fluid kinetics final exam, Exams of Fluid Dynamics

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Fluid Mechanics for Chemical Engineering (Class 1), Course No.: 24605, Spring 2021
Final Exam on June 14, 2021
Problem #1 (15 pt). The water flow in a circular pipe with a radius (R) of 1 cm is driven by a pressure
gradient. The flow velocity profile (u) is expressed by the equation below. When the magnitude of shear
stress at the inner surface of the circular pipe is – 0.1 N/m2, what is the maximum velocity (umax) of the
water flow in the pipe? The viscosity of water (μ) is 1.0×10-3 kg/m s.
𝑢(𝑟)= 𝑢𝑚𝑎𝑥 [1 (𝑟
𝑅)2]
Problem #2 (20 pt). When the solid bulb with a cylindrical rod is submerged in the water, the point P
on the cylindrical rod is located on the free surface of the water, as shown in Figure (a) below. When
the solid bulb with the cylindrical rod is submerged in the unknown oil with its density of ρo, the solid
bulb rises and the point P on the rod indicates the height h of 50 cm above the free surface of the oil
(Figure (b)). What is the density (ρo) of the oil?
A total volume (V) of the bulb and the cylindrical rod submerged in the water is V = 0.5 m3. The cross-
sectional area (A) of the cylindrical rod is A = 0.03 m2. The density of water (ρw) is 1,000 kg/m3.
(Hint: Use of the Law of Buoyancy)
Problem #3 (10 pt). The layered fluids (1 meter of water and 3 meter of oil) are held by the vertical
wall. The density of water (ρw) is 1,000 kg/m3 and the specific gravity of the oil is 2. What is the
hydrostatic force on the wall with a width of 1 meter?
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Fluid Mechanics for Chemical Engineering (Class 1), Course No.: 24605, Spring 20 21

Final Exam on June 14 , 20 21

Problem #1 (1 5 pt). The water flow in a circular pipe with a radius ( R ) of 1 cm is driven by a pressure gradient. The flow velocity profile ( u ) is expressed by the equation below. When the magnitude of shear stress at the inner surface of the circular pipe is – 0.1 N/m^2 , what is the maximum velocity ( u max) of the water flow in the pipe? The viscosity of water ( μ ) is 1.0× 10 -^3 kg/m s.

𝑢(𝑟)^ = 𝑢𝑚𝑎𝑥 [ 1 − (

𝑟 𝑅

2

]

Problem #2 (20 pt). When the solid bulb with a cylindrical rod is submerged in the water, the point P on the cylindrical rod is located on the free surface of the water, as shown in Figure (a) below. When the solid bulb with the cylindrical rod is submerged in the unknown oil with its density of ρo , the solid bulb rises and the point P on the rod indicates the height h of 50 cm above the free surface of the oil (Figure (b)). What is the density ( ρo ) of the oil? A total volume ( V ) of the bulb and the cylindrical rod submerged in the water is V = 0.5 m^3. The cross- sectional area ( A ) of the cylindrical rod is A = 0.03 m^2. The density of water ( ρw ) is 1,000 kg/m^3. ( Hint : Use of the Law of Buoyancy ) Problem #3 (10 pt). The layered fluids (1 meter of water and 3 meter of oil) are held by the vertical wall. The density of water ( ρw ) is 1,000 kg/m^3 and the specific gravity of the oil is 2. What is the hydrostatic force on the wall with a width of 1 meter?

Problem # 4 ( 15 pt). The figure below shows an idealized view of a return elbow or “U-band,” which is connected to two pipes by flexible hoses(couplings) that transmit no forces. Water flows into and out of the U-band at a velocity of 10 m/s through the pipe, which has an internal diameter of 0.1 m. The gauge pressures at points 1 and 2 are 300 and 250 kPa, respectively. The water density is 1,000 kg/m^3. What horizontal force F is needed to keep the U-band in position? Problem # 5 ( 20 pt). The incompressible fluid with constant viscosity flows between two horizontally parallel plates due to the pressure gradient. The two plates are separated with a distance of h. The upper plate moves at constant velocity U and the lower plate is stationary. The flow is fully developed. The length and width of the plates are very large compared to the gap between two plates. (a) (10 pt) Derive an expression for the fluid velocity. (b) (10 pt) Find the pressure gradient to be zero shear stress at the lower wall. Problem # 6 ( 20 pt). The velocity field of an incompressible steady laminar flow is given by V = ( y^2 /4) i

  • ( x^2 /4) j in the unit of meter per sec. The flow is considered inviscid. The y - axis is vertical direction, and thus, the gravitational field is g = − g j , where g is gravitational acceleration. Determine the pressure gradient at the point (2 m, 2 m), when the density ( ρ ) of fluid is 1000 kg/m^3 and the gravitational acceleration ( g ) is 9.8 m/s^2.