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Examples of algebraic factorisation problems and their solutions. It shows how to factorize polynomials of different degrees and how to identify factors using algebraic methods. useful for students studying algebra and preparing for exams or assignments on factorisation.
Typology: Exercises
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Factorisation Factorize the following:
1. x^3 – 4 x^2 + 5 x – 2 Solution: 1 – 4 + 5 – 2 = 0 ( x 1) is a factor 1 1 4 5 2 0 1 3 2 1 3 2 0 x 2 - 3 x + 2 = ( x – 1) ( x – 2) The factors are ( x – 1) ( x – 2) ( x – 3) = ( x – 1) 2 ( x – 2) Factorize the following: 2. x **3
1 + 23 = 9 + 15 = 24 ( x 1) is a factor 1 1 9 23 15 0 1 8 15 1 8 15 0 x^2 + 8 x + 15 = ( x + 3) ( x + 5)
3. x^3 2 x^2 5 x + 6 Solution: 1 2 5 + 6 = 0 ( x 1) is a factor 1 5 2 + 6 ( x + 1) is not a factor 1 1 2 5 6 0 1 1 6 1 1 6 0 x 2 x 6 = ( x 3) ( x + 2)
Factorize the following:
4. 2 x^4 + 7 x^3 + x^2 – 7 x 3 Solution: 2 + 7 + 1 7 3 = 0 ( x 1) is a factor 2 + 1 3 = 7 7 = 0 ( x + 1) is also a factor 1 2 7 1 7 3 0 2 9 10 3 1 2 9 10 3 0 0 2 7 3 2 7 3 0 2 x 2
7. m 3 - 2 m 2 - 4 m + 8 Solution:
In that case try m = 2 2 1 2 4 8 0 2 0 8 1 0 4 0 m^2 4 = ( m + 2) ( m 2)
Factorize the following:
8. a^3 – 5 a^2 – 2 a + 24 Solution: 1 5 2 + 24 0 ( a 1) is not a factor 1 2 5 + 24 1 ( a + 1) is also not a factor Try a = 2 2 1 5 2 24 0 2 6 16 1 3 8 8 ( a 2) is not a factor Try a = 2 2 1 5 2 24 0 2 14 24 1 7 12 0 a^2 – 7 a + 12 = ( a 3) ( a 4) The factors are ( a + 2) ( a 3) ( a 4)
9. x 4 5 x + 4 Solution: x 4