Higher Algebra 1, Exercises - Mathematics8, Exercises of Algebra

Tensor products,Chevalley’s Theorem,basics on tensor, products of algebras, isomorphic, polynomial equations,vector space.

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Math 250a: Higher Algebra
Problem Set #8 (29 November 2004):
Tensor products etc.; Chevalley’s Theorem
Some overdue basics on tensor products of algebras:
1. i) Let Abe any algebra over a field k. Prove that AkMn(k) is isomorphic
as a k-algebra with Mn(A), for each positive integer n.
ii) Prove that the tensor product Mm(k)kMn(k) is isomorphic as a k-algebra
with Mmn(k) for all positive integers m, n (and an arbitrary commutative
field k).
An instructive example of a division algebra in positive characteristic:
Let kbe a finite field, and Athe noncommuting k-algebra generated by two
indeterminates x, y satisfying xy yx = 1.
2. i) Prove that Ahas no zero divisors, and that its center consists of the poly-
nomials in X:= xpand Y:= yp. (Hint for the second part: compare xya
with yax, and likewise xbywith yxb.)
ii) Let R=k[X, Y ] be that center, and Kits fraction field (the field of rational
functions in two variables with coefficients in k). Let D=ARK. Show
that Dis a skew field with center K.
iii) We know that Dmust have a separable decomposition field. Find an
inseparable field extension K0/K of degree psuch that DKK0
=Mp(K0).
Can you find, at least for p= 2 or p= 3, an explicit isomorphism by finding
endomorphisms x, y of K0psatisfying xp=X,yp=Y, and xy yx = 1?
Finally, we obtain Chevalley’s theorem on solutions of polynomial equations in
many variables over a finite field, and deduce the triviality of Br(k).
Fix a finite field k=Fq, and let pbe its characteristic, so qis some power of p.
3. i) Prove that Pxkxm= 0 for all nonnegative integers m < q 1. What is
Pxkxmfor an arbitrary nonnegative mZ?
It follows that PxkP(x) = 0 for any polynomial Pk[X] of degree less than
q1. We next extend this to polynomials in several variables X1, . . . , Xn. The
“degree” of a nonzero monomial cQn
i=1 Xmi
iis Pimi; the degree of a sum of
distinct monomials is the largest of those monomials’ degrees. This defines the
degree on k[X1, . . . , Xn]. (Note that this degree is invariant under an invertible
linear change of variables; thus we may speak of a polynomial of degree mon an
n-dimensional vector space over kwithout specifying which coordinates on that
space we use.)
ii) Prove that
X
(x1,...,xn)kn
P(x1, . . . , xn) = 0
for every polynomial Pk[X1, . . . , Xn] of degree less than n(q1).
pf2

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Math 250a: Higher Algebra Problem Set #8 (29 November 2004): Tensor products etc.; Chevalley’s Theorem

Some overdue basics on tensor products of algebras:

  1. i) Let A be any algebra over a field k. Prove that A ⊗k Mn(k) is isomorphic as a k-algebra with Mn(A), for each positive integer n. ii) Prove that the tensor product Mm(k)⊗k Mn(k) is isomorphic as a k-algebra with Mmn(k) for all positive integers m, n (and an arbitrary commutative field k).

An instructive example of a division algebra in positive characteristic:

Let k be a finite field, and A the noncommuting k-algebra generated by two indeterminates x, y satisfying xy − yx = 1.

  1. i) Prove that A has no zero divisors, and that its center consists of the poly- nomials in X := xp^ and Y := yp. (Hint for the second part: compare xya with yax, and likewise xby with yxb.) ii) Let R = k[X, Y ] be that center, and K its fraction field (the field of rational functions in two variables with coefficients in k). Let D = A ⊗R K. Show that D is a skew field with center K. iii) We know that D must have a separable decomposition field. Find an inseparable field extension K′/K of degree p such that D ⊗K K′^ ∼= Mp(K′).

Can you find, at least for p = 2 or p = 3, an explicit isomorphism by finding endomorphisms x, y of K′p^ satisfying xp^ = X, yp^ = Y , and xy − yx = 1?

Finally, we obtain Chevalley’s theorem on solutions of polynomial equations in many variables over a finite field, and deduce the triviality of Br(k).

Fix a finite field k = Fq , and let p be its characteristic, so q is some power of p.

  1. i) Prove that

x∈k x m (^) = 0 for all nonnegative integers m < q − 1. What is ∑ x∈k x m (^) for an arbitrary nonnegative m ∈ Z?

It follows that

x∈k P^ (x) = 0 for any polynomial^ P^ ∈^ k[X] of degree less than q − 1. We next extend this to polynomials in several variables X 1 ,... , Xn. The “degree” of a nonzero monomial c

∏n i=1 X

mi i is^

i mi; the degree of a sum of distinct monomials is the largest of those monomials’ degrees. This defines the degree on k[X 1 ,... , Xn]. (Note that this degree is invariant under an invertible linear change of variables; thus we may speak of a polynomial of degree m on an n-dimensional vector space over k without specifying which coordinates on that space we use.)

ii) Prove that (^) ∑

(x 1 ,...,xn)∈kn

P (x 1 ,... , xn) = 0

for every polynomial P ∈ k[X 1 ,... , Xn] of degree less than n(q − 1).

iii) Now let f ∈ k[X 1 ,... , Xn] be a polynomial of degree less than n. Take P = f q−^1 in (ii) to prove that the number of solutions in kn^ of the equation f (x 1 ,... , xn) = 0 is a multiple of p.

As noted class the degree bound in (iii) is sharp. As also noted, it follows from (iii) that every finite skew field is commutative. Indeed, let K be such a field, and k its center. Then K is a vector space over k, of dimension n^2 for some positive integer n. The reduced norm is a polynomial of degree n on that vector space that vanishes only at the origin. Hence n ≥ n^2. Therefore n = 1, and K = k as claimed.

Can you generalize Chevalley’s theorem to simultaneous solutions of several poly- nomials of low degree? Can you get a formula for the enumeration mod p of solutions of x^3 + y^3 + z^3 = 0 and x^4 + y^4 = z^2 in k^3 , or x^3 − x = y^2 in k^2?

Problems 1–3 are due in class Monday, December the 6th.

  1. Send me e-mail, or schedule a time to meet with me, to discuss your final paper topic.