Lab 6 Work and Conservation of Energy | PHY250L | Spring Constant & Graphs, Exams of Physics

Complete Lab 6 report covering Work, Potential Energy, and Kinetic Energy. Includes Force vs. Distance graphs, spring constant (k) calculations, and work done by a spring (W=1/2kx 2 ). 100% complete with discussion questions. Work and Energy, Potential Energy, Kinetic Energy, Spring Constant, PHY250L, Physics Lab Report, Conservation of Energy, Hooke's Law

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Lab 3 Newton’s Laws PHY250L
The ultimate study guide
Student Name:
Kit Code (located on the lid of your lab kit):
Pre-Lab Questions
Use the free body diagram of the pulley (Figure 5)
to answer the Pre-Lab Questions.
1. Draw free body diagrams for M and M.
Insert photo of diagram with your name
clearly visible in the background:
2. Apply Newtons Second Law to write the equations for M and M. You should get
two equations with tension in the string, weight for each mass and accelerations for
each mass (a and a).
M1, T M1g = M1a1, T = M1(g + a1) ----------------(1), Equation for M2, M2g T = M2a2,
T = M2(g-a2) -----------------(2). Equating both equations for T, and a1 = a2 = a, we get
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Student Name: Kit Code (located on the lid of your lab kit):

Pre-Lab Questions

Use the free body diagram of the pulley (Figure 5) to answer the Pre-Lab Questions.

  1. Draw free body diagrams for M₁ and M₂.

Insert photo of diagram with your name clearly visible in the background:

  1. Apply Newtons Second Law to write the equations for M₁ and M₂. You should get two equations with tension in the string, weight for each mass and accelerations for each mass (a₁ and a₂). ” M1, T – M1g = M1a1, T = M1(g + a1) ----------------(1), Equation for M2, M2g – T = M2a2, T = M2(g-a2) -----------------(2). Equating both equations for T, and a1 = a2 = a, we get

M1(g+a) = M2(g-a) M1g + M1a = M2g – M2a a(M1 + M2) = g(M2 – M1) a = g(M2 – M1)/(M1 + M2)

  1. Equation for M1, TM1g = M1a1, T = M1(g + a1) ----------------(1), Equation for M2, M2gT = M2a2, T = M2(g-a2) -----------------(2). Equating both equations for T, and a1 = a2 = a, we get M1(g+a) = M2(g-a) M1g + M1a = M2gM2a a(M1 + M2) = g(M2M1) a = g(M2M1)/(M1 + M2) T=m1a +m1g
  2. Post-Lab Question 2 results in two equations with three unknowns! A third equation is required to solve the system. What is the third equation? ” S Fx = m ax mg sin(q) = m ax ax = g sin(q) Plugging in g = 9.8 and q = 25 degrees:

Experiment 1: Graphing Linear Motion ” “ Table 1: Motion of Water Observations

Motion ” “ Observations

a ” Water rises up the back of the cup (towards you) “ b ” No movement of water “ c ”^ Water rises up left side of the cup when turning right, and up right side of the cup when turning left (i.e water rises in opposite of direction of turn) “ d ” Water rises in front of cup (away from you)

Table 2: Observations After Flicking Notecard Off of Cup ” “ Trial ” “ Observations ” “ 1 ” Card flies off of cup, washer goes in the cup “ 2 ” Card goes up in the air & off of cup, washer goes on the floor “ 3 ” Card flies off of cup, washer goes in the cup “ 4 ” Card flies off of cup, washer goes in the cup “ 5 ” Card flies off of cup, washer goes in the cup

Post-Lab Questions

1.Explain how your observations of the water and washer demonstrate Newtons law of inertia. ” The washer is at rest while it sits on top of the card and glass. When you flick the card out from under the washer, gravity (an outside force) is enabled to act upon the washer and pull it into the glass. When the washer drops, it is stopped by the bottom of the glass.

  1. Draw a free body diagram of your containers of water from the situation in Part 1 Step 4d. Draw arrows for the force of gravity, the normal force (your hand pushing up on the container), and the stopping force (your hand accelerating the container as you stop). What is the direction of the waters acceleration?

Insert photo of diagram with your name clearly visible in the background:

Experiment 2: Newtons Third Law and Force Pairs

Table 3: Force on Stationary Springs ” “ Force on Stationary 10 N Spring Scale (N) ” Force on Stationary 10 N Spring Scale (N) 5 N “ Force on Stationary 5N Spring Scale (N) ” Force on Stationary 5N Spring Scale (N) 5 N

Table 4: Spring Scale Force Data

Suspension Set Up ” “ Force (N) on 10 N Spring Scale

Force (N) on 5 N Spring Scale ” “ 0.5 kg Mass on 10 N Spring Scale ” Spring Scale 5 N 5 N “ 0.5 kg Mass with String on 10 N Spring Scale ”^ 5N “ 0.5 kg mass, string and 5 N Spring Scale on 10 N spring scale

10 N 0.4N 5 N

0.5 kg mass, string and 5 N Spring Scale on 10 N spring scale on Pulley

10 N 0 N 5 N

Post-Lab Questions

  1. How did the magnitude of the forces on both spring scales compare after you moved the 10 N spring scale?

Motion Data Mass of 15 Washers(kg) 40 g Average Mass of Washer (kg) 2.67 g Height (m): 25” Trial Time(s)2.

  1. How did the magnitude of the forces on both spring scales compare after you move the 5 N spring scale?

  2. Use Newtons Third Law to explain your observations in Questions 1 and 2.

  3. Compare the force on the 10 N spring scale when it was directly attached to the 0. kg mass and when there was a string between them.

Experiment 3: Newtons Third Law and Force Pairs

Table 5: Motion Data ” “ Mass of 15 Washers (kg)

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Average of Mass of Washer (kg)

Click here to enter text.

Procedure 1 ” “ Height (m): ”Click here to enter text. “ Trial ” “ Time(s) ” “ 1 ” 0. “ 2 ” 0. “ 3 ” 0. “ 4 ” 0. “ 5 ” 0. “ Average ” 0. “ Average Acceleration (m/s²) ” 0. “ Procedure 2

Height (m): ”Click here to enter text. “ Trial ” “ Time(s) ” “ 1 ” 1. “ 2 ” 2. “ 3 ” 1. “ 4 ” 0. “ 5 ” 1. “ Average ” 1. “ Average Acceleration (m/s²) ” Click here to enter text.

Post-Lab Questions

1.Draw a free body diagram for M₁ and M₂ in Procedure 2. Draw force arrows for the force due to gravity acting on both masses (F₁and F₂) and the force of tension(F). Also draw arrows indicating the direction of acceleration, a****.

Insert photo of diagram with your name clearly visible in the background:

6.Using the theoretical acceleration found in Question 4 for Procedure 1, find the velocity of the block as a function of time by integration. ” Click here to enter text.