6/22/2017 B
Equation Stoichiometry
Chemistry 110
1] Given the equation: 2C8H18 + 25 O2 ----> 16CO2 + 18H2O
a. How many moles of oxygen gas are required to make 8.33 moles of carbon dioxide?
8.33 moles CO2 X 25mol O2
16mol CO2 = 13.0 moles O2
Answer ___________________
b. How many moles of C8H18 must be used to produce 1.99 grams of water
1.99 mg H2O X 1mol H2O
18.0g X
2mol C8H18
18mol H2O = 1.23 x 10-2 mol C8H18
Answer ___________________
c. If the reaction produces 5.3 mg of carbon dioxide how many grams of water are produced?
5.3mg CO2 X 10-3g
1mg X
1mol CO2
44.0g CO2 X 18mol H2O
16mol CO2 X
18.0g H2O
1mol H2O =
2.4 x 10-3 g H2O
Answer ___________________
d. How many grams of oxygen are needed to react with 7.22 x 10 24 molecules of C8H18?
7.22 x 1024molec. C8H18 X 1mol C8H18
6.02x1023molec X
25mol O2
2mol C8H18 X 32.0g O2
1mol O2 =
4.80 x 103g O2
Answer ___________________
2] How many grams of aluminum oxide are formed when 25.0 grams of Aluminum are reacted with oxygen gas?
a. Write the balanced equation
4 Al + 3 O2 ---> 2 Al2O3
b. Calculate the number of grams of aluminum oxide produced
25.0g Al X 1mol Al
27.0g Al X
1mol Al2O3
2mol Al X 102.0g Al2O3
1mol Al2O3 = 47.2g Al2O3
Answer ___________________
3] A sample of TiCl4 is reacted with Titanium metal to produce Titanium (III) chloride
a. Write the balanced equation
3 TiCl4 + Ti ---> 4 TiCl3
b. How many kg of Titanium (III) chloride was produced from 52 kg of Titanium (IV) chloride?
52 Kg TiCl4 X 103g
1Kg X
1mol TiCl4
189.9g TiCl4 X .4mol TiCl3
3mol TiCl4 X
154.4g TiCl3
1mol TiCl3 X 10-3Kg
1g =
56.4 Kg TiCl3
Answer ___________________
