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Logarithmic Function, Basic Logarithmic Equations, Exponential Function, Logarithm in Base, Increasing, Positive Value, Asymptote for the Function, One to One, Two Particular, Natural Log Function are the key points of this lecture.
Typology: Study notes
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Objectives : 1. To graph a logarithmic function;
Because the exponential function is one-to-one, then
ܽൌ ݕ ௫^ ݃ ݈ൌ ݔ ↔ (^) ݕ.
The expression ݈ ݃ (^) ݕ is called “the logarithm in base a of y ”.
If a > 0 with ്ܽ 1 , then the logarithmic function with the base a is:
݂ : ሺ0, ∞ሻ → ࡾ,݂ ݃ ݈ൌ ሻݔሺ (^) .ݔ
Graphs of logarithmic functions: a. If a > 1 b. If 0 < a < 1
Properties of the graphs:
-4 -3 -2 -1 1 2 3 4 5 6 7 8 9
1
2
3
4
5
x
y
(1,0)
-4 -3 -2 -1 1 2 3 4 5 6 7 8 9
1
2
3
4
5
6
7
8
9
x
y
(1,0)
Two particular exponential functions are when a = e (the Euler’s number), or a = 10 : ݂: ሺ0, ∞ሻ → ࡾ,݂ ݃ ݈ൌ ሻݔሺ (^) ݔൌ lnݔ the natural log function; ݂: ሺ0, ∞ሻ → ࡾ,݂ ݃ ݈ൌ ሻݔሺ (^) ଵ ݔൌ logݔ the common log function.
Ex 1: ݈ ݃ (^) ହ 25 ൌ 2 ↔ 5 ଶ^ ൌ 25.
Ex 2: Find the domain of the function ݂ ݃ ݈ൌ ሻݔሺ (^) ଷ ሺ2 ݔ 1ሻ. To find the domain of the function, we set the inner expression to be positive, and then solve it:
2 ݔ 1 0 → ݔ െ ଵ ଶ. The domain is ቀെ ଵ ଶ , ∞ቁ.
Ex 3: Solve the equation: ݈ ݃ (^) ଶ ሺ2 ݔ 1ሻ ൌ 3.
We rewrite as exponential expression and solve it: ݈ ݃ (^) ଶ ሺ2 ݔ 1ሻ ൌ 3 ↔ 2 ݔ 1 ൌ 2ଷ^ → ݔ ൌ ଶ.
Ex 4: Solve the equation: ݁2 ଷ௫^ ൌ 8.
We have: ݁ ଷ௫^ ൌ 4 ↔ 3 ݔൌ 4 ݈݊→ ݔ ൌ ସ ଷ.