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Statistics Exercises: Point and Interval Estimation (Chapters 4 & 5), Ejercicios de Estadística

exercises unit 4 and unit 5 point and interval estimation

Tipo: Ejercicios

2018/2019

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STATISTICS 2016-17
GEI
Chapters 4 & 5. Point and Interval Estimation - Exercises
1. A simple random sample of 50 items from a population with σ=6 resulted in a sample mean of
32.
a) Provide a 90% confidence interval for the population mean.
b) Provide a 95% confidence interval for the population mean.
c) Provide a 99% confidence interval for the population mean.
2. A 95% confidence interval for a population mean was reported to be 152 to 160. If σ=15, what
sample size was used in this study?
3. In an effort to estimate the mean amount spent per customer for dinner at a major Atlanta restau-
rant, data were collected for a sample of 49 customers. Assume a population standard deviation of
$5.
a) At 95% confidence, what is the margin of error?
b) If the sample mean is $24.80, what is the 95% confidence interval for the population mean?
4. The National Quality Research Center at the University of Michigan provides a quarterly measure
of consumer opinions about products and services (The Wall Street Journal, February 18, 2003). A
survey of 10 restaurants in the Fast Food/Pizza group showed a sample mean customer satisfac-
tion index of 71. Past data indicate that the population standard deviation of the index has been
relatively stable with σ=5.
a) What assumption should the researcher be willing to make if a margin of error is desired?
b) Using 95% confidence, what is the margin of error?
c) What is the margin of error if 99% confidence is desired?
5. Playbill magazine reported that the mean annual household income of its readers is $119,155 (Play-
bill, January 2006). Assume this estimate of the mean annual household income is based on a sam-
ple of 80 households, and based on past studies, the population standard deviation is known to be
σ=$ 30, 000.
a) Develop a 90% confidence interval estimate of the population mean.
b) Develop a 95% confidence interval estimate of the population mean.
c) Develop a 99% confidence interval estimate of the population mean.
d) Discuss what happens to the width of the confidence interval as the confidence level is in-
creased. Does this result seem reasonable? Explain.
6. Find the t value(s) for each of the following cases.
a) Upper tail area of 0.025 with 12 degrees of freedom
b) Lower tail area of 0.05 with 50 degrees of freedom
c) Upper tail area of 0.01 with 30 degrees of freedom
d) Where 90% of the area falls between these two t values with 25 degrees of freedom
e) Where 95% of the area falls between these two t values with 45 degrees of freedom
7. The following sample data are from a normal population: 10, 8, 12, 15, 13, 11, 6, 5.
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STATISTICS 2016-

GEI

Chapters 4 & 5. Point and Interval Estimation - Exercises

  1. A simple random sample of 50 items from a population with σ = 6 resulted in a sample mean of
    a) Provide a 90% confidence interval for the population mean. b) Provide a 95% confidence interval for the population mean. c) Provide a 99% confidence interval for the population mean. 
  2. A 95% confidence interval for a population mean was reported to be 152 to 160. If σ = 15, what sample size was used in this study?
  3. In an effort to estimate the mean amount spent per customer for dinner at a major Atlanta restau- rant, data were collected for a sample of 49 customers. Assume a population standard deviation of $5. a) At 95% confidence, what is the margin of error? b) If the sample mean is $24.80, what is the 95% confidence interval for the population mean?
  4. The National Quality Research Center at the University of Michigan provides a quarterly measure of consumer opinions about products and services (The Wall Street Journal, February 18, 2003). A survey of 10 restaurants in the Fast Food/Pizza group showed a sample mean customer satisfac- tion index of 71. Past data indicate that the population standard deviation of the index has been relatively stable with σ = 5. a) What assumption should the researcher be willing to make if a margin of error is desired? b) Using 95% confidence, what is the margin of error? c) What is the margin of error if 99% confidence is desired?
  5. Playbill magazine reported that the mean annual household income of its readers is $119,155 (Play- bill, January 2006). Assume this estimate of the mean annual household income is based on a sam- ple of 80 households, and based on past studies, the population standard deviation is known to be σ = $ 30, 000. a) Develop a 90% confidence interval estimate of the population mean. b) Develop a 95% confidence interval estimate of the population mean. c) Develop a 99% confidence interval estimate of the population mean. d) Discuss what happens to the width of the confidence interval as the confidence level is in- creased. Does this result seem reasonable? Explain.
  6. Find the t value(s) for each of the following cases.

a) Upper tail area of 0.025 with 12 degrees of freedom b) Lower tail area of 0.05 with 50 degrees of freedom c) Upper tail area of 0.01 with 30 degrees of freedom d) Where 90% of the area falls between these two t values with 25 degrees of freedom e) Where 95% of the area falls between these two t values with 45 degrees of freedom

  1. The following sample data are from a normal population: 10, 8, 12, 15, 13, 11, 6, 5.

a) What is the point estimate of the population mean? b) What is the point estimate of the population standard deviation? c) With 95% confidence, what is the margin of error for the estimation of the population mean? d) What is the 95% confidence interval for the population mean?

  1. A simple random sample with n = 54 provided a sample mean of 22.5 and a sample standard deviation of 4.4. a) Develop a 90% confidence interval for the population mean. b) Develop a 95% confidence interval for the population mean. c) Develop a 99% confidence interval for the population mean. d) What happens to the margin of error and the confidence interval as the confidence level is increased?
  2. Sales personnel for Skillings Distributors submit weekly reports listing the customer contacts made during the week. A sample of 65 weekly reports showed a sample mean of 19.5 customer contacts per week. The sample standard deviation was 5.2. Provide 90% and 95% confidence intervals for the population mean number of weekly customer contacts for the sales personnel.
  3. The mean number of hours of flying time for pilots at Continental Airlines is 49 hours per month (The Wall Street Journal, February 25, 2003). Assume that this mean was based on actual flying times for a sample of 100 Continental pilots and that the sample standard deviation was 8.5 hours. a) At 95% confidence, what is the margin of error? b) What is the 95% confidence interval estimate of the population mean flying time for the pilots? c) The mean number of hours of flying time for pilots at United Airlines is 36 hours per month. Use your results from part (b) to discuss differences between the flying times for the pilots at the two airlines. The Wall Street Journal reported United Airlines as having the highest labor cost among all airlines. Does the information in this exercise provide insight as to why United Airlines might expect higher labor costs?
  4. Thirty fast-food restaurants including Wendy’s, McDonald’s, and Burger King were visited during the summer of 2000 (The Cincinnati Enquirer, July 9, 2000). During each visit, the customer went to the drive-through and ordered a basic meal such as a “combo” meal or a sandwich, fries, and shake. The time between pulling up to the menu board and receiving the filled order was recorded. The times in minutes for the 30 visits are as follows: 0.9 1.0 1.2 2.2 1.9 3.6 2.8 5.2 1.8 2. 6.8 1.3 3.0 4.5 2.8 2.3 2.7 5.7 4.8 3. 2.6 3.3 5.0 4.0 7.2 9.1 2.8 3.6 7.3 9. a) Provide a point estimate of the population mean drive-through time at fast-food restaurants. b) At 95% confidence, what is the margin of error? c) What is the 95% confidence interval estimate of the population mean? d) Discuss skewness that may be present in this population. What suggestion would you make for a repeat of this study?
  5. Refer to the Scheer Industries example in Section 8.2. Use 6.84 days as a planning value for the population standard deviation. a) Assuming 95% confidence, what sample size would be required to obtain a margin of error of 1.5 days? b) If the precision statement was made with 90% confidence, what sample size would be required to obtain a margin of error of 2 days?
  1. According to Thomson Financial, through January 25, 2006, the majority of companies reporting profits had beaten estimates (BusinessWeek, February 6, 2006). A sample of 162 companies showed 104 beat estimates, 29 matched estimates, and 29 fell short. a) What is the point estimate of the proportion that fell short of estimates? b) Determine the margin of error and provide a 95% confidence interval for the proportion that beat estimates. c) How large a sample is needed if the desired margin of error is 0.05?
  2. The percentage of people not covered by health care insurance in 2003 was 15.6% (Statistical Ab- stract of the United States, 2006). A congressional committee has been charged with conducting a sample survey to obtain more current information. a) What sample size would you recommend if the committee’s goal is to estimate the current proportion of individuals without health care insurance with a margin of error of 0.03? Use a 95% confidence level. b) Repeat part (a) using a 99% confidence level.
  3. A dependent random sample from two normally distributed populations gives the following re- sults: n = 15 d = 25.4 sd = 2. a) Find the 95% confidence interval for the difference between the means of the two populations. b) Find the margin of error for a 95% confidence interval for the difference between the means of the two populations.
  4. A confidence interval for the difference between the means of two normally distributed popula- tions based on the following dependent samples is desired:

Before After 6 8 12 14 8 9 10 13 6 7 a) Find the margin of error for a 90% confidence level. b) Find the UCL and the LCL for a 90% confidence level. c) Find the width of a 95% confidence interval.

  1. Independent random sampling from two normally distributed populations gives the following results: nx = 64 X = 400 σ x = 20

ny = 36 Y = 360 σ y = 25

Find a 90% confidence interval estimate of the difference between the means of the two popula- tions.

  1. Assuming equal population variances, determine the number of degrees of freedom for each of the following: a) nx = 16 s^2 x = 30 ny = 9 s^2 y = 36 b) nx = 12 s^2 x = 30 ny = 14 s^2 y = 36 c) nx = 20 s^2 x = 16 ny = 8 s^2 y = 25
  1. Assuming equal population variances, compute the pooled sample variance s^2 p for part (a) through part (c) of Exercise 25.
  2. Assuming unequal population variances, determine the number of degrees of freedom for each of the following: a) nx = 16 s^2 x = 5 ny = 4 s^2 y = 36 b) nx = 9 s^2 x = 30 ny = 16 s^2 y = 4
  3. Calculate the 95% confidence interval for the difference in population proportions for each of the following: a) nx = 350 pˆx = 0. ny = 300 pˆy = 0. b) nx = 245 pˆx = 0. ny = 230 pˆy = 0.
  4. In a computer store chain, all PC tablets are sold with the option of a discount coupon for some application packages. Some of them are low-priced tablets, and some are the upmarket models. To learn the buying habits of customers and find out how to encourage application sales, the seller decides to select a random sample of 407 customers and to ask if they have also purchased the discount coupon, with the following results:

Upmarket Low-priced Tablets Tablets Sample size 229 178 Option coupon 47 25

It is possible to conclude at 10% of significance level that the people buying upmarket tablets are also more willing to purchase option coupons?

  1. Find the LCL and the UCL for the population variance for each of the following normal popula- tions: a) n = 21 α = 0.05 s^2 = 16 b) n = 16 α = 0.05 s^2 = 8 c) n = 28 α = 0.01 s^2 = 15
  2. A clinic offers a weight-loss program. A review of its records found the followwing amounts of weight loss, in pounds, for a random sample of 10 clients at the conclusion of the program:

18.2 25.9 6.3 11.8 15.4 20.3 16.8 18.5 12.3 17.

Find a 90% confidence interval for the population variance of weight loss for clients of this weight- loss program.

  1. A manufacturer is concerned about the variability of the levels of impurity contained in consign- ments of raw material from a supplier. A random sample of 15 consignments showed a standard deviation of 2.36 in the concentration of impurity levels. Assume normality. a) Find a 95% confidence interval for the population variance. b) Would a 99% confidence interval for this variance be wider or narrower than the found in part (a)?