Parameters - Electrical Engineering - Exam, Exams of Electrical Engineering

Main points of this exam paper are: Parameters, Notation, Reference, Impedance, Spherical Shell, Material Centered, Uniform Charge Density

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EECS 117A, Midterm #2, Fall 1998
EECS 117A, Fall 1998
Midterm #2
Professor S.E. Schwarz
Problem #1 (40 points)
We want the four S-parameters for the block shown above. Use the notation shown. The reference
impedance is 50 ohms.
(a) Find S11
(b) Find S22
(c) Find S21
(d) Find S12
Problem #2 (30 points)
Consider a thin, rigid, spherical shell of material centered at the origin. The shell occupies the space
between r = a and r = a+h, and you should assume h << a. The shell has a uniform charge density rho,
and it rotates around the polar axis (or z-axis) with angular velocity omega radians/sec. Find the
magnitude |H| of the magnetic field at the origin.
(If you happen to get an integral that you can't evaluate, just leave it in the form of an integral.)
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EECS 117A, Midterm #2, Fall 1998

EECS 117A, Fall 1998

Midterm

Professor S.E. Schwarz

Problem #1 (40 points)

We want the four S-parameters for the block shown above. Use the notation shown. The reference impedance is 50 ohms.

(a) Find S (^11)

(b) Find S 22

(c) Find S 21

(d) Find S 12

Problem #2 (30 points)

Consider a thin, rigid, spherical shell of material centered at the origin. The shell occupies the space between r = a and r = a+h, and you should assume h << a. The shell has a uniform charge density rho , and it rotates around the polar axis (or z-axis) with angular velocity omega radians/sec. Find the magnitude | H | of the magnetic field at the origin. (If you happen to get an integral that you can't evaluate, just leave it in the form of an integral.)

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EECS 117A, Midterm #2, Fall 1998

Problem #3 (30 points)

The boundary between two electrically conductive materials lies in the x = 0 plane. Material 1 has epsilon 1 , sigma E1, mu 1 and material 2 has epsilon 2 , sigma E2, mu 2. Let epsilon 2 = 2 epsilon 1 , sigma E2 =

3 sigma E1 , mu 2 = 5 mu 1. There is an electrostatic field E 1 in Region 1, which makes an angle of 45o

with the normal to the interface, as shown. Find theta 2 , the angle between the electrostatic field and the

normal on the right side of the boundary.

Answer: theta = ____________ degrees

Posted by HKN (Electrical Engineering and Computer Science Honor Society) University of California at Berkeley If you have any questions about these online exams please contact mailto:[email protected]

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