Problem Solving using Polya's Four-step Strategy, Assignments of Mathematics

Problem solving with step-by-step solution

Typology: Assignments

2021/2022

Uploaded on 11/05/2022

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Problem Solving
Question:
Andrew has some magic cards to trade. Ian has 2 more than 2 times the number
of magic cards Andrew has. Patrick has 2 less than Ian. Ken has 4 less than 2 times the
number of magic cards Patrick has. Patrick has 8 magic cards. How many magic cards
does Andrew have to trade?
Polya’s Four-Step Problem Solving Strategy
1. Understand the problem.
We are looking the total number of cards Andrew (x) must have to trade. Given
that Ian has 2 more than 2 times the number of cards of Andrew (2x+2). Then, Patrick
has 2 less than the numbers of card of Ian ([2x+2] 2), or simplify to be 2x. While Ken
has 4 less than 2 times the number of cards of Patrick (2[2x] 4). If Patrick has 8 cards,
how many cards does Andrew have. Let x be the number of Andrew’s magic cards.
2. Devise a plan.
Given:
Let x be the total number of magic cards Andrew's have
Ian= 2x+2
Patrick= (2x+2) 2= 2x
Ken= 2(2x) 4
If Patrick has 8 magic cards, we can use this in the formula since number of Patrick's
cards is 2 times the number (2x). Let’s use this formula, 2x = 8, to get the total number of
magic cards of Andrew.
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Problem SolvingQuestion: Andrew has some magic cards to trade. Ian has 2 more than 2 times the number of magic cards Andrew has. Patrick has 2 less than Ian. Ken has 4 less than 2 times the number of magic cards Patrick has. Patrick has 8 magic cards. How many magic cards does Andrew have to trade? ▪ Polya’s Four-Step Problem Solving Strategy

1. Understand the problem. We are looking the total number of cards Andrew (x) must have to trade. Given that Ian has 2 more than 2 times the number of cards of Andrew (2x+2). Then, Patrick has 2 less than the numbers of card of Ian ([2x+2] – 2) , or simplify to be 2x. While Ken has 4 less than 2 times the number of cards of Patrick (2[2x] – 4). If Patrick has 8 cards, how many cards does Andrew have. Let x be the number of Andrew’s magic cards. 2. Devise a plan. Given: Let x be the total number of magic cards Andrew's have Ian= 2x+ Patrick= (2x+2) – 2= 2x Ken= 2(2x) – 4 If Patrick has 8 magic cards, we can use this in the formula since number of Patrick's cards is 2 times the number (2x). Let’s use this formula, 2x = 8 , to get the total number of magic cards of Andrew.

3. Carry out the plan. 2x = 8 2 2 x = 4 Therefore, the total number of Andrew’s magic cards are 4 magic cards for his trading**.

  1. Look back. Checking** : Substitution Ian’s magic cards = 2x + 2 = 2(4) + 2 = 8 + 2 Ian’s magic cards = 10 magic cards Patrick’s magic cards = (2x + 2) – 2 = (2(4) +2) – 2 = (8 + 2) – 2 = 10 – 2 Patrick’s magic cards = 8 magic cards Ken’s magic cards = ((2x + 2) – 2 ) – 4 = ((2(4) + 2) – 2) – 4