Electric Circuit Elements and Power Calculation, Lecture notes of Electronics

Various electric circuit elements including ideal voltage and current sources, controlled sources, resistors, and their interconnections. It also discusses Ohm's Law, Kirchhoff's Laws, voltage and current division, and delta-wy transformation. examples and solutions for calculating power in electric circuits.

Typology: Lecture notes

2019/2020

Uploaded on 12/03/2020

llyp
llyp 🇲🇾

1

(1)

2 documents

1 / 25

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Module 02
Electric Circuit Elements, Voltage & Current Sources, Resistors, Ohm’s
Law, Kirchhoff's Law, Voltage Division, Current Division, Delta-Wye
Transformation
1
pf3
pf4
pf5
pf8
pf9
pfa
pfd
pfe
pff
pf12
pf13
pf14
pf15
pf16
pf17
pf18
pf19

Partial preview of the text

Download Electric Circuit Elements and Power Calculation and more Lecture notes Electronics in PDF only on Docsity!

Module 02

Electric Circuit Elements, Voltage & Current Sources, Resistors, Ohm’s

Law, Kirchhoff's Law, Voltage Division, Current Division, Delta-Wye

Transformation

Electric Circuit Elements

1) Ideal (Independent) Sources

 Delivers a prescribed voltage independent of the current flowing.

v

i

i-V Characteristics

Ideal Voltage Source

2) Controlled (Dependent) Sources

 The voltage or current of the source depends on another voltage or current

elsewhere in the circuit.

Type of Sources in Circuits

A. Constant Sources

B. Sinusoidal Sources

 D irect C urrent ( DC ) Signals

 Normally represent signal from battery

 DC Power Supply Sources

 A lternating C urrent ( AC ) Signals

 Sine waveform

 Normally represent signal from power outlet

 Function generator

5) Conductance

 Is the reciprocal of resistance.

ܩ =

1

ܴ

 Units: siemens (S)

Review

If the interconnection is valid, find the total power developed by the

voltage sources. If the interconnection is not valid, explain why?

௟௢௢௣

Thus, interconnection is not valid

Solution

Solution

KVL around mesh 1 (CW):

− 50 − 20 ݅ (^) ఙ + 18 ݅ (^) ∆ = 0

KVL around mesh 2 (CW):

− 18 ݅ (^) ∆ + 5 ݅ (^) ఙ + 40 ݅ (^) ఙ = 0

Solve:

− 50 − 20 ݅ (^) ఙ + 5 ݅ (^) ఙ + 40 ݅ (^) ఙ = 0

݅ ఙ = ܣ

Sub ݅ ఙ = ܣ2:

(a)

Thus : ݒ଴ = 2A 40 Ω = ૡ૙ ܄

Solution

(b)

at node A: ݅ ௫ = ݅∆ + ݅௬

A B

݅ ∆ = 5A

ܲ ௗ௘௟௜௩௘௥௘ௗ (" − " sign): ܲ =^ ݅ݒ

To find ݅ ௫, apply KCL :

෍ ݅௜௡ = ෍ ݅௢௨௧

at node B: ݅ ௬ = ݅ఙ + ݅8 (^) ∆

Solve: ݅ ௫ = 47 ܣ, ݅௬ = 42 ܣ

= − 2350 W

= − 1880 W

ܲ ௔௕௦௢௥௕௘ௗ = (݅ ∆)ଶ^18 + (݅ ఙ)ଶ^40 + 5 ݅ ఙ ݅௬ + ݒ௫ 8 ݅ ∆ + 20 (݅8 ∆)

ܲ ௔௕௦௢௥௕௘ௗ (" + " sign): (^) ܲ = ݅ ଶܴ

To find ݒ௫, apply KVL :

෍ ݒ = 0 ௟௢௢௣ −ݒ଴ + ݒ௫ + 20 = 0 ݒ௫ = ݒ଴ − 20 = 80 − 20 = 60 ܸ

∴ ෍ ࡼࢊࢋ࢘ࢋ࢜࢏࢒ࢋࢊ = ෍ ࡼࢊࢋ࢈࢘࢕࢙࢈ࢇ = ૝૛૜૙ ࢃ

− 4230 W

Parallel Resistors & Current Division

 Parallel-connected circuit elements have the same voltage.

 Parallel elements are connected between the same nodes.

KCL from node a to node b:

݅ ௦ = ݅ଵ + ݅ଶ + ݅ଷ + ݅ସ

Ohm’s Law

௦ ܴ ଵ

௦ ܴ ଶ

௦ ܴ ଷ

௦ ܴ ସ

Thus, ܸ ௦ =

௦ 1 ܴ ଵ +^

ܴ ଶ +^

ܴ ଷ +^

Review

Find power delivered by the 5 A source?

Solution Simplified and find an equivalent circuit. Starts by combining elements from right to left.

௘௤ =^ ܴ ଺଴Ω//ܴ^ ଷ଴Ω =^

∴ ࡼ࡭૞= ܫଶ^ ܴ = (ܣ5)ଶ^20 Ω = ࢃ૞૙૙

Wheatstone Bridge

 The Wheatstone bridge circuit is used to precisely measure resistances.

 To find the value of ܴ ௑ , we adjust the variable resistor ܴ ଷ until there is no current in the galvanometer.

 Then calculate the unknown resistor using

ܴ ௑ =

ܴ ଶ ܴ ଵ

ܴ ଷ

Review

(a) Find resistance as seen by the voltage source?

(b) Find power dissipated in 31 Ω resistor.

Solving this will introduces the concepts of Wye & Delta circuits (Tee & Pi Circuits).

Answers

(a) ܴ ௘௤ = 80 Ω

(b) ܲ ଷଵΩ = ܹ