Wave-Particle Duality and Electron Diffraction: A Physics Problem Set - Prof. Liu, Assignments of Physical Chemistry

Homework Assignment 1 - Spring 2024

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2023/2024

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(1) Let y(x, t) = Acos(kx ωt). Show that
2y
∂x2=k2y, 2y
∂t2=ω2y(1)
(2) When a clean surface of silver is irradiated with light of wavelength 230nm,
the kinetic energy of the ejected electron is found to be 0.805eV. Calculate the work
function and the threshold frequency of silver.
(3) Express the Planck distribution law
ρν(T)dν=8πh
c3
ν3dν
ehν/kBT1(2)
in terms of λand dλby using the relationship λν =c
(4) (Advanced Problem)
In this question you will calculate the theoretical and “experimental” de Broglie
wavelengths using a phenomenon known as the “Bragg reflection”
The de Broglie relationship is as follows:
λ=h
p(3)
where λis the wavelength, his Plank’s constant and pis momentum. In an electron
diffraction tube (Figure (1)), the electron are accelerated by applying a voltage (V)
(also referred to as a potential difference), which increases their kinetic energy (K).
When Vis small,
K=eV =p2
2m(4)
where eis the elementary electric charge and mis mass of an electron. The λmay
then be solved for to give,
λ=h
2meV (5)
(i) Using the above equations, calculate the theoretical wavelength λof an elec-
tron which is accelerated through an electron diffraction tube of the 2500V voltage.
(ii) You will now use mock data to determine the experimental wavelength of an
electron based upon the diffraction pattern seen in the diffraction tube. In Figure
(2), you will notice how a beam of electrons is focused on graphite (indicated in
Figure (2) with a yellow square). Graphite is a crystal which contains two lattice
planes. The atoms in each plane reflect incoming radiation and have a distance d
between them, as shown in Figure () (d1=123pm and d2=213pm). These lattice
1
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(1) Let y(x, t) = A cos(kx − ωt). Show that ∂^2 y ∂x^2 =^ −k

(^2) y, ∂^2 y ∂t^2 =^ −ω

(^2) y (1)

(2) When a clean surface of silver is irradiated with light of wavelength 230nm, the kinetic energy of the ejected electron is found to be 0.805eV. Calculate the work function and the threshold frequency of silver. (3) Express the Planck distribution law

ρν (T )dν =^8 cπh 3 ν

(^3) dν ehν/kBT^ − 1 (2)

in terms of λ and dλ by using the relationship λν = c (4) (Advanced Problem) In this question you will calculate the theoretical and “experimental” de Broglie wavelengths using a phenomenon known as the “Bragg reflection” The de Broglie relationship is as follows:

λ = hp (3)

where λ is the wavelength, h is Plank’s constant and p is momentum. In an electron diffraction tube (Figure (1)), the electron are accelerated by applying a voltage (V ) (also referred to as a potential difference), which increases their kinetic energy (K). When V is small, K = eV = p

2 2 m (4) where e is the elementary electric charge and m is mass of an electron. The λ may then be solved for to give, λ = √ 2 meVh (5) (i) Using the above equations, calculate the theoretical wavelength λ of an elec- tron which is accelerated through an electron diffraction tube of the 2500V voltage. (ii) You will now use mock data to determine the experimental wavelength of an electron based upon the diffraction pattern seen in the diffraction tube. In Figure (2), you will notice how a beam of electrons is focused on graphite (indicated in Figure (2) with a yellow square). Graphite is a crystal which contains two lattice planes. The atoms in each plane reflect incoming radiation and have a distance d between them, as shown in Figure () (d 1 =123pm and d 2 =213pm). These lattice

FIG. 1. Particle vs. Wave Models of Diffraction. (a) represents the continuous inten- sity distribution seen on a wall when electrons act like a particle while (b) depicts the constructive interference seen when electron are diffracted and act as a wave.

FIG. 2. Electron Diffraction Tube. Example schematic of an electron diffraction tube, where θ is the “Bragg Angle” and D 1 and D 2 are innter (1) and outer (2) diameters of the diffraction

planes are also referred to as Bragg planes and function as a grating used to scatter the wave. Hence, we can use the formula for Bragg diffraction along with trigonometry to reaching the following relationship:

D = 2L tan(2θ) (6) 2 d sin(θ) = nλ (7) sin(θ 1 ) = D^ sin^

( D 1

2 D

4 L (8)

sin(θ 2 ) = D^ sin^

( D 2

2 D

4 L (9)

λ 1 = 2d 1 sin(θ 1 ) (10) λ 2 = 2d 2 sin(θ 2 ) (11)

If you know that the distance to the fluorescent screen (L) is 130mm, the diam-