14. Since both charges are positive (and aligned along the zaxis) we have
Enet
=1
4πε0q
(z−d/2)2+q
(z+d/2)2.
For zdwe have (z±d/2)−2≈z−2,so
Enet
≈1
4πε0q
z2+q
z2=2q
4πε0z2.
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Electric Field Problem with Solution: Positive Charges, Exercises of Electrical Engineering
This is solution to problems related Electrical Engineering course. It was suggested by Prof. Bhooshan Sawhney at Shree Ram Swarup College of Engineering and Management. It includes: Coordinate, System, Origin, Direction, Rough, Sketch, Lines, Magnetic, Electric, Fields
Typology: Exercises
2011/2012
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- Since both charges are positive (and aligned along the z axis) we have
Enet
4 πε 0
[
q
(z − d/2) 2
q
(z + d/2) 2
]
For z d we have (z ± d/2) − 2 ≈ z − 2 , so
Enet
4 πε 0
q
z 2
q
z 2
2 q
4 πε 0 z 2