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A physics project focused on analyzing payload motion under various conditions. It includes initial calculations for vertical and horizontal motion, considering factors like gravity and initial velocity. The project explores modified scenarios, such as accounting for wind speed and launch angles, to determine the payload's trajectory and landing point. A step-by-step approach to solving kinematics problems, incorporating diagrams and equations to visualize and calculate the payload's motion. It also includes references to external sources for weather data, enhancing the project's real-world applicability and accuracy. This project is designed to enhance understanding of physics principles through practical application and problem-solving.
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Instructions: Respond to the prompts in the tables below and replace the text in brackets.
y=yo+vyot+1/2ayt2 x=vxot 2650=0+1/2(9.8)t2 x=111.76m/s(23.26s) = 2599.53 m 2650=4.9t t=(2650/4.9)1/2 = 23.26 s 250mi/hr1609m/1mi1hr/60min*1min/60sec = 111. m/s
What we know: Initial velocity is 0. Rate of gravity is 9.8m/s. Plane height is 2650m. What we need to find: Vertical motion (Initial/Final Velocity) and Velocity of payload. We will use this equation to find the vertical displacement y = yo + voyt + 1/2a*t^ Y= Height of plane(2650)// yo=initial height of plane(0)// vyo intial plane velocity(1/2)// ay= acceleration of payload as it is dropped (9.8m/s^2)//. Solve for t = 23.26s Create a diagram describing the horizontal and vertical motion of the payload. Remember that your diagram should visually represent the motion of the payload. Provide your calculations, including all relevant steps are included and your units are labeled. Describe the components of the kinematics equations used in your initial calculations below.
In this scenario I will be using Houston, TX as my dropoff location. Currently for 7/13/2023 the wind speeds are 9mph according to localconditions.com. First off we need to convert 9mph to m/s. We will do 9(0.44704 m/s)= 4.02 m/s (approximately). Afterwards subract 4.02 m/s from the original velocity of 111.76 m/s and it equals 107.74m/s. With the new velocity of 107.74m/s we multiply it by the time the payload takes to fall which would be 107.76m/s(23.26)= 2,506.03m. This would be the new distance that the payload will need to be dropped off.
Create a diagram showing the first modified scenario. Then adjust your initial calculations to incorporate the changing variables from the scenario and describe how these changed variables affect your calculations.
Reference Houston, TX Past Weather For Last 30 days - LocalConditions.com. (n.d.). Www.localconditions.com. Retrieved July 13, 2023, from https://www.localconditions.com/weather-houston- texas/77001/past.php