Rotational Inertia - Principle of Physics - Lecture Slides, Slides of Physics

Principle of Physics course includes many basic theories and concepts we study in throughout Physics. Other title of the course is Core Physics. Keywords in here are: Rotational Inertia, Linear Motion, Rotational Inertia, Conservation of Angular Momentum, Angular Momentum, Riding a Bike, Moment of Inertia

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2013/2014

Uploaded on 01/31/2014

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Rotational Inertia
I. Rotational Inertia
A. Newton’s 2nd law: F = ma
1) Rewrite for Rotational Motion = m
2) But, should we really use m (mass)?
3) In Linear motion,
a) Mass = measure of inertia
b) Mass = resistance to change in motion
4) In Rotational motion, mass and how far from center (r) determine inertia
a) Rotational Inertia = Moment of Inertia = resistance to change in
rotational motion = I
b) I = mr2(Units = kg x m2) for a point mass rotating around center
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Rotational Inertia

I.^

Rotational InertiaA.^

Newton’s 2

nd^ law: F = ma

1)^

Rewrite for Rotational Motion

= m

2)^

But, should we really use m (mass)? 3)^

In Linear motion,a)^

Mass = measure of inertia b)^

Mass = resistance to change in motion

4)^

In Rotational motion, mass and how far from center (r) determine inertiaa)^

Rotational Inertia = Moment of Inertia = resistance to change inrotational motion = I b)^

I = mr

2 (Units = kg x m

2 ) for a point mass rotating around center

5)^

I depends on shape for solid objects 6)^

I replaces m for rotational motion ^

^ = I

^

is Newton’s 2

nd^ Law

for Rotational Motion

B.^

Example Calculation: Merry-go-round I^ M^

= 800 kgm

2 , r = 2 m, 40 kg child at edge

I^ ?T

required to cause

^

= 0.05 rad/s

τ I

α^

2

2

2

2

2

kgm

m

kg

kgm

mr

kgm

I

I

I^

C M T^

48Nm

/s

48kgm

s

)(0.05rad/

(960kgm

τ^

2 2

2

2

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4)^

Example Calculation: I

(arms out) = 1.2 kgm 1

2 , I

(arms in) = 0.5 kgm 2

2

w^1

= 1 rev/s

w^2

5)^

Demo: student on a rotating chair 6)^

Other Examples of Conservation of Angular Momentum

2 2 1 1 2 1

ωI

ωI

L

L^

^

rev/s

kgm

rev/s)

kgm

ωI I

ω^

2 2

(^112)

2

Kepler’s 2

nd^ Law: equal areas in equal times

L = mvr

v r ω rω v^

^

mvr v r ) (mr Iω L^

2

L^1

= L

2

mv

r^11

= mv

r^22

III.

Everyday ApplicationsA.

Direction of

^

and L

1)^

p^ is a vector with the same direction as

v

2)^

L^ is a vector with the direction determined by

3)^

Right-hand rule establishes direction of

^

and

L

B.^

Riding a Bike ^

^ is applied to wheel to make it turn 2)^

L^ is horizontal for the motion of the turning wheel 3)^

To tip over the bike,

L^1

must be changed by another torque

4)^

That torque will be gravity working on C.O.M. of the rider/bikea)^

Axis of rotation is the line on the ground of bike’s path b)^

When upright the force is in line with the axis, so

^ = 0 (l = 0)

c)^

Conservation of momentum keeps the bike balanced d)^

When tilted,

L^2

is forward or back along the road axis

i.^

Standing still, bike falls over ii.^

Moving,

L^1

+^

L^2

=^

L

bike changes direction

iii.

Turn the wheel slightly to compensate and you stay up

e)^

Angular momentum of a moving bike makes it easier to balance