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Dimensional Analysis, Conversions, Load Factors, Unfactored, Each Service, Design Load, Upward or Downward, Load Combinations, Load Tracing and Load Factors, Under Footing. This is Architectural Structures assignment. Keywords of assignment are given above.
Typology: Exercises
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Problems: supplemental problems (7A, etc.) and from Onouye Chapters 4 & 5 Notes: Problems marked with a * have been altered with respect to the problem stated in the text.
7A) A reinforced concrete slab is 6 in. thick. If the density is 150 lb/ft^3 , determine the weight per unit area in lb/ft^2 and in kN/m^2. (un-dimensioned figure). (dimensional analysis & conversions) Partial answer to check with: 3.59 kN/m^2
7B) The compressive force in a column to each service (unfactored) load are: D = 465 kN, L = 290 kN, Lr = 65 kN, W = 110 kN, E = 245 kN. The wind load can also result in a tensile force. Determine the design load for the column based on LRFD using ASCE-7 load combinations (see Note Set 13.6) (load factors) Partial answer to check with: max{651, 1054.5, (952 or 717, 607), (990.5 or 770.5), 1093, (528.5 or 308.5), 663.5} kN.
7C) Roof beams that weigh 50 lb/ft and are spaced at 10’ center to center support an additional dead load of 30 lb/ft^2. Code specified roof loads are 35 lb/ft^2 downward (due to roof live load, snow or rain) and 25 lb/ft^2 upward or downward (due to wind). Determine the critical loading for LRFD using ASCE-7 load combinations (see Note Set 13.6). (load tracing and load factors) Partial answer to check with: max {490, 595, (1105 or 855), (845 or 345), 490. (565 or 65), 315} lb/ft.
Partial answer to check with: SFover= 1.43, SFslide = 1.77, pmax = 2000 lb/ft^2 (under footing)
Assume the allowable bearing pressure is 3000 psf. Also check for factor of safety against sliding if the friction coefficient is 0.62. (retaining wall behavior)
force due to pressure
Partial answer to check with: B-1: w = 335 lb/ft, reaction = 4020 lb G-1: 4 loads of 8040 lb and w (50 lb/ft), reaction = 17.08 k; column: 2 girder and 2 beam reactions = 42.2 k B-2: w = 252 lb/ft, reaction = 2016 lb G-2: 4 loads of 2016 and w = 556 lb, reaction = 12,372 lb (note: the truss joist load is in lb/ft^2 and acts on G-2)
7D) The floor framing plan is subject to uniform distributed loads of: dead load = 45 psf, live load = 120 psf. Determine the resulting reactions by the beams & load on the columns. (load tracing) Partial answer to check with: RB2 = 16706.25 lb, RG3@G1 = 10395 lb, RG1@C1 =12529.7 lb, PonC2 =20,882.8 lb.
7E) For the frame of problem 7D, use Multiframe software to find the column loads to verify your work from load tracing by constructing a 3D model (View 3D). Use the standard steel section you have been assigned which is posted in My Grades on e-Learning.. Submit the data file (.mfd) on e-Learning (under Contents-Assignments) and provide a print of the bending moment (M) and axial force (P) diagrams. Be careful to make joints on all the girders at the location of beam supports. Model the column bases as fixed. Do not use panels, but put on linearly distributed loads on G1, B2 and G2 only****. Model the beam ends only as a pin-type releases using the member restraint menu and release (check) the major moment resistance, Mz’, for each end.
C
G
dead load = 45 psf live load = 120 psf
B
C
C4 C
C
18 ft
C
C4 (^) C
14 ft
8.5 ft
ope
ning
6 ft
B G
G
B
G
G
G2 12 ft
G3 B
G
decking
decking
and
Find all support reactions. (load tracing)
with load values V