Transforming Reflection Coefficient: Input Impedance with Reflection, Exams of Electromagnetic Engineering

How to express the input impedance of a transmission line in terms of its reflection coefficient. complex arithmetic equations and provides an easier method to obtain the result. It is a valuable resource for students and professionals in the field of electrical engineering and communications.

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1/26/2005 The Reflection Coefficient Transformation.doc 1/7
Jim Stiles The Univ. of Kansas Dept. of EECS
The Reflection Coefficient
Transformation
The load at the end of some length of a transmission line (with
characteristic impedance
Z
0
) can be specified in terms of its
impedance
Z
L
or its reflection coefficient Γ
L
.
Note both values are complex, and either one completely
specifies the load—if you know one, you know the other!
0
0
0
1
and 1
LL
LL
LL
ZZ ZZ
ZZ
⎛⎞
−+Γ
Γ= = ⎜⎟
+−Γ
⎝⎠
Recall that we determined how a length of transmission line
transformed
the load
impedance
into an input
impedanc
e of a
(generally) different value:
0
,Z
β
A
in
Z
0
,Z
β
L
Z
pf3
pf4
pf5

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The Reflection Coefficient

Transformation

The load at the end of some length of a transmission line (with

characteristic impedanceZ 0 ) can be specified in terms of its

impedanceZ L or its reflection coefficient Γ L.

Note both values are complex, and either one completely specifies the load—if you know one , you know the other!

0 0 0

and 1

L L L L L L

Z Z

Z Z

Z Z

− ⎛^ + Γ ⎞

Recall that we determined how a length of transmission line transformed the load impedance into an input impedanc e of a (generally) different value:

Z 0 , β

A

Z 0 , β Z i n Z L

where:

0 0 0 0 0 0 cos sin cos sin tan tan

L in L L L

Z j Z

Z Z

Z j Z

Z j Z

Z

Z j Z

A A

A A

A

A

Q: Say we know the load in terms of its reflection coefficient.

How can we express the input impedance in terms its reflection

coefficient (call this Γin )?

A: Well, we could execute these three steps:

1. Convert Γ L toZ L:

0

L L L

Z Z

2. TransformZL down the line toZ in :

0 0 0

cos sin cos sin

L in L

Z j Z

Z Z

Z j Z

A A

A A

Z 0 , β Γ L

A

Z 0 , β Γ^ i n =^?

( ) ( ) ( ) ( )

0 0

2

j j j j L L in j j j j L L j L j j j L j L

Z e e e e

Z e e e e

e

e

e e

e

β β β β β β β β β β β β β

  • − + −
  • − + − −

− − −

A A A A A A A A A A A A A

Q: Hey! This result looks familiar. Haven’t we seen something

like this before?

A: Absolutely! Recall that we found that the reflection coefficient function Γ ( z) can be expressed as:

Γ (^) ( z (^) ) = Γ 0 e 2 γz

Now, for a lossless line, we know that γ = jβ, so that:

Γ (^) ( z (^) ) = Γ 0 e j^2 βz

Evaluating this function at the beginning of the line (i.e., at

z = zL − A ):

( ) 0 2 (^ ) 2 2 0

L L

j z L j z j

z z e

e e

β β β

− −

A A

A

But, we recognize that:

Γ 0 ej^2 βzL = Γ (^) ( z = zL)= ΓL

And so: ( ) 0 2 2 2

L j^ zL^ j j L

z z e e

e

β β β

− −

A A

A

Thus, we find that Γin is simply the value of function Γ( z)

evaluated at the line input of z = zL − A!

Γin = Γ (^) ( z = zL− A) = ΓL e −j^2 βA

Makes sense! After all, the input impedance is likewise simply

the line impedance evaluated at the line input of z = zL − A :

Z in = Z (^) ( z = zL − A)

It is apparent that from the above expression that the reflection coefficient at the input is simply related to ΓL by a

phase shift of 2 β A.

In other words, the magnitude of Γin is the same as the

magnitude of Γ (^) L!

( 2 )

(1)

j in L L L

Γ = Γ e θ^ Γ^ − β

A

If we think about this, it makes perfect sense!

Thus, we can conclude from conservation of energy that:

Γin = ΓL

Which of course is exactly the result we just found!

Finally, the phase shift associated with transforming the load Γ L down a transmission line can be attributed to the phase shift associated with the wave propagating a length A down the line, reflecting from load Γ L , and then propagating a length A back up the line:

To emphasize this wave interpretation, we recall that by definition, we can write Γin as:

( ) ( ) ( )

L in L L

V z z

z z

V z z

A

A

A

Therefore:

( ) ( ) ( )

L in L j j L L

V z z V z z

e β e β V z z

− + − − +

= A^ Γ A = −

A A

A

Z 0 , β Γ L

φ = βA

j j

i n e Le

Γ = −^ βA^ Γ −^ βA