Partial preview of the text
Download Numerical Methods Study Notes with Solved Examples and more Study notes Numerical Methods in Engineering in PDF only on Docsity!
Moswhe-3(Fintie Dis ai ate cduhe. SUN aie! Thterposttton s system of betoeen froces of ‘ArdBng 4 Correyondiig DAT & XOX intewolaty 7 OH) finding 4 outgtle the afven Tange Jextrapdation, lL. Brsasd aE ye Yog Hs Demet operatorfs) : Af(z)= #(xth)~ -() ) Backward at8l operator (ep: VElW) £()-F@-h) 3) Centra ast operator (g) fr yet) tay f( (4h) f(x: -tlek) usher operator) eta)= HOt) Et t= S(utth) +: ENW= flxtnh ————e qnvewse operatdy E aefind by ¢“fly =flx-h) —_——_—"—=_. eS a Relaktors blew operat’ {) aa ~ appet) &f oe (E- Dade EF ta)- 100) ey 80 = totb- Ha) (e-') 4a) p$(4) €-\eb , aay he £°| : ) feb (“N= a cts) pide PAY, PM te Wn * sa JT Yo ap he CF 0 foe ie} a (os - ar May reset) = ays a ¢+ Uo 414 Dosen | A ta) g Woutey dretRbutfon ofa Buta now a fat curdsio pa \ o\ | 0.2 | 0:6 0,8 | \ \ow | Wel | 48 sue | HA dtgtance fom eunface, sovelor?ty Cmm|s) Use appro method 4p obtdh voloofty at ete 6! = Lagrarg e's Inter poatfon Forma - 4{ 0= Y (HA) (R-22). CHF) J (tHe) 2D CAD. — (oan) (0-1) (%0-%,) — Cx,-%n) O-%e) (CH -WE - co) : y [2 ho) CRAY Cer 25) Cx-ate) + * aX) (HA) CMD Crp) Se v= 2) Noe RING + 18i/ (co (rogtta (wre) ored(or edd i (b-1-0:2)C 01-06) (0-1-08) ' oad (cowreatted) a.yg/(eo) C-0-2(1-09) | ; b-g-or)(oc-o900477 (o8- o)(oee 1)+(0.8-0 VQ= ~es4r ~\-3165 4 S43. 8294 edt = 6.1826 ——— af Ela (xNxw)(90 347 4 Su(r-S)2-$4) Ke Sd 3 4 p-3e + Ie 1 one 5(ox* exe ame 4b ySt- ® soxti5a'] 10 = ils -28x° xs, 3x(x-e), 2 xloDlrs) WW= 2 Cex DRY , ately) ed (4.2 < fr : rat (eV 60 A al ea (x-S) «3 a Wes x 25, = a(x- (x 7 tx) vat 3 esx 54) ee pat yh 2 Coabic) (X- Baal p ho =O ry Cady Eon 4 Sous =a a : + 49 (= shor 62) wi = wt ‘ GSogés “ORY | : z ud ay 2 L-BHATATD 4 goieun'xB0% — a 62 4, sa) a \ r \ at ya 5 2/9 eS aot if e ‘ + re atl pe) Oy aS : — " epi gale exv(s ie a x(2 cat) oY.) : =| ak xP ve usi(- axa. t (a-y) (a-s) nis + (8-H) E-) B- Ug x nxsit URBRIS + AKBAL = HYG ea ye gt (IS“DXSAt US UCI) AUF 4 (1S) Cts sCs-D Gena To Lt [5 | use newton stud ~ Vp) | 24s STB 5 \4 q [1385 } dSference. y 4 [xo.m) Le, x1 922) Covent 2s) Creates) “4 yey 4 33-1245 x04 28-08) 107 84 AY] ore se ==) o- CY) red | 5-4 a 3 5-33-88 | 22(29- 10] 99-0 | oC) one eae On 75 “ Cl 5 44) 3 = ural 8 ees 5-0 pes = 441. Bigs | st be ) Its “ Poe ax ote embers tes Fatecaectety) Y= Yo + (a- ate, 4)* (x-%eJAA) [Ho.m, 8a] (-ASORIOC ar, 4, f4.33) AML AYO -x2) 9%) [Ae, %, Ker Bs, tale xt y 3G «a (a ne) CHAN XHI()( ry) (et) HNO & 9 jer 1 HCHO wey(eed Garba (a S94) 9-1 (x sxe) (22x) =1245 — YOu =e = AEST EMC + FON PSEA Lee Laacioat 8x) & | = -34) YON Kt Qut + | ie ; L gon aire tO% a 3 256k 2 meel4uertOor +5) aot rsa ag) ee | qe ase (ty) C404) + (eer) (er Cod) 4 eyo) (00) + = Geet) a) IDO) Yass eee +5648) q bpbickb AL Uy Nn (ate Fae’ + 64) Y= (24S @ “4O4C elorau(nesery >| ( ) RE | Se crap le pont e+ (CUSTER ik 2, 3th FINr “a ton & 56% (« HAY eQal pe pty HOU + AUCH MTOM olox=8%) (ae : © 3 u She qoxtesoxt dati “\8X Livi i J=> Myot LATIN EA TOR AN : 2 arato aye) + (4449+ 33" ye 5 aa feuon ag 35S) ‘ er (-s)a 3a" i; A 7 | a 5+ (4x + i fi 1 Q Find the thd dtuedel affference with arguments age of © twee | , 3 X-.deH4, B podti: 4? 3.4256 £9) = q-aA= Al 49) = 10% 2-to= 40 Aue 450-8 tse Lay pasted = ois £(0:8125) = - 0303 4 0 s Thus wot Ite plu 0812S and 0-545 Lek ke = or Ps tos _ 9.9 y3ts a. t(0-24345) = +H -0:(85 Ake Ry7 , 4a Rg Yo Yo ‘tho > Ye Ho z\ Uttho 0 YY% te gr Ayo Ag Re 1 No Mo € ae oh Sole mo 2 hL? aa + & ux x {o Wo uila+ 362 | = G48 tHe 1365 \o 2365, ee \o \° he wury 360) = Adit . 7H (XO “a uly oUN\ a Lv method a%=B ee pet A= nes) ab ©) tle : Un ‘ — Joy V0 O rr hy et ane J, die! 0 0 Uy Upper 5 mats goive PrHLU? yo get Joy ts: --- Wy value. gupatoke @ fr O LUX=B L(ux)=8 Beaks tO Hence LN=8 2D coive thea — you got ay cae hon, Solve UX 4 7 yor get re a \ . : 2 co ° Uy Mir Us = 10 mice Cee _ @ oto hy eke ° 2 : Uy Un Ug UNS ge Gude Sodje, yg t03 reac ae Joi Uy gir tanta Asitgttaiss4 L wee S 93 (rt Uby =) Uday = 2 tye Lo Sox Sn Unt n= Me 
