicating which are essential.

Out = A โ‹… B โ‹… C โ‹… D ๎‚ƒ B โ‹… C โ‹… D ๎‚ƒ A โ‹… B โ‹… C ๎‚ƒ A โ‹… B โ‹… C โ‹… D ๎‚ƒ A โ‹… B โ‹… C

A

A

B B

C

C

C

D

D D

prime implicants

essential? yes no

simplified SOP expression

Part B (12 points) For the follow expression, derive a simplified product of sums expression

using a Karnaugh Map. Circle and list all prime implicants, indicating which are essential.

Out =๎‚ž B ๎‚ƒ C ๎‚ƒ D ๎‚Ÿโ‹…๎‚ž A ๎‚ƒ B ๎‚ƒ D ๎‚Ÿโ‹…๎‚ž A ๎‚ƒ C ๎‚ƒ D ๎‚Ÿโ‹…๎‚ž A ๎‚ƒ B ๎‚ƒ D ๎‚Ÿโ‹…๎‚ž A ๎‚ƒ B ๎‚ƒ D ๎‚Ÿ

A

A

B B

C

C

C

D

D D

prime implicants

essential? yes no

simplified POS expression

4 problems, 5 pages Exam One 22 September 2010

Problem 4 (2 parts, 26 points) Mixed Logic Design

Part A (12 points) The following design has no supporting documentation. Derive the desired

Boolean expression and the implementation cost (in CMOS transistors).

OUTX =

OUTY =

transistors =

Part B (14 points) Now reimplement this expression using NAND gates and inverters. Use

proper mixed logic notation. Determine the cost of this implementation (in transistors).

transistors =