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Solutions to various ph calculation problems involving the determination of ph and poh for hydroiodic acid, sodium hydroxide, diluted nitric acid, and a solution containing hydrochloric acid and nitrous acid.
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Find the pH of a 9.8 x 10-4^ M HI solution.
Find the pH of a 2.76 x 10-4^ M NaOH solution. (Hint: this is a basic solution – concentration is of OH - )
Find the pH of a solution made by diluting 35 mL of 4.5 M HNO 3 to a final volume of 2.25 L.
Find the pH of 4.75 L of an aqueous solution that contains 3.20 grams of HCl and 1. grams of nitrous acid.
Find the pOH’s for the solutions in problems 1 – 4 above:
pH = -log (9.8 x 10-4) = 3.
pOH = -log (2.76 x 10-4) = 3. pH = 14.000 – 3.559 = 10.
M 2 = M 1 V 1 = (4.5 M)(35 mL) = 0.070 M V 2 (2250 mL)
pH = -log (0.070) = 1.
Find the pH of 4.75 L of an aqueous solution that contains 3.20 grams of HCl and 1. grams of nitrous acid. 3.20 g HCl x 1 mole HCl = 0.0878 mole HCl 36.45 g HCl 1.85 g HNO 2 x 1 mole HNO 2 = 0.0394 mole HNO 2 47 g HNO 2 0.0878 mole HCl + 0.0394 mole HNO 2 = 0.1272 moles acid 0.1272 moles acid = 0.0268 M acid solution 4.75 L H 2 O pH = -log (0.0268) = 1.
Find the pOHs for the solutions in problems 1 – 4 above:
#1) pOH = 14.00 – 3.01 = 10.
#2) pOH = 3.
#3) pOH = 14.00 – 1.15 = 12.
#4) pOH = 14.000 – 1.572 = 12.