Problems: from Onouye, Chapter 10.
Note: Problems marked with a * have been altered with respect to the problem stated in the text.
*
Partial answers to check with:
ASD: Areq’d ≥ 10.82 in2 with Fa = 10.72,
LRFD: Pu = 167 k,
φ
cPn = k
Partial answers to check with:
(CD = 1) F’c = 1021 psi, Pa = 72.4 k
*
Partial answers to check with:
kL/rx = 50.2, kL/ry = 45, fb = 19.6 ksi, interaction value: 1.09
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*Use A992 steel: Fy = 50 ksi, E = 30,000 ksi,
Also select the column using LRFD design method and the column chart. γD = 1.2, γL = 1.6 (LRFD)
*The column has been changed to a W14 x 109. Use A992 steel (Fy = 50 ksi,
Fb = 33 ksi, E = 30x103 ksi). And assume that the second-floor load is
applied at an eccentricity (e) of 4 inches in the direction of the framing.
(wood column analysis)
(beam-column analysis)
Fy = 50 ksi
46 k dead and 70 k live and a length
K = 1.
(steel column analysis – allowable stress )
W14 x 109
at e = 4 in.
Problem 10.3.5
(5%)
(30%)
(30%)
(35%)
