CEE 379 HW#9: Determining Degree of Kinematic Indeterminacy and Beam Stiffness Matrices - , Assignments of Civil Engineering

The solution to problem 1 of homework 9 in cee 379, a structural engineering course. The problem involves determining the degree of kinematic indeterminacy and calculating the beam stiffness matrices for three members (ab, bc, cd) in a multi-member beam. Input and calculated properties for each member, as well as the equilibrium equations and the free stiffness matrix.

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CEE 379
HW#9
PROFESSOR EBERHARD
AUTUMN 2007
PROBLEM 1:
a.) Determi ne the degree of kinem atic indeterminac y.
θ
B
+ D
B
+ θ
C
+ θ
D
= 4
b.) Beam Siffness Matrices For Beams AB, BC, CD
Member AB : Elemental Stiffness Matrix
Input Properties E (ksi) I (in
4
)X
N
(in.)
YN
(in.) X
F
(in.) Y
F
(in.) d (in.)
29000 1500 0 0 264 0 15.6
Calculated Properties
DOF 1 DOF 2 DOF 3 DOF 4
L (in.) EI (k/*n
2
.)
q
Ny'
28.37 3744. 83 -28.37 3744.83
d
Nx
DOF 1
264.00 43500000.00
m
NFz'
3744.83 659090.91 -3744.83 329545.45
d
Ny
DOF 2
cos(theta) sin(theta)
q
Fy'
-28.37 -3744.83 28.37 -3744.83
d
Fx
DOF 3
1.00 0.00
m
Fz'
3744.83 329545.45 -3744.83 659090.91
d
Fy
DOF 4
Member BC : Elemental Stiffness Matrix
Input Properties E (ksi) I (in
4
)X
N
(in.)
YN
(in.) X
F
(in.) Y
F
(in.) d (in.)
29000 1500 264 0 462 0 15.6
Calculated Properties
DOF 3 DOF 4 DOF 5 DOF 6
L (in.) EI (k/*n
2
.)
q
Ny'
67.25 6657. 48 -67.25 6657.48
d
Nx
DOF 3
198.00 43500000.00
m
NFz'
6657.48 878787.88 -6657.48 439393.94
d
Ny
DOF 4
cos(theta) sin(theta)
q
Fy'
-67.25 -6657.48 67.25 -6657.48
d
Fx
DOF 5
1.00 0.00
m
Fz'
6657.48 439393.94 -6657.48 878787.88
d
Fy
DOF 6
Member CD : Elemental Stiffness Matrix
Input Properties E (ksi) I (in
4
)X
N
(in.)
YN
(in.) X
F
(in.) Y
F
(in.) d (in.)
29000 1500 462 0 660 0 15.6
Calculated Properties
DOF 5 DOF 6 DOF 7 DOF 8
L (in.) EI (k/*n
2
.)
q
Ny'
67.25 6657. 48 -67.25 6657.48
d
Nx
DOF 5
198.00 43500000.00
m
NFz'
6657.48 878787.88 -6657.48 439393.94
d
Ny
DOF 6
cos(theta) sin(theta)
q
Fy'
-67.25 -6657.48 67.25 -6657.48
d
Fx
DOF 7
1.00 0.00
m
Fz'
6657.48 439393.94 -6657.48 878787.88
d
Fy
DOF 8
c.) Express Equi librium Equatio ns at each DOF
Assemble Glo bal Stiffness Matrix , K (k/in)
DOF 1 DOF 2 DOF 3 DOF 4 DOF 5 DOF 6 DOF 7 DOF 8
28.37
-28.37
0.00
0.00
0.00
0.00
DOF 1
D
A
659090.91
-3744.83
329545.45
0.00
0.00
0.00
0.00
DOF 2
θ
A
-28.37
-3744.83
95.62
-67.25
0.00
0.00
DOF 3
D
B
329545.45
1537878.79
-6657.48
439393.94
0.00
0.00
DOF 4
θ
B
0.00
0.00
-67.25
-6657.48
134.49
0.00
-67.25
DOF 5
D
C
0.00
0.00
439393.94
0.00
1757575.76
-6657.48
439393.94
DOF 6
θ
C
0.00
0.00
0.00
0.00
-67.25
-6657.48
67.25
-6657.48
DOF 7
D
D
0.00
0.00
0.00
0.00
439393.94
-6657.48
878787.88
DOF 8
θ
D
BLUE = FREE DOF
Partition Fr ee Stiffness Matrix , K
11 (k/in)
DOF 4 DOF 5 DOF 6 DOF 8
1537878.79
-6657.48
439393.94
0.00
DOF 4
θ
B
-6657.48
134.49
0.00
DOF 5
D
C
439393.94
0.00
1757575.76
439393.94
DOF 6
θ
C
0.00
439393.94
878787.88
DOF 8
θ
D
=
=
K
11
(K
ff)
=
pf2

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Download CEE 379 HW#9: Determining Degree of Kinematic Indeterminacy and Beam Stiffness Matrices - and more Assignments Civil Engineering in PDF only on Docsity!

CEE 379HW#9PROFESSOR EBERHARD

AUTUMN 2007 PROBLEM 1:

a.) Determine the degree of kinematic indeterminacy. θB + DB + θC + θD = 4 b.) Beam Siffness Matrices For Beams AB, BC, CD Member AB : Elemental Stiffness Matrix Input PropertiesCalculated Properties E (ksi) 29000 I (in 15004 ) XN (in.) (^0) DOF 1YN (in.) (^0) DOF 2XF 264 (in.) (^) DOF 3YF 0 (in.) (^) DOF 4d (in.)15.

cos(theta)^ 264.00^ L (in.)^ 43500000.00EI (k/*nsin(theta)^2 .) mqqNy'NFz'Fy'^ 3744.83-28.3728.37^ 659090.91-3744.833744.83^ -3744.83-28.3728.37 329545.45-3744.833744.83^ dddNxNyFx^ DOF 1^ DOF 2 DOF 3 Member BC : Elemental Stiffness Matrix^ 1.00^ 0.00^ mFz'^ 3744.83^ 329545.45^ -3744.83^ 659090.91^ dFy^ DOF 4 Input PropertiesCalculated Properties E (ksi) 29000 I (in 15004 )^ XN 264 (in.) (^) DOF 3YN (in.) (^0) DOF 4XF 462 (in.) (^) DOF 5YF 0 (in.) (^) DOF 6d (in.)15.

cos(theta)^ 198.00^ L (in.)^ 43500000.00EI (k/*nsin(theta)^2 .) mqqNy'NFz'Fy'^ 6657.48-67.2567.25^ 878787.88-6657.486657.48^ -6657.48-67.2567.25 439393.94-6657.486657.48^ dddNxNyFx^ DOF 3^ DOF 4 DOF 5 Member CD : Elemental Stiffness Matrix^ 1.00^ 0.00^ mFz'^ 6657.48^ 439393.94^ -6657.48^ 878787.88^ dFy^ DOF 6 Input PropertiesCalculated Properties E (ksi) 29000 I (in 15004 )^ XN 462 (in.) (^) DOF 5YN (in.) (^0) DOF 6XF 660 (in.) (^) DOF 7YF 0 (in.) (^) DOF 8d (in.)15.

cos(theta)^ 198.00^ L (in.)^ 43500000.00EI (k/*nsin(theta)^2 .) mqqNy'NFz'Fy'^ 6657.48-67.2567.25^ 878787.88-6657.486657.48^ -6657.48-67.2567.25 439393.94-6657.486657.48^ dddNxNyFx^ DOF 5^ DOF 6 DOF 7 c.) Express Equilibrium Equations at each DOF^ 1.00^ 0.00^ mFz'^ 6657.48^ 439393.94^ -6657.48^ 878787.88^ dFy^ DOF 8 Assemble Global Stiffness Matrix , K (k/in) 3744.83 DOF 1 28.37 (^) 659090.913744.83DOF 2 (^) -3744.83DOF 3-28.37 (^) 329545.453744.83 DOF 4 DOF 50.000.00 DOF 60.000.00 DOF 70.000.00 DOF 80.000.00 DOF 1 DOF 2 DθAA 3744.83^ -28.37 0.00 329545.45-3744.830.00 2912.65-67.2595.62^ 1537878.79-6657.482912.65^ -6657.48-67.25134.49^ 439393.946657.480.00 -67.250.000.00^ 6657.480.000.00^ DOF 3 DOF 4 DOF 5^ DθDBBC 0.00 0.00 0.00 0.000.000.00 6657.480.000.00 439393.940.000.00 (^) 6657.48-67.250.00 1757575.76439393.94-6657.48 -6657.48-6657.4867.25 439393.94878787.88-6657.48 DOF 6 DOF 7 DOF 8 θDθCDD Partition Free Stiffness Matrix , K 1537878.79 11 (k/in) DOF 4 -6657.48DOF 5 439393.94DOF 6 DOF 80.00 DOF 4^ BLUE = FREE DOF θB 439393.94^ -6657.48 0.00 6657.48134.490.00 1757575.76439393.940.00^ 439393.94878787.886657.48^ DOF 5 DOF 6 DOF 8^ DθθCDC

=

=

K 11 (Kff)

=

Invert Free Stiffness Matrix , K11 (in/k) 0.0000010 DOF 4 0.0000751DOF 5 -0.0000001DOF 6 -0.0000005DOF 8 DOF 4 -0.0000001 -0.0000005^ 0.0000751^ -0.00015020.01858810.0000188^ -0.00000050.00001880.0000007^ -0.0001502-0.00000050.0000025^ DOF 5 DOF 6 DOF 8 Force Matrix at Free DOFs , Q Input Forces k (kip) PC-12 (kip) M-480.0000D (kipin) -12.0^ 0.0 0.0^ kipinkipkipin^ DOF 4 DOF 5 DOF 6^ θDθBCC Equations of Equilibrium^ -480.0^ kipin^ DOF 8^ θD d.) Unknown Displacements and Rotations at DOF Displacement Matrix at DOFs, Df (^) (in) -0.000658 (^) rad DOF 4 θB -0.150958 0.000017 0.000589 (^) inradrad DOF 5 DOF 6 DOF 8 DθθCDC Global Displacement Matrix (D) (in) Dx1 Dy1 Dx2 0.0000000.0000000.000000 inradin DOF 1 DOF 2 DOF 3 DθDAAB Dy2 Dx3 Dx3 -0.000658-0.1509580.000017 radinrad DOF 4 DOF 5 DOF 6 θDθBCC Dx4 Dy4 0.0000000.000589 inrad DOF 7 DOF 8 DθDD e.) End Member Forces and Moments Beam End Forces 0.000000 0.000000 0.000000 D^ Q = kD (kip,kipin)** -217.00-2.472.47^ DOF 1 DOF 2 DOF 3 (^) -0.000658-0.1509580.000000 D^ Q = kD (kip,kipin)** 434.00-5.885.88 DOF 3 DOF 4 DOF 5^ -0.1509580.0000170.000000 D^ Q = kD (kip,kipin)** -731.00-6.126.12 DOF 5 DOF 6 DOF 7 j.) Flexural Stresses^ -0.000658^ -434.00^ DOF 4^ 0.000017^ 731.00^ DOF 6^ 0.000589^ -480.00^ DOF 8 S = 2I/d m ftNN -217.000192.308-1.128 inkinksi^3 S = 2I/dmftNN 434.000192.312.257 inkinksi^3 S = 2I/dmftNN -731.000192.31-3.801 inkinksi^3 fb m ftFNF -434.000-2.2571.128 ksikinksi fbmftFNF 731.000-2.2573.801 ksikinksi fbmftFNF -480.000-2.4963.801 ksik*inksi Stresses Do Not Exceed Maximum of 20-ksi^ fbF^ 2.257^ ksi^ fbF^ -3.801^ ksi^ fbF^ 2.496^ ksi

K 11 x (Df )

Member CD

Member CD

(Df ) =

Member AB Member BC

Member AB Member BC

(Qk ) = (Qk ) =

K 11 -1^ (Kff-1) =