daniel hart solutions, Ejercicios de Electrónica de Potencia

¡Descarga daniel hart solutions y más Ejercicios en PDF de Electrónica de Potencia solo en Docsity!

CHAPTER 1 SOLUTIONS

(1-1)

https://www.book4me.xyz/solution-manual-power-electronics-hart/

Access Full Complete Solution Manual Here

(1-2)

(1-3)

Time

0s 5us 10us 15us V(V2:-)

-20V

0V

20V

40V

(3.150u,-1.052)

(3.150u,-1.052)

96.46n,23.94)

(1-4)

T i m e

0 s 2 u s 4 u s 6 u s 8 u s 1 0 u s 1 2 u s 1 4 u s 1 6 u s V ( V 2 : - )

• 5 V

0 V

5 V

1 0 V

1 5 V

2 0 V

2 5 V

( 3. 8 3 3 3 u , - 1. 0 5 1 7 )

( 8 0 0. 0 0 0 n , 2 3. 9 2 4 )

   

  

6 10 14

0 0 6 10

T ms ms ms

ms ms

W p t dt dt dt dt J

or W PT ms mJ

   

---

2 - 6)

  

  

dc avg

avg

avg

P V I

a I A P W

b I A P W

---

2 - 7)

a)

   

          

 

2

0

25sin 377.

25sin 377 1.0sin 377 25sin 377 12.5 1 cos 754.

R

T

R

v t i t R t V

p t v t i t t t t t W

P p t dt W T

 (^)  

b)

 

      

        

  

 

3

0

10 10 377 1.0 cos 377 3.77 cos 377.

3.77 cos 377 1.0sin 377 sin 754 1.89sin 754. 2

1 0

L

L

T

L

di t v t L t t V dt

p t v t i t t t t t W

P p t dt T

   



c)

        

  0

12 1.0sin 377 12sin 377.

T

dc

p t v t i t t t W

P p t dt T

 (^)  

---

2 - 8) Resistor:

2

1/60 1/60 1/ 2

0 0 0 0

8 24sin 2 60.

8 24sin 2 60 2 6sin 2 60

16 96sin 2 60 144sin 2 60.

16 96sin 2 60 144sin 2 60 1/ 60

T

v t i t R t V

p t v t i t t t

t t W

P p t dt dt t dt t T

W

Inductor: PL 0.

dc source: Pdc  I avg Vdc   2  6  12 W.

---

2 - 9) a) With the heater on,

2 2 2

sin 120 2 12.5 2 sin 3000sin

max 3000.

m m m

m m

V I

P W I

p t V I t t t

p t W

b) P = 1500(5/12) = 625 W. c) W = PT = (625 W)(12 s) = 7500 J. (or 1500(5) = 7500 W.)

---

2 - 10)

0 3

t

L L

L

i t v t dt d t t ms L

i ms A





a)

W  Li   J

b) All stored energy is absorbed by R: WR = 0.648 J_._

c)

16.. 40 16..

R R

S R

W

P W

T ms

P P W

d) No change in power supplied by the source: 16.2 W.

---