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Problem solving with step-by-step solution
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Problem Solving ▪ Question: Andrew has some magic cards to trade. Ian has 2 more than 2 times the number of magic cards Andrew has. Patrick has 2 less than Ian. Ken has 4 less than 2 times the number of magic cards Patrick has. Patrick has 8 magic cards. How many magic cards does Andrew have to trade? ▪ Polya’s Four-Step Problem Solving Strategy
1. Understand the problem. We are looking the total number of cards Andrew (x) must have to trade. Given that Ian has 2 more than 2 times the number of cards of Andrew (2x+2). Then, Patrick has 2 less than the numbers of card of Ian ([2x+2] – 2) , or simplify to be 2x. While Ken has 4 less than 2 times the number of cards of Patrick (2[2x] – 4). If Patrick has 8 cards, how many cards does Andrew have. Let x be the number of Andrew’s magic cards. 2. Devise a plan. Given: Let x be the total number of magic cards Andrew's have Ian= 2x+ Patrick= (2x+2) – 2= 2x Ken= 2(2x) – 4 If Patrick has 8 magic cards, we can use this in the formula since number of Patrick's cards is 2 times the number (2x). Let’s use this formula, 2x = 8 , to get the total number of magic cards of Andrew.
3. Carry out the plan. 2x = 8 2 2 x = 4 Therefore, the total number of Andrew’s magic cards are 4 magic cards for his trading**.