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All about Shell Methods are here with sample problems
Typology: Lecture notes
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If we slice perpendicular to the y - axis, we get a washer. ▪ However, to compute the inner radius and the outer radius of the washer, we would have to solve the cubic equation y = 2 x 2
Fortunately, there is a method—the method of cylindrical shells—that is easier to use in such a case.
Its volume V is calculated by subtracting the volume V 1 of the inner cylinder from the volume of the outer cylinder V 2 .
Thus, we have: 2 1 2 2 2 1 2 2 2 1 2 1 2 1 2 1 2 1 ( ) ( )( ) 2 ( ) 2 V V V r h r h r r h r r r r h r r h r r
= − = − = − = + −
= −
The equation can be remembered as: V = [circumference] [height] [thickness]
V = 2 rh r
Now, let S be the solid obtained by rotating about the y - axis the region bounded by y = f ( x ) [where f ( x ) ≥ 0], y = 0 , x = a and x = b , where b > a ≥ 0.
The rectangle with base [ x i - 1 , x i ] and height is rotated about the y - axis. ▪ The result is a cylindrical shell with average radius , height , and thickness ∆ x. ( ) i f x ( ) i f x i
Thus, by Formula 1, its volume is calculated as follows: (2 )[ ( )]
V = x f x x
The approximation appears to become better as n →∞. However, from the definition of an integral, we know that: 1 lim 2 ( ) 2 ( ) n b i i n a i x f x x x f x dx → = = (^)
Thus, the following appears plausible. ▪ The volume of the solid obtained by rotating about the y - axis the region under the curve y = f ( x ) from a to b , is: where 0 ≤ a < b 2 ( ) b a V = xf x dx CYLINDRICAL SHELLS METHOD Formula 2
This type of reasoning will be helpful in other situations—such as when we rotate about lines other than the y - axis.
Find the volume of the solid obtained by rotating about the y - axis the region bounded by y = 2 x
and y = 0. 16π/ CYLINDRICAL SHELLS METHOD Example 1