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If we apply a force on an object, the object's speed will change. ... The gravitational force Fg between two objects is directly related to the mass and ...
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Review the Concept of ‘Force’
Q1) How can we justify that the force of gravity of Earth is acting on the Moon? Explain your answer by applying Newton’s 1st^ law!!
Gravitational Fields – Force at distance
Newton’s Law of Universal Gravitation Newton did not discover gravity. What he discovered was that gravity is _universal(!). => Everything pulls on everything else that involves only mass and distance_**
Q2) When the planet Uranus approached Jupiter, the great mass of Jupiter caused Uranus to slightly wobble(‘ perturbation ’). However, in the eighteenth century, scientists have observed that even though Uranus was far away from Jupiter, there was a point in space where Uranus again showed perturbation. What could this mean? a) The law of gravity was a little different at far distance in space b) Actually, there really was a planet near that point. It’s just that scientist did not discover it yet c) Newton’s law of gravity applies only to certain areas in space; only areas near the Earth
Fg = 𝐺𝐺 𝑚𝑚^1 𝑟𝑟𝑚𝑚 22^ m^1 r m (^2)
- m 1 , m 2 is the mass of the object, and r is the distance between the two center of each mass, not from the surface
*How was the constant ‘ G ’ discovered? step i) Suspend a triangular container of very dense mercury flask of a known mass on one arm of a very sensitive balance that is put in equilibrium
mercury flask hook
step ii) Place a 6-ton lead sphere beneath the mercury flask. The lead is massive enough to pull the flask downward. F (^) g due to the mass of the lead
step iii) Add known weights on the hook until balance is restored. Since the system is balanced, it means that the total weight on the hook is equal the gravitational pull F (^) g due to the mercury flask and the lead
mercury flask
F g = Weights
Fg = 𝐺𝐺 𝑚𝑚^1 𝑟𝑟 2 𝑚𝑚^2
Q8) Calculate the force of gravity on a 1kg mass if it were 6.4×10^6 m above the Earth’s surface. The mass of the Earth is me =6×10 24 kg, and its radius is Re =6.4×10 6 m. ( G=6.67×10-11^ N·m^2 /kg^2 ) a) 7.42N b) 4.96N c) 2.44N d) 1.12N
r
R (^) e
Q9) Calculate the force of gravity between the Earth and the moon. The average distance between the Earth and the moon is r=3.8×10^8 m. The mass of the Earth me =6×10 24 kg and mass of the moon is mm =7.4×10 22 kg. ( G=6.67×10 -11^ N·m^2 /kg^2 ) a) 7.4×10^20 N b) 4.1×10^20 N c) 2.0×10^20 N d) 1.1×10 20 N
moon r
Earth
Q10) A plane is flying at a height of 10000 meters above the surface. If the plane descent down to a height of 5000 meters, how much will Fg decrease? ( G=6.67×10-11^ N·m^2 /kg^2 ) a) Fg will reduce to one-half b) Fg will triple c) Not sure, but Fg will surely reduce a lot d) Fg will remain pretty much unchanged