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The concept of sampling distributions, the difference between parameters and sample statistics, and the properties of sampling distributions. It covers the mean and standard deviation of sampling distributions, the unbiasedness and minimum variance of sample statistics, and the central limit theorem. The document also includes examples and formulas.
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Parameter
vs.
Sample
Statistic
-^
-^
In
practice,
sample
statistics
are
used
to
estimate population
parameters.
Parameter
Statistic
Mean V^
i
μ
ˆ μ
2
(^2) ˆ
2
Variance St.
DeviationProportion
2
(^2) ˆ
σ
2 σ
ˆ p
p
ˆ σ
σ
Properties
of
Sampling
Distributions
If the
sampling
distribution
of
a
sample
statistic
has
a
mean
equal
to
the
population
parameter
the
statistic
is
intended
to
estimate,
the
statistic is said to be an
unbiased estimate
of the parameter
statistic
is
said
to
be
an
unbiased
estimate
of
the
parameter
If two
alternative
sample
statistics
are
both
unbiased,
the
one
with
the smaller standard deviation is preferred (
minimum variance
the
smaller
standard
deviation
is
preferred
( minimum
variance
Sampling
Distribution
of
The
mean
of the sampling
The standard deviation of the
The
mean
of
the
sampling
distribution
equals
the
mean
of
the
population
The
standard
deviation
of
the
sampling
distribution
(the
standard
error
of
the
mean)
equals:
μ
μ
=
=
) ( x E
x^
n
x
σ
σ
=
n
( )
1
1
⎞ ⎛ ⎞
⎛
( ) ( )
n
x
V x V
n n x n E x E
x
i
2 2 2 2 1 1
1
1
σ
σ
σ
μ
μ μ
=
=
× ⎞⎟ ⎛⎜ = ⎞⎟
=
=
⎞×⎟ ⎠ ⎛⎜ ⎝ = ⎞⎟ ⎠
∑ ∑
2
) (
i x^ i V
x E If
(^
)^
n n n x n V x V x
i
σ
σ
=
=
× ⎟ ⎠ ⎜ ⎝ = ⎟ ⎠
⎜ ⎝ =^
∑
Example
The
caffeine
content
(mg)
was
examined
for
a
random
sample
of
cups
of
black
coffee
dispensed
by
a
new
machine.
The
mean
and
standard deviation were 100 mg and 7.1 mg, respectively.standard
deviation
were
mg
and
mg,
respectively.
a)
Find
the
probability
that
the
average
caffeine
contents
will
be
b
d 101
b etween
and
mg.
b)
How
likely
are
you
to
get
on
those
cups
an
average
caffeine
content
higher
than
mg.
Central
Limit
Theorem
(CLT)
The
sampling
distribution
of
based
on
a
random
sample
of
n
observations,
will
be
approximately
normal,
i.e.
Sampling distributions of averages will become more like a normal
) / , ( ~ ) , ( ~ n
N
x
iid
x i
σ μ
σ μ
≈≈>
Sampling
distributions
of
averages
will
become
more
like
a
normal
distribution
as
n
increases
(regardless
of
the
shape
of
the
population
of
individual
measurements!!!).
Example
The
is
an
index
used
to
determine
the
ozone
level
in
a
city.
Depending
upon
the
reading,
it
might
not
be
safe
to
jog
or
even
to
go
outside.
Readings
in
the
range
are
considered
‘normal’,
are
‘unsatisfactory’,
means
‘condition
bad’,
and
means
‘conditions
very
bad’.
Suppose
that
an
industrial
region
has
an
average
reading
of
with
a
g^
g^
g
standard
deviation
of
a) If a sample of 50 days is measured what is the samplinga)
If
a
sample
of
days
is
measured
,^ what
is
the
sampling
distribution
of
a
sample
mean?
b)
Find
the
probability
that
for
a
sample
of
days,
the
average
reading
is
more
than
Example
a)
If
a
sample
of
days
is
measured,
what
is
the
sampling
distribution
of
a
sample
mean?
b) Find the probability that for a sample of 50 days the average IMECA
b)
Find
the
probability
that
for
a
sample
of
days
,^ the
average
reading
is
less
than