

Study with the several resources on Docsity
Earn points by helping other students or get them with a premium plan
Prepare for your exams
Study with the several resources on Docsity
Earn points to download
Earn points by helping other students or get them with a premium plan
The solution to problem 1 of homework 9 in cee 379, a structural engineering course. The problem involves determining the degree of kinematic indeterminacy and calculating the beam stiffness matrices for three members (ab, bc, cd) in a multi-member beam. Input and calculated properties for each member, as well as the equilibrium equations and the free stiffness matrix.
Typology: Assignments
1 / 2
This page cannot be seen from the preview
Don't miss anything!


a.) Determine the degree of kinematic indeterminacy. θB + DB + θC + θD = 4 b.) Beam Siffness Matrices For Beams AB, BC, CD Member AB : Elemental Stiffness Matrix Input PropertiesCalculated Properties E (ksi) 29000 I (in 15004 ) XN (in.) (^0) DOF 1YN (in.) (^0) DOF 2XF 264 (in.) (^) DOF 3YF 0 (in.) (^) DOF 4d (in.)15.
cos(theta)^ 264.00^ L (in.)^ 43500000.00EI (k/*nsin(theta)^2 .) mqqNy'NFz'Fy'^ 3744.83-28.3728.37^ 659090.91-3744.833744.83^ -3744.83-28.3728.37 329545.45-3744.833744.83^ dddNxNyFx^ DOF 1^ DOF 2 DOF 3 Member BC : Elemental Stiffness Matrix^ 1.00^ 0.00^ mFz'^ 3744.83^ 329545.45^ -3744.83^ 659090.91^ dFy^ DOF 4 Input PropertiesCalculated Properties E (ksi) 29000 I (in 15004 )^ XN 264 (in.) (^) DOF 3YN (in.) (^0) DOF 4XF 462 (in.) (^) DOF 5YF 0 (in.) (^) DOF 6d (in.)15.
cos(theta)^ 198.00^ L (in.)^ 43500000.00EI (k/*nsin(theta)^2 .) mqqNy'NFz'Fy'^ 6657.48-67.2567.25^ 878787.88-6657.486657.48^ -6657.48-67.2567.25 439393.94-6657.486657.48^ dddNxNyFx^ DOF 3^ DOF 4 DOF 5 Member CD : Elemental Stiffness Matrix^ 1.00^ 0.00^ mFz'^ 6657.48^ 439393.94^ -6657.48^ 878787.88^ dFy^ DOF 6 Input PropertiesCalculated Properties E (ksi) 29000 I (in 15004 )^ XN 462 (in.) (^) DOF 5YN (in.) (^0) DOF 6XF 660 (in.) (^) DOF 7YF 0 (in.) (^) DOF 8d (in.)15.
cos(theta)^ 198.00^ L (in.)^ 43500000.00EI (k/*nsin(theta)^2 .) mqqNy'NFz'Fy'^ 6657.48-67.2567.25^ 878787.88-6657.486657.48^ -6657.48-67.2567.25 439393.94-6657.486657.48^ dddNxNyFx^ DOF 5^ DOF 6 DOF 7 c.) Express Equilibrium Equations at each DOF^ 1.00^ 0.00^ mFz'^ 6657.48^ 439393.94^ -6657.48^ 878787.88^ dFy^ DOF 8 Assemble Global Stiffness Matrix , K (k/in) 3744.83 DOF 1 28.37 (^) 659090.913744.83DOF 2 (^) -3744.83DOF 3-28.37 (^) 329545.453744.83 DOF 4 DOF 50.000.00 DOF 60.000.00 DOF 70.000.00 DOF 80.000.00 DOF 1 DOF 2 DθAA 3744.83^ -28.37 0.00 329545.45-3744.830.00 2912.65-67.2595.62^ 1537878.79-6657.482912.65^ -6657.48-67.25134.49^ 439393.946657.480.00 -67.250.000.00^ 6657.480.000.00^ DOF 3 DOF 4 DOF 5^ DθDBBC 0.00 0.00 0.00 0.000.000.00 6657.480.000.00 439393.940.000.00 (^) 6657.48-67.250.00 1757575.76439393.94-6657.48 -6657.48-6657.4867.25 439393.94878787.88-6657.48 DOF 6 DOF 7 DOF 8 θDθCDD Partition Free Stiffness Matrix , K 1537878.79 11 (k/in) DOF 4 -6657.48DOF 5 439393.94DOF 6 DOF 80.00 DOF 4^ BLUE = FREE DOF θB 439393.94^ -6657.48 0.00 6657.48134.490.00 1757575.76439393.940.00^ 439393.94878787.886657.48^ DOF 5 DOF 6 DOF 8^ DθθCDC
=
=
K 11 (Kff)
=
Invert Free Stiffness Matrix , K11 (in/k) 0.0000010 DOF 4 0.0000751DOF 5 -0.0000001DOF 6 -0.0000005DOF 8 DOF 4 -0.0000001 -0.0000005^ 0.0000751^ -0.00015020.01858810.0000188^ -0.00000050.00001880.0000007^ -0.0001502-0.00000050.0000025^ DOF 5 DOF 6 DOF 8 Force Matrix at Free DOFs , Q Input Forces k (kip) PC-12 (kip) M-480.0000D (kipin) -12.0^ 0.0 0.0^ kipinkipkipin^ DOF 4 DOF 5 DOF 6^ θDθBCC Equations of Equilibrium^ -480.0^ kipin^ DOF 8^ θD d.) Unknown Displacements and Rotations at DOF Displacement Matrix at DOFs, Df (^) (in) -0.000658 (^) rad DOF 4 θB -0.150958 0.000017 0.000589 (^) inradrad DOF 5 DOF 6 DOF 8 DθθCDC Global Displacement Matrix (D) (in) Dx1 Dy1 Dx2 0.0000000.0000000.000000 inradin DOF 1 DOF 2 DOF 3 DθDAAB Dy2 Dx3 Dx3 -0.000658-0.1509580.000017 radinrad DOF 4 DOF 5 DOF 6 θDθBCC Dx4 Dy4 0.0000000.000589 inrad DOF 7 DOF 8 DθDD e.) End Member Forces and Moments Beam End Forces 0.000000 0.000000 0.000000 D^ Q = kD (kip,kipin)** -217.00-2.472.47^ DOF 1 DOF 2 DOF 3 (^) -0.000658-0.1509580.000000 D^ Q = kD (kip,kipin)** 434.00-5.885.88 DOF 3 DOF 4 DOF 5^ -0.1509580.0000170.000000 D^ Q = kD (kip,kipin)** -731.00-6.126.12 DOF 5 DOF 6 DOF 7 j.) Flexural Stresses^ -0.000658^ -434.00^ DOF 4^ 0.000017^ 731.00^ DOF 6^ 0.000589^ -480.00^ DOF 8 S = 2I/d m ftNN -217.000192.308-1.128 inkinksi^3 S = 2I/dmftNN 434.000192.312.257 inkinksi^3 S = 2I/dmftNN -731.000192.31-3.801 inkinksi^3 fb m ftFNF -434.000-2.2571.128 ksikinksi fbmftFNF 731.000-2.2573.801 ksikinksi fbmftFNF -480.000-2.4963.801 ksik*inksi Stresses Do Not Exceed Maximum of 20-ksi^ fbF^ 2.257^ ksi^ fbF^ -3.801^ ksi^ fbF^ 2.496^ ksi
K 11 x (Df )
Member CD
Member CD
(Df ) =
Member AB Member BC
Member AB Member BC
(Qk ) = (Qk ) =
K 11 -1^ (Kff-1) =